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3.
Development:
identification
of
terms
E.8121
For
each
of
the
questions
below,
de-termine
the
values
of
the
reals
a
and
b
realizing
the
proposed
identity:
a
2
x
2
−
5
x
−
3
=
(2
x
+
1)(
a
×
x
+
b
)
b
−
2
x
2
+
5
x
−
3
=
(
x
−
1)(
a
×
x
+
b
)
c
−
x
2
−
3
x
+
4
=
(
−
x
+
a
)(
−
1
+
b
×
x
)
d
4
x
2
+
12
x
+
9
=
2
x
+
a
2
E.8155
1
Consider
the
algebraic
expression
−
4
x
2
+4
x
+3
.
Its
fac-torized
form
is
one
of
the
four
expressions
below.
Which
is
it?
a
−
2
x
+
1
2
x
+
3
b
2
x
−
1
2
x
−
3
c
2
x
+
1
2
x
−
3
d
2
x
+
1
3
−
2
x
2
Determine
the
values
of
the
numbers
a
and
b
performing
the
following
factorization
:
6
x
2
−
7
x
−
5
=
2
x
+
1
a
×
x
+
b
E.8160
1
Consider
the
algebraic
expression
−
4
x
2
−
4
x
+3
.
Its
fac-torized
form
is
one
of
the
four
expressions
below.
Which
is
it?
a
−
2
x
+
1
2
x
+
3
b
2
x
−
1
2
x
−
3
c
2
x
+
1
2
x
−
3
d
2
x
+
1
3
−
2
x
2
Determine
the
values
of
the
numbers
a
and
b
performing
the
following
factorization
:
8
x
2
−
2
x
−
3
=
2
x
+
1
a
×
x
+
b
4.
Factorisation:
with
common
factor
E.9666
Factoring
expressions
:
a
(2
−
3
x
)(3
+
2
x
)
+
(3
x
+
2)(
−
6
x
−
9)
b
2
x
+
1
2
x
+
3
+
2
2
x
+
3
E.9389
Factoring
expressions
:
a
3
x
+
2
2
−
2
x
+
3
x
+
2
x
+
4
b
x
−
1
2
x
−
2
+
2
x
−
2
5
−
2
x
E.8125
Factoring
expressions
:
a
x
+
3
x
+
1
+
3
x
−
1
x
+
3
b
2
x
+
1
4
x
−
1
+
2
+
x
2
x
+
1
E.11606
Factoring
expressions
:
a
(
x
+
1)(
x
+
2)
+
(
x
+
1)(
x
−
2)
b
(2
+
x
)(3
−
x
)
+
(5
−
2
x
)(3
−
x
)
E.4381
Factor
the
following
expressions
:
a
(3
x
−
1)(2
x
+
1)
+
(5
−
x
)(2
x
+
1)
b
x
(2
−
x
)
+
(3
x
+
1)(2
−
x
)
E.9671
Factoring
expressions
:
a
(5
x
+
1)(3
−
2
x
)
−
(5
x
+
1)(2
x
+
1)
b
(
x
+
1)(1
−
x
)
−
(
x
+
1)(2
x
+
1)
E.9608
Factoring
expressions
:
a
4
−
3
x
x
+
5
−
4
−
3
x
x
+
2
b
2
x
+
5
x
+
2
−
2
x
+
5
3
x
−
2
E.9388
Factoring
expressions
:
a
(5
x
+
2)(3
x
+
4)
+
(
x
−
2)(3
x
+
4)
b
(3
−
x
)(2
x
+
4)
−
(3
−
x
)(3
x
−
4)
E.9412
Factoring
expressions
:
a
(
x
+
1)(
x
−
1)
−
(2
x
+
3)(
x
−
1)
b
(3
x
+
4)(2
x
−
1)
+
4(3
x
+
4)
E.11475
Factoring
expressions
:
a
4
−
3
x
x
+
5
+
4
−
3
x
b
2
x
+
5
x
+
2
−
2
x
+
5
E.434
Factoring
expressions
:
a
(
x
+
1)(2
x
−
1)
−
(2
x
−
1)
b
(
x
−
2)(
x
+
3)
−
(
x
−
2)
c
(
x
+
1)
×
x
+
2(
x
+
1)
E.9411
Factoring
expressions
:
a
(2
x
+
4)(3
−
3
x
)
+
(2
x
+
4)
b
(5
x
+
1)(7
−
3
x
)
−
(5
x
+
1)
E.11609
Factor
the
following
expressions
:
a
3(
x
+
1)(2
x
−
1)
+
(
x
+
1)(5
−
2
x
)
b
(
x
−
2)(
x
+
1)
−
2(
x
−
2)(2
x
+
3)
https://chingmath.fr
chapExoCorrec/8121
sacados/8121
chapExoCorrec/8155
sacados/8155
chapExoCorrec/8160
sacados/8160
chapExoCorrec/9666
sacados/9666
chapExoCorrec/9389
sacados/9389
chapExoCorrec/8125
sacados/8125
chapExoCorrec/11606
sacados/11606
chapExoCorrec/4381
sacados/4381
chapExoCorrec/9671
sacados/9671
chapExoCorrec/9608
sacados/9608
chapExoCorrec/9388
sacados/9388
chapExoCorrec/9412
sacados/9412
chapExoCorrec/11475
sacados/11475
chapExoCorrec/434
sacados/434
chapExoCorrec/9411
sacados/9411
chapExoCorrec/11609
sacados/11609
1612xx
E.11610
Factor
the
following
expressions
:
a
(2
x
−
1)
2
+
(2
x
−
1)(3
x
+
1)
b
(
x
+
3)
2
+
(
x
+
3)(2
x
−
4)
E.11612
Factoring
expressions
:
a
(3
x
−
2)(
x
+
4)
+
(3
x
−
2)
2
b
(
x
+
2)
2
−
(
x
+
2)
E.9609
Factoring
expressions
:
a
5
−
x
2
+
5
−
x
x
+
1
b
x
3
x
+
5)
+
3
x
+
5
2
E.9410
Factoring
expressions
:
a
(
x
+
1)(3
−
2
x
)
+
(3
−
2
x
)
2
b
x
+
5
3
−
2
x
−
3
−
2
x
2
E.8159
Factoring
expressions
:
a
(3
x
−
1)
2
+
(3
x
−
1)(5
x
+
4)
b
x
+
5
4
−
x
−
4
−
x
2
5.
Factoring
and
Product
Equations
E.2110
Solve
by
the
method
of
your
choice
the
following
equations
:
a
(3
x
+
1)(2
−
3
x
)
−
(5
x
−
1)(3
x
+
1)
=
0
b
2(
x
+
2)(3
−
x
)
=
(
x
+
2)(5
x
−
7)
6.
Product
and
1st
degree
equation
E.2096
1
Expand
each
of
the
following
expressions
:
a
x
(
x
−
3)
−
x
2
b
(6
x
+
1)
2
−
(12
x
+
2)(3
x
−
3)
2
Solve
the
following
equations
after
development
and
re-duction
:
a
x
(
x
−
3)
−
x
2
=
0
b
(6
x
+
1)
2
=
(12
x
+
2)(3
x
−
3)
E.453
1
Using
mental
arithmetic,
which
equations,
after
expan-sion
and
reduction,
have
no
terms
in
x
2
:
a
(
x
+
1)(
x
−
1)
−
(
x
+
1)(2
x
+
1)
=
0
b
x
2
−
8
=
(
x
+
3)(1
+
x
)
c
(3
x
−
2)
2
=
6
x
−
4
d
(2
x
+
1)(1
−
x
)
=
(3
x
−
3)(
x
+
2)
e
3
x
(4
x
−
1)
−
(2
x
−
5)(6
x
+
4)
=
0
2
Solve
the
equations
in
questions
b
and
e
.
E.9610
Solve
the
following
equations
using
the
method
of
your
choice
:
a
(2
x
+
3)(6
x
+
7)
+
(2
−
4
x
)(3
x
+
1)
=
3
x
−
7
b
2
x
+
1
x
−
2
+
3
x
−
5
2
x
+
1
=
0
E.8156
Solve
in
R
the
following
equations
:
a
2
x
+
1
4
−
x
+
4
x
−
1
2
x
+
1
=
0
b
−
(12
x
−
2)(2
−
3
x
)
=
36
x
2
−
12
x
+
1
E.443
Solve
the
following
equations
:
a
2
·
(6
x
+
4)(3
−
4
x
)
−
(8
x
−
6)
2
=
0
b
3
·
2
x
−
4
2
=
6
x
2
−
4
x
+
12
7.
Problems
and
Equations:
Products
E.4489
On
a
rectangular
former
wasteland
of
length
16
m
and
12
m
,
the
municipality
wishes
to
build
a
kindergarten
with
a
pathway
running
around
the
play
area:
The
playground
is
represented
below
by
the
hatched
area:
https://chingmath.fr
chapExoCorrec/11610
sacados/11610
chapExoCorrec/11612
sacados/11612
chapExoCorrec/9609
sacados/9609
chapExoCorrec/9410
sacados/9410
chapExoCorrec/8159
sacados/8159
chapExoCorrec/2110
sacados/2110
chapExoCorrec/2096
sacados/2096
chapExoCorrec/453
sacados/453
chapExoCorrec/9610
sacados/9610
chapExoCorrec/8156
sacados/8156
chapExoCorrec/443
sacados/443
chapExoCorrec/4489
sacados/4489
1612xx
9m5mx
ABCD4·x−1x
ABCDHSxx−16x23EFGIJKL
ABCDEFGx4m
1
Without
justification,
specify
the
possible
values
of
the
variable
x
for
this
problem.
2
a
Justify
that
the
playing
area
measures,
as
a
function
of
x
:
4
x
2
−
56
x
+
192
b
Justify
that
the
area
of
the
aisle
measures,
as
a
func-tion
of
x
:
56
x
−
4
x
2
3
a
Establish
the
following
equality:
8
x
2
−
112
x
+
192
=
8(
x
−
12)(
x
−
2)
b
Determine
the
possible
aisle
widths
so
that
the
play
area
has
the
same
area
as
the
aisle.
E.8154
Backing
onto
his
house,
Jean
has
a
rectangular-shaped
garden
with
dimensions
9
m
and
5
m
.
He
wants
to
build
a
driveway
on
three
of
the
sides
of
this
garden
with
the
same
width,
and
he
will
plant
lawn
on
the
rest
of
the
garden.
He
proposes
the
diagram
below
où
the
hatched
area
is
the
lawn
space
How
wide
must
the
driveway
be
for
the
whole
lawn
to
have
a
surface
area
of
10
m
2
?
Hint:
Use
one
of
the
factorized
forms
below
:
2
x
2
−
18
x
+28=
2
x
−
4
x
−
7
2
x
2
−
20
x
+32=
2
x
−
4
x
−
8
2
x
2
−
19
x
+35=
2
x
−
5
x
−
7
2
x
2
−
21
x
+40=
2
x
−
5
x
−
8
E.9754
1
Establish
the
following
factorization
:
x
+
5
4
x
−
1
−
10
x
−
8
=
(
x
−
1)(4
x
+
13)
2
Consider
the
rectangle
ABCD
whose
dimensions
are
a
function
of
a
real
number
x
and
are
given
in
centimeters
:
AB
=
4
x
−
1
;
AD
=
x
+
5
a
What
are
the
possible
values
of
parameter
x
.
b
Determine
the
value(s)
of
x
so
that
the
perimeter,
ex-pressed
in
cm
,
of
the
rectangle
ABCD
is
equal
to
the
area,
expressed
in
cm
2
,
of
the
rectangle
ABCD
.
E.6599
Consider
the
two
surfaces
ABCSD
and
EFLKJI
shown
below
où
x
is
a
real
number.
ABCD
is
a
square
with
side
x
and
SDC
is
a
triangle
whose
height
[
SH
]
has
measure
x
−
1
.
The
quadrilaterals
EFGI
and
GJKL
are
two
rectangles.
1
What
are
the
possible
values
of
the
variable
x
according
to
the
constraints
of
the
figures?
2
Express
the
area
of
these
two
surfaces
as
a
function
of
x
.
3
a
Establish
factorization
:
3
2
·
x
2
−
9
2
·
x
−
6
=
3
2
·
x
−
6
x
+
1
b
Determine
the
possible
value(s)
of
the
variable
x
to
obtain
equality
of
areas
of
these
two
surfaces.
E.4422
A
field
is
made
up
of
two
squares
and
a
right-angled
triangle.
This
field
is
shown
in
the
figure
below
:
1
Justify
the
following
factorization
:
x
2
+
2
x
−
168
=
(
x
+
14)(
x
−
12)
2
a
Justify
that
the
square
CEFG
has
area
(
x
2
+16)
m
2
.
b
Deduce
the
value
of
the
length
x
so
that
the
total
area
of
the
field
is
200
m
2
https://chingmath.fr
chapExoCorrec/8154
sacados/8154
9m5mx
chapExoCorrec/9754
sacados/9754
ABCD4·x−1x
chapExoCorrec/6599
sacados/6599
ABCDHSxx−16x23EFGIJKL
chapExoCorrec/4422
sacados/4422
ABCDEFGx4m
20m15mxx
ABCDMNPQx6cm
ABCDEF16cm6cmxx
E.1859
A
garden
is
rectangular,
with
a
length
of
20
m
and
a
width
of
15
m
.
Two
paths,
each
x
m
wide,
run
across
the
garden
;
the
rest
of
the
garden
will
be
planted
with
grass.
A
fence
must
be
installed
around
the
lawn
:
it
is
shown
as
a
dotted
line
in
the
diagram.
1
Indicate
the
possible
values
of
the
variable
x
.
2
a
Determine
the
total
area
of
the
two
paths
in
terms
of
x
.
b
Determine,
in
terms
of
x
,
the
area
of
the
lawn
in
this
garden.
3
a
Determine
the
values
of
the
real
numbers
a
and
b
that
satisfy
the
equation
:
2
·
x
2
−
70
·
x
+
300
=
(
x
−
30)(
a
·
x
+
b
)
b
The
architect
in
charge
of
designing
this
garden
de-cides
to
choose
the
width
of
the
path
so
that
the
areas
of
the
paths
and
the
lawn
are
equal.
4
The
garden
owner
decides
to
invest
5
600
euros
in
land-scaping
the
garden.
m
2
of
lawn
costs
7
e
;
m
2
of
the
wood
used
for
the
walk-way
costs
30
e
;
m
of
the
fence
costs
12
e
.
a
Establish
the
following
equation
:
23
x
2
−
757
x
+
2660
=
(
x
−
4)(23
x
−
665)
b
Use
this
to
determine
the
width
of
the
paths
that
form
the
owner’s
designs.
E.9700
Consider
the
square
ABCD
with
sides
6
cm
and
four
points
M
,
N
,
P
,
Q
such
that
:
AM
=
BN
=
CP
=
DQ
We
admit
that
MNPQ
is
a
square
and
note
:
x
=
BM
1
Justify
that
the
area
A
of
the
square
MNPQ
has
the
value
:
A
=
2
x
2
−
12
x
+
36
2
a
Andabir
factorization
:
2
x
2
−
12
x
+
27
2
=
1
2
2
x
−
9
2
x
−
3
b
Determine
the
value(s)
of
x
so
that
the
area
of
the
square
MNPQ
has
the
value
5
8
of
that
of
the
square
ABCD
.
E.8158
Consider
the
figure
below
consisting
of
a
rectangle
ABCD
of
dimension
16
cm
and
6
cm
and
the
two
points
E
and
F
belonging
respectively
to
the
segments
[
BC
]
and
[
CD
]
such
that
:
CE
=
DF
=
x
where
x
is
a
real
number.
Consider
the
hatched
area
of
the
figure
defined
by
the
triangle
AEF
.
1
Give
the
set
of
possible
values
of
the
number
x
.
2
a
Justify
that
the
ˇ
blanche
ı
part
of
this
figure
has
area
A
whose
expression
as
a
function
of
x
is
:
A
=
−
1
2
x
2
+
3
x
+
48
b
Determine
the
area
A
of
the
part
ˇ
hachurée
ı.
3
Determine
the
value(s)
of
x
to
obtain
the
two
domains
ˇ
blancs
ı
and
ˇ
hachurés
ı
of
the
same
area.
https://chingmath.fr
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sacados/1859
20m15mxx
chapExoCorrec/9700
sacados/9700
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chapExoCorrec/8158
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ABCDEF16cm6cmxx
ABCDEF18cm10cmxx
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10mxABCDMNOP
IJOCfCg
E.8157
Consider
the
figure
below
consisting
of
a
rectangle
ABCD
of
dimension
18
cm
and
10
cm
and
the
two
points
E
and
F
belonging
respectively
to
the
segments
[
BC
]
and
[
CD
]
such
that
:
CE
=
DF
=
x
where
x
is
a
real
number.
Consider
the
hatched
area
of
the
figure
defined
by
the
triangle
AEF
.
1
Give
the
set
of
possible
values
of
the
number
x
.
2
a
Justify
that
the
ˇ
blanche
ı
part
of
this
figure
has
area
A
whose
expression
as
a
function
of
x
is
:
A
=
−
1
2
x
2
+
5
x
+
90
b
Determine
the
area
A
of
the
ˇ
hachurée
ı
part.
Hint:
remember
to
factor
by
x
.
3
Determine
the
value(s)
of
x
to
obtain
the
two
domains
ˇ
blancs
ı
and
ˇ
hachurés
ı
of
the
same
area.
E.4527
A
workshop
has
a
block
of
marble
with
a
parallelepiped
shape
and
dimensions
32
cm
long,
10
cm
deep
and
6
cm
high.
We
wish
to
recover
the
ˇ
heart
ı
of
this
block.
To
do
this,
we
plane
each
side
of
this
right
block
by
a
length
of
x
cm
:
1
Give
the
possible
values
taken
by
the
variable
x
.
2
a
Determine
the
volume
of
the
ˇ
heart
ı
of
this
marble
block.
b
Deduce
the
volume
of
the
planed
part.
3
a
Expand
:
−
16
·
(
x
−
1)(
x
−
8)(
x
−
15)
b
For
what
value
of
x
,
the
volume
of
the
planed
part
is
equal
to
the
volume
of
the
ˇ
coeur
ı
of
this
part.
E.8126
Consider
a
park
represented
by
the
square
ABCD
opposite.
This
park
consists
of
a
wooded
area
(in
grey)
and
a
driveway
(in
white)
.
The
hexagon
AMNCOP
repre-senting
the
driveway
has
its
sides
[
OP
]
and
[
MN
]
parallel
to
the
di-agonal
[
AC
]
of
the
square
ABCD
.
We
note
x
the
measure
of
segment
[
CN
]
and
we
have
equality
of
lengths
:
CN
=
CO
Determine
the
value(s)
of
x
so
that
the
wooded
area
measures
one-third
of
the
driveway.
Hint:
You
can
use
one
of
the
following
factorizations
:
x
2
−
20
x
+75=
x
−
15
x
−
5
x
2
+20
x
+75=
x
+5
x
+15
x
2
+25
x
+150=
x
+10
x
+15
x
2
−
25
x
+150=
x
−
10
x
−
15
8.
Functions
and
product
equations
E.8162
Consider
the
two
second-degree
func-tions
f
and
g
defined
on
R
by
the
algebraic
expressions
:
f
(
x
)
=
3
x
2
+
3
x
−
4
;
g
(
x
)
=
x
+
1
In
the
reference
frame
O
;
I
;
J
orthogonal
below,
consider
the
representative
curves
C
f
and
C
g
given
below
:
1
Establish
the
factorization
:
f
(
x
)
−
g
(
x
)
=
x
−
1
3
x
+
5
https://chingmath.fr
chapExoCorrec/8157
sacados/8157
ABCDEF18cm10cmxx
chapExoCorrec/4527
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chapExoCorrec/8126
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IJOCfCg
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2
Deduce
the
coordinates
of
the
intersection
points
of
the
curves
C
f
and
C
g
.
E.8161
Consider
the
two
second-degree
func-tions
f
and
g
defined
on
R
by
the
algebraic
expressions
:
f
(
x
)
=
3
x
2
+
2
x
−
1
;
g
(
x
)
=
x
+
1
In
the
reference
frame
O
;
I
;
J
orthogonal
below,
consider
the
representative
curves
C
f
and
C
g
given
below
:
1
Establish
the
factorization
:
f
(
x
)
−
g
(
x
)
=
x
+
1
3
x
−
2
2
Deduce
the
coordinates
of
the
intersection
points
of
the
curves
C
f
and
C
g
.
E.8153
Consider
the
two
second-degree
func-tions
f
and
g
defined
on
R
by
the
algebraic
expressions
:
f
(
x
)
=
3
x
2
+
2
;
g
(
x
)
=
x
2
+
x
+
5
Note
respectively
C
f
and
C
the
representative
curves
of
the
functions
f
and
g
in
any
reference
frame.
1
Using
the
calculator,
draw
the
curves
C
f
and
C
g
and
conjecture
the
coordinates
of
their
points
of
intersection.
2
a
Establish
factorization
:
f
(
x
)
−
g
(
x
)
=
2
x
−
3
x
+
1
b
Determine
the
coordinates
of
the
iintersection
points
of
the
curves
C
f
and
C
g
.
E.9701
Consider
the
two
functions
f
and
g
defined
on
R
by:
f
(
x
)
=
(
−
x
−
2)(
x
+
3)
;
g
(
x
)
=
3
x
2
+
3
x
−
3
In
the
plane
provided
with
a
reference
frame
O
;
I
;
J
,
we
note
respectively
C
f
and
C
g
the
representative
curves
of
the
functions
f
and
g
:
1
Establish
factorization
:
f
(
x
)
−
g
(
x
)
=
−
2
x
−
1
2
x
+
3
2
Deduce
the
abscissas
of
the
points
of
intersection
of
these
two
curves.
E.6600
Consider
the
two
functions
f
and
g
defined
on
R
by
the
relations
:
f
(
x
)
=
x
2
+
2
·
x
+
1
;
g
(
x
)
=
−
x
+
1
x
−
2
The
curves
C
f
and
C
g
representative
respectively
of
the
func-tions
f
and
g
are
given
in
the
orthonormal
frame
O
;
I
;
J
.
Determine
the
coordinates
of
the
points
of
intersection
of
these
two
curves.
Any
trace
of
research,
even
if
incomplete,
will
be
taken
into
account
in
the
assessment.
E.4472
Consider
the
two
functions
f
and
g
whose
images
of
a
number
x
are
given
by
the
relation:
f
(
x
)
=
−
1
4
x
2
+
x
+
3
;
g
(
x
)
=
1
2
x
+
1
The
representation
C
f
and
C
g
of
the
functions
f
and
g
are
given
below
in
the
frame
O
;
I
;
J
:
1
a
Determine
the
values
of
the
reals
a
and
b
verifying
the
equality:
−
x
2
+
4
x
+
12
=
x
−
6
a
·
x
+
b
b
Deduce
the
solutions
of
the
equation
:
f
(
x
)
=
0
2
a
Establish
the
following
equality:
−
x
2
4
+
x
2
+
2
=
−
(
x
−
4)(
x
+
2)
4
b
Solve
the
equation
:
f
(
x
)
=
g
(
x
)
c
Deduce
the
coordinates
of
the
intersection
points
of
the
curves
C
f
and
C
g
.
https://chingmath.fr
chapExoCorrec/8161
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-4-3-2-1234I-8-6-4-2246JOCf
E.4488
Consider
the
two
functions
f
and
g
whose
image
of
a
number
x
is
given
by
the
relation:
f
(
x
)
=
1
4
x
2
+
1
4
x
−
3
2
;
g
(
x
)
=
−
1
4
x
+
9
4
We
give
the
representations
C
f
and
C
g
respectively
of
f
and
g
in
the
frame
O
;
I
;
J
below
:
1
Graphically,
give
the
antecedents
of
0
by
the
function
f
.
The
following
questions
must
be
dealt
with
algebraically:
2
Determine
the
antecedents
of
the
number
0
by
the
func-tion
g
.
3
a
Determine
the
value
of
the
numbers
a
and
b
verify-ing
the
following
factorization
:
x
2
+
2
x
−
15
=
(
x
−
3)(
a
·
x
+
b
)
b
Deduce
the
solutions
of
the
equation
:
f
(
x
)=
g
(
x
)
c
Give
the
coordinates
of
the
intersection
points
of
the
curves
C
f
and
C
g
.
E.4444
In
the
(
O
;
I
;
J
)
orthogonal
repre-sented
below,
the
curve
C
f
is
the
graphical
representation
of
a
function
f
defined
on
R
:
1
a
Determine
the
image
of
the
number
−
3
by
the
func-tion
f
.
Justify
your
answer.
b
Solve,
graphically,
the
equation
f
(
x
)=1
.
Justify
your
answer.
2
The
image
of
a
number
x
by
the
function
f
is
given
by
the
relation:
f
(
x
)
=
x
3
+
2
x
2
−
5
x
−
5
a
Justify,
by
calculation,
the
value
of
the
image
of
the
number
−
3
.
b
Establish
the
following
equality:
x
3
+
2
x
2
−
5
x
−
5
=
(
x
+
3)(
x
−
2)(
x
+
1)
+
1
c
Solve,
by
calculation,
the
equation
f
(
x
)=1
.
9.
Factorization:
recognizing
common
factors
/
multiples
of
each
other
E.2095
1
Find
an
algebraic
relationship
between
the
two
expres-sions
:
3
x
−
2
;
6
x
−
4
2
Deduce
a
factorization
of
the
following
algebraic
expres-sion
:
A
=
(
x
+
2)(3
x
−
2)
+
(5
x
−
2)(6
x
−
4)
E.11604
Factoring
expressions
:
a
(2
x
+
1)(3
x
−
1)
−
(
x
+
3)(6
x
−
2)
b
(2
x
−
4)(3
x
+
1)
−
(6
x
+
2)(4
x
+
1)
E.450
Factor
the
expressions
:
a
(7
x
−
1)(5
x
−
6)
−
(10
x
−
12)
b
(7
x
−
1)(9
x
−
3)
−
(3
x
−
1)
E.4446
Factor
the
following
expressions
:
a
(3
x
+
2)(
x
+
4)
+
(6
x
+
4)(4
x
+
1)
b
(3
x
+
2)(2
x
−
1)
+
(4
x
−
2)(3
−
5
x
)
E.11599
Factor
the
following
expressions
:
a
(
x
+
1)(3
x
+
2)
−
(2
x
−
2)(6
x
+
4)
b
(5
x
+
2)(6
x
+
3)
−
(3
−
2
x
)(2
x
+
1)
E.2109
Factoring
expressions
:
a
(
x
−
1)(2
x
+
1)
−
(2
x
−
2)(5
−
2
x
)
b
(2
−
x
)(3
x
−
4)
+
2
−
3
2
x
(2
x
+
3)
E.11603
Factoring
expressions
:
a
(6
x
−
4)(5
x
+
1)
−
(3
x
−
2)
2
b
6
x
−
3
2
x
+
1
−
2
2
x
−
1
2
E.9657
Factor
the
following
expressions
:
a
(6
x
−
4)(5
x
+
1)
−
(3
x
−
2)
2
b
(
x
−
5)
2
+
(
x
+
3)(2
x
−
10)
https://chingmath.fr
chapExoCorrec/4488
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chapExoCorrec/4444
sacados/4444
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chapExoCorrec/2095
sacados/2095
chapExoCorrec/11604
sacados/11604
chapExoCorrec/450
sacados/450
chapExoCorrec/4446
sacados/4446
chapExoCorrec/11599
sacados/11599
chapExoCorrec/2109
sacados/2109
chapExoCorrec/11603
sacados/11603
chapExoCorrec/9657
sacados/9657
E.11598
1
Find
an
algebraic
relationship
between
:
3
−
x
;
x
−
3
2
Deduce
a
factorization
of
the
following
algebraic
expres-sion
:
B
=
(2
x
+
1)(3
−
x
)
−
(2
−
2
x
)(
x
−
3)
E.11597
1
Find
an
algebraic
relationship
between
:
2
x
−
1
;
2
−
4
x
?
2
Deduce
a
factorization
of
the
following
algebraic
expres-sion
:
C
=
(5
−
2
x
)(2
x
−
1)
+
(2
−
4
x
)
E.4485
Factor
the
following
expressions
:
a
(2
x
−
1)(5
−
3
x
)
+
(5
x
−
2)(3
x
−
5)
b
(3
x
−
1)(2
−
x
)
−
2(1
−
3
x
)(4
x
−
3)
E.11600
Factor
the
following
expressions
:
a
(7
x
−
2)(5
−
x
)
+
(4
x
−
1)(
x
−
5)
b
(2
x
−
3)(4
−
7
x
)
−
(3
x
−
2)(7
x
−
4)
E.824
Factoring
expressions
:
a
3(
x
−
2)
+
(
x
+
2)(2
−
x
)
b
(2
x
−
3)(5
x
+
4)
−
(2
x
−
3)(3
−
2
x
)
E.9667
Factoring
expressions
:
a
3(2
x
−
2)
+
(
x
+
1)(1
−
x
)
b
(2
−
6
x
)
+
(
x
+
1)(3
x
−
1)
E.9665
Factoring
expressions
:
a
(
x
−
1)(3
x
+
2)
+
(2
x
+
3)(1
−
x
)
b
(2
−
x
)(2
+
x
)
−
5(2
−
x
)
+
(
−
x
+
1)(
x
−
2)
E.6597
Factor
the
following
expressions
:
a
(25
x
−
10)(
x
+
1)
+
(2
−
5
x
)(1
−
x
)
b
(
x
+
3)(2
x
−
1)
+
(2
−
4
x
)(
x
−
1)
E.9611
Factor
the
following
expressions
:
a
x
(
x
−
5)
+
(10
−
2
x
)(3
x
−
1)
b
(12
x
−
3)(7
+
2
x
)
−
(5
−
2
x
)(1
−
4
x
)
E.9678
Factoring
expressions
:
a
3
x
+
2
x
−
2
+
4
−
2
x
2
x
+
3
b
(3
−
x
)(7
x
+
1)
−
2(2
x
+
2)(3
x
−
9)
E.11601
Factoring
expressions
:
a
(2
x
−
1)(3
x
+
2)
+
(2
x
+
3)(2
−
4
x
)
b
(3
x
+
1)(2
−
2
x
)
−
(5
−
4
x
)(
x
−
1)
E.5902
Factor
the
following
expressions
:
a
(2
x
+
3)(1
−
x
)
+
(4
x
+
6)
2
b
(3
−
9
x
)
2
+
3(3
x
−
1)
E.11602
Factoring
expressions
:
a
x
(
x
−
2)
+
(3
x
−
6)
2
b
(2
+
x
)(5
−
x
)
+
(2
x
+
4)
2
E.2850
Factoring
expressions
:
a
x
+
1
5
−
2
x
3
x
−
4
+
3
2
x
−
5
6
x
−
8
10.
Factorization:
recognizing
common
factors
E.436
Factorize
the
expressions,
if
possible
:
a
3(4
+
2
x
)
−
(3
+
x
)(10
+
5
x
)
b
(6
x
−
9)(
x
+
1)
−
(4
x
−
6)
E.2099
Factor
the
following
expressions
:
a
(3
x
−
3)(5
x
+
2)
−
(2
x
−
2)(3
x
−
1)
b
3(4
+
2
x
)
−
(3
+
x
)(10
+
5
x
)
E.10189
Factor
the
following
expressions
:
a
(2
x
−
4)(
x
+
4)
+
(6
−
3
x
)(4
x
+
2)
b
2(4
x
+
6)(5
−
2
x
)
+
(
x
−
3)(6
x
+
9)
E.11611
Factor
the
following
expressions
:
a
(6
x
+
2)(2
x
+
3)
+
(9
x
+
3)
2
b
(5
x
+
1)(2
x
−
4)
+
(3
x
−
6)
2
E.11605
Factoring
expressions
:
a
(6
x
+
2)(2
x
+
3)
+
(9
x
+
3)
2
b
https://chingmath.fr
chapExoCorrec/11598
sacados/11598
chapExoCorrec/11597
sacados/11597
chapExoCorrec/4485
sacados/4485
chapExoCorrec/11600
sacados/11600
chapExoCorrec/824
sacados/824
chapExoCorrec/9667
sacados/9667
chapExoCorrec/9665
sacados/9665
chapExoCorrec/6597
sacados/6597
chapExoCorrec/9611
sacados/9611
chapExoCorrec/9678
sacados/9678
chapExoCorrec/11601
sacados/11601
chapExoCorrec/5902
sacados/5902
chapExoCorrec/11602
sacados/11602
chapExoCorrec/2850
sacados/2850
chapExoCorrec/436
sacados/436
chapExoCorrec/2099
sacados/2099
chapExoCorrec/10189
sacados/10189
chapExoCorrec/11611
sacados/11611
chapExoCorrec/11605
sacados/11605
11.
Product
equation:
recognition
of
the
common
factor
E.2823
1
a
Factor
the
following
algebraic
expression
:
(3
x
+
2)(2
x
−
1)
+
(4
x
−
2)(3
−
5
x
)
b
Solve
the
following
equation
:
(3
x
+
2)(2
x
−
1)
+
(4
x
−
2)(3
−
5
x
)
=
0
2
a
Factor
the
following
expression
:
(2
x
+
1)(3
−
2
x
)
−
(3
x
−
2)(2
x
−
3)
b
Solve
the
following
equation
:
(2
x
+
1)(3
−
2
x
)
=
(3
x
−
2)(2
x
−
3)
E.4388
1
a
Show
that
the
following
two
equations
are
equiva-lent
:
x
2
=
x
;
x
(
x
−
1)
=
0
b
Deduce
the
solutions
of
the
equation
:
x
2
=
x
2
Solve
the
following
equations
:
a
(
x
−
2)(3
−
2
x
)
=
0
b
(5
x
−
1)(2
−
x
)
+
(2
x
−
4)(3
−
2
x
)
=
0
E.4560
Solve
the
following
equations
:
a
(
x
+
2)(3
−
x
)
+
2(
x
−
3)(2
x
−
5)
=
0
b
(6
−
2
x
)(3
x
+
2)
=
(3
x
−
9)(
x
+
2)
E.2851
Reducing
to
a
product
equation,
solve
the
following
equations
:
a
3
x
−
1
2
x
+
2
+
3
5
−
2
x
x
+
1
=
0
b
3
5
x
+
1
2
−
3
x
+
6
x
−
4
x
−
1
=
0
c
4
x
+
6
1
−
2
x
=
5
2
x
+
3
2
E.2875
1
Factor
the
following
expressions
:
a
(5
x
+
1)(6
+
4
x
)
+
(3
x
+
9)(2
x
+
3)
b
(3
−
2
x
)(4
x
+
1)
+
4
x
2
−
12
x
+
9
2
Solve
the
following
equations
:
a
(4
−
2
x
)(3
x
+
2)
=
3(2
x
+
3)(
x
−
2)
b
(4
x
+
3)(2
−
3
x
)
+
(2
−
6
x
)(3
x
−
2)
=
0
E.4486
Solve
the
following
equations
:
a
(5
x
−
1)(3
x
−
2)
+
(6
x
−
4)(
x
−
1)
=
0
b
(3
−
2
x
)(2
x
+
4)
=
(2
x
−
3)(3
−
9
x
)
c
(6
x
−
3)(1
−
2
x
)
+
(3
−
4
x
)(2
−
3
x
)
=
0
12.
Rational
expression
and
equation
E.7002
Establish
the
following
identities:
a
3
x
+
1
x
+
1
+
3
x
−
1
=
3
x
2
+
x
+
2
(
x
+
1)(
x
−
1)
b
2
−
x
3
x
+
1
+
x
+
1
2
=
3
x
2
+
2
x
+
5
2
3
x
+
1
E.5904
Solve
the
following
equations
:
a
2
x
+
1
−
3
2
x
−
1
=
0
b
2
x
−
1
4
x
+
1
−
3
x
6
x
−
1
=
0
E.9753
Solve
the
equation
:
4
x
2
x
+
1
−
2
x
−
3
x
+
1
=
0
E.9698
Solve
the
following
equations
:
a
2
x
4
x
+
1
=
x
+
1
2
x
−
1
b
1
−
x
2
−
x
=
x
+
3
x
−
1
E.9658
Solve
the
equation
:
3
5
x
+
3
−
2
−
5
x
x
+
2
=
0
E.2750
Solve
equation
:
1
2
x
2
+
5
x
+
3
−
1
2
x
2
+
3
x
+
1
=
0
E.2734
Solve
the
following
equation
:
(
E
)
:
1
3
x
2
−
8
x
+
4
+
2
3
x
2
+
10
x
−
8
=
0
13.
Algebraic
expression:
antecedents
E.6498
1
Consider
the
following
three
functions
:
f
(
x
)=
x
+1
1
−
x
2
;
g
(
x
)=
1+
x
2
x
−
2
;
h
(
x
)=3
−
2
·
x
+1
Determine
the
image
of
the
number
1
by
each
of
these
three
functions.
2
Consider
the
following
three
functions
:
j
(
x
)
=
1
1
−
x
;
k
(
x
)
=
x
2
−
x
+
1
x
+
1
;
‘
(
x
)
=
3
·
x
−
1
2
−
3
·
x
Determine
the
antecedents
of
the
number
−
1
by
each
of
these
three
functions.
https://chingmath.fr
chapExoCorrec/2823
sacados/2823
chapExoCorrec/4388
sacados/4388
chapExoCorrec/4560
sacados/4560
chapExoCorrec/2851
sacados/2851
chapExoCorrec/2875
sacados/2875
chapExoCorrec/4486
sacados/4486
chapExoCorrec/7002
sacados/7002
chapExoCorrec/5904
sacados/5904
chapExoCorrec/9753
sacados/9753
chapExoCorrec/9698
sacados/9698
chapExoCorrec/9658
sacados/9658
chapExoCorrec/2750
sacados/2750
chapExoCorrec/2734
sacados/2734
chapExoCorrec/6498
sacados/6498
E.8026
Consider
the
three
functions
f
,
g
and
h
defining
the
image
of
the
number
x
as
follows
:
f
(
x
)
=
3
x
−
2
;
g
(
x
)
=
x
2
;
h
(
x
)
=
2
3
x
−
1
1
Solve
the
following
three
equations
:
(
E
)
:
3
x
−
2
=
1
2
;
(
F
)
:
x
2
=
2
;
(
G
)
:
2
3
x
−
1
=
−
1
2
Using
the
previous
question,
determine
the
sets
below
:
The
set
of
antecedents
of
1
2
by
f
;
The
set
of
antecedents
of
2
by
g
;
The
set
of
antecedents
of
−
1
by
h
.
14.
Algebraic
expression:
antecedents
and
definition
set
E.8022
1
Consider
the
function
f
square
whose
algebraic
expres-sion
is
:
f
(
x
)
=
x
2
Does
the
function
f
admit
one
or
more
antecedents
of
the
number
−
4
?
Justify
your
answer.
2
Consider
the
function
g
whose
expression
is
given
by
the
relation:
g
(
x
)=
1
x
2
+1
What
can
be
said
about
the
set
of
antecedents
of
the
number
2
by
the
function
g
?
3
Consider
the
function
h
defined
by
the
expression
:
h
(
x
)
=
3
·
x
+
1
x
Determine
the
set
of
antecedents
of
the
number
3
by
the
function
h
.
15.
Algebraic
expression:
image
and
antecedents
E.6562
1
Let
f
be
a
function
realizing
the
relation:
f
(2)=
5
a
Translate
this
relationship
into
a
sentence
using
the
word
ˇ
image
ı.
b
Translate
this
relationship
into
a
sentence
using
the
word
ˇ
antecedent
ı.
2
Let
g
be
a
function
such
that
the
equation
g
(
x
)=1
ad-mits
for
solution
the
numbers
−
1
and
2
.
Translate
this
property
into
a
sentence
using
the
word
ˇ
antecedent
ı.
E.362
Consider
the
following
two
functions
:
f
:
x
↦−→
1
1
+
x
;
g
:
x
↦−→
3
−
2
x
1
Determine
the
image
of
the
number
1
for
each
of
these
functions.
2
Determine
the
set
of
antecedents
of
the
number
4
for
each
of
these
two
functions.
E.367
We
define
six
functions
and,
for
each
of
them,
two
numerical
values
:
a
f
(
x
)
=
3
x
+
5
;
a
=
2
;
b
=
−
1
b
g
(
x
)
=
−
2
x
−
2
;
a
=
1
;
b
=
8
c
h
(
x
)
=
x
2
;
a
=
5
;
b
=
9
d
j
(
x
)
=
3
x
2
;
a
=
−
3
;
b
=
−
1
e
k
(
x
)
=
3
x
+
1
x
+
1
;
a
=
2
;
b
=
1
f
‘
(
x
)
=
2
x
−
2
x
+
ı
;
a
=
1
;
b
=
2
1
For
each
question,
determine
the
image
of
the
number
a
by
the
associated
function.
2
For
each
question,
determine
the
set
of
antecedents
of
the
number
b
by
the
associated
function.
E.4673
1
Below
are
three
functions
that
have
been
entered
on
a
calculator:
a
b
c
Rewrite
these
three
functions
on
your
copy
using
the
usual
presentation
of
mathematical
expressions.
2
For
each
of
the
functions
below,
write
the
characters
you
would
enter
in
a
calculator
to
insert
:
a
f
:
x
↦→
1
+
3
+
x
x
2
−
3
x
b
g
:
x
↦→
(1
−
2
x
)
×
3
x
−
1)
c
h
:
x
↦→
√
x
+
1
x
+
1
E.6497
1
Consider
the
following
three
functions
:
f
(
x
)
=
x
2
−
x
+
2
;
g
(
x
)
=
2
·
x
−
1
3
−
x
;
h
(
x
)
=
20
−
3
·
x
2
Determine
the
image
of
the
number
2
by
each
of
these
three
functions.
2
Consider
the
following
three
functions
:
j
(
x
)
=
4
−
2
·
x
;
k
(
x
)
=
3
·
x
2
;
‘
(
x
)
=
2
−
x
2
·
x
+
1
Determine
the
antecedents
of
the
number
3
by
each
of
these
three
functions.
https://chingmath.fr
chapExoCorrec/8026
sacados/8026
chapExoCorrec/8022
sacados/8022
chapExoCorrec/6562
sacados/6562
chapExoCorrec/362
sacados/362
chapExoCorrec/367
sacados/367
chapExoCorrec/4673
sacados/4673
chapExoCorrec/6497
sacados/6497
-5-4-3-2-1012345-3-2-1123ijCfCf
x-5-4-3-2-1012345678y-2-11234Cg
16.
Study
of
functions
E.4451
1
In
the
reference
frame
below,
is
represented
the
represen-tative
curve
of
the
function
f
:
a
Give
the
definition
set
of
the
function
f
.
b
Give,
if
possible,
the
images
of
the
following
numbers
by
the
function
f
:
1
;
0
;
−
4.5
c
Give
the
set
of
antecedents
for
each
of
the
following
numbers
:
2
;
−
1
;
0.75
2
Consider
the
function
g
whose
image
of
a
number
x
is
defined
by:
g
(
x
)
=
2
x
2
+
3
x
−
2
x
2
+
1
a
Justify
that
the
function
g
is
defined
on
R
.
b
Determine
the
image
of
the
number
−
2
by
the
function
g
.
c
Determine
the
antecedent
of
the
number
2
by
the
func-tion
g
.
E.373
Consider
the
two
functions
f
and
g
:
the
function
f
defined
by:
f
:
x
↦−→
x
2
−
6
x
+2
.
The
function
g
is
defined
by
the
graph
shown
below
:
For
each
of
the
following
questions,
only
one
of
the
four
pos-
sible
answers
is
correct;
select
the
correct
answer.
1
The
image
of
1
under
the
function
f
is
:
a
1
b
0
c
−
1
d
−
3
2
The
domain
of
−
7
under
f
is
:
a
3
b
2
c
−
2
;
3
d
1
;
2
3
The
domain
of
the
function
g
is
:
a
−
1;
−
3
b
−
1;3
c
−
4;7
d
−
4;7
4
The
image
of
0
under
the
function
g
is
:
a
1
b
−
1
c
7
d
0
5
UWhich
points
do
not
belong
to
C
g
?
a
(
−
3;
−
1)
b
(
−
4;
1)
c
(6;
2)
d
(
−
2;
−
0
;
5)
E.2731
1
Consider
a
function
f
.
We
denote
(
C
)
the
representative
curve
of
the
function
f
.
Consider
the
following
properties
of
the
curve
(
C
)
:
a
The
coordinate
point
(0
;
3)
belongs
to
(
C
)
.
b
The
only
point
of
(
C
)
with
ordinate
5
has
abscissa
−
1
.
c
No
point
of
(
C
)
has
abscissa
−
2
.
d
There
is
no
(
C
)
point
of
ordinate
6
.
Translate
each
of
these
sentences
into
a
sentence
describ-ing
a
property
of
the
function
f
using,
each
time,
at
least
one
of
the
following
words
image
,
antecedent
,
definitey
.
2
Let
g
be
the
defined
function
whose
image
of
a
number
x
is
defined
by:
g
(
x
)
=
2
x
2
−
3
Let
(
C
g
)
be
the
representative
curve
of
the
function
g
.
a
A
is
a
point
of
abscissa
2
of
(
C
g
)
.
What
is
the
ordinate
of
point
A
?
b
B
is
a
point
of
(
C
g
)
with
ordinate
−
3
.
Give
the
ab-scissa
of
the
point
B
.
c
How
many
points
on
the
curve
(
C
g
)
have
ordinates
−
1
?
Specify,
if
they
exist,
the
coordinates
of
these
points.
d
How
many
points
on
the
curve
(
C
g
)
have
ordinates
−
4
?
Specify,
if
they
exist,
the
coordinates
of
these
points.
3
Consider
the
function
h
defined
by
the
relation:
h
(
x
)
=
2
x
2
+
3
Let
(
C
h
)
be
the
representative
curve
of
the
function
h
.
a
Give
the
ordinate
of
the
point
of
(
C
h
)
abscissa
0
.
b
How
many
points
(
C
h
)
have
ordinate
1
6
?
Give,
if
they
exist,
the
coordinates
of
these
points.
17.
Set
of
definitions
E.363
Determine
the
definition
set
of
the
following
functions
:
1
f
:
x
↦−→
2
x
+
5
2
g
:
x
↦−→
1
x
3
h
:
x
↦−→
1
2
x
+
5
4
j
:
x
↦−→
x
+
1
2
x
+
5
5
k
:
x
↦−→
x
6
‘
:
x
↦−→
x
2
7
m
:
x
↦−→
2
x
+
5
8
n
:
x
↦−→
−
x
+
2
https://chingmath.fr
chapExoCorrec/4451
sacados/4451
-5-4-3-2-1012345-3-2-1123ijCfCf
chapExoCorrec/373
sacados/373
x-5-4-3-2-1012345678y-2-11234Cg
chapExoCorrec/2731
sacados/2731
chapExoCorrec/363
sacados/363
x-5-4-3-2-1012345y-3-2-1123CfCf
hBb
ABCDFGH
E.377
Determine
the
definition
set
for
each
of
the
functions
below
:
1
f
:
x
↦−→
1
3
x
+
7
2
g
:
x
↦−→
1
−
6
x
E.2755
Consider
the
function
f
whose
image
of
a
number
x
is
defined
by
the
relation:
f
(
x
)
=
2
x
+
1
x
−
4
1
Determine
the
definition
set
of
the
function
f
.
2
Determine
the
image
of
the
number
3
by
the
function
f
.
3
Determine
the
set
of
antecedents
of
0
by
the
function
f
.
E.2710
In
the
reference
frame
below,
is
rep-resented
the
curve
of
the
function
f
1
Determine
the
images
of
the
following
numbers
by
the
function
f
:
a
1
b
0
c
−
2
2
Determine
the
set
of
antecedents
for
each
of
the
following
numbers
:
a
2
b
−
2
3
a
Give
two
numbers
that
do
not
admit
images
by
the
function
f
.
b
Give
a
number
that
admits
no
antecedents
by
the
func-tion
f
.
18.
Unclassified
exercises
E.1782
1
Establish
for
any
non-zero
natural
number
p
the
follow-ing
equality:
1
p
−
1
p
+
1
=
1
p
(
p
+
1)
2
Deduce
the
value
of
the
following
sum
:
S
=
1
1
×
2
+
1
2
×
3
+
1
3
×
4
+
·
·
·
+
1
2003
×
2004
+
1
2004
×
2005
E.455
The
following
equation
is
to
be
solved
:
3
x
−
1
x
+
1
=
6
x
−
3
3
x
+
3
1
Give
the
solution
set
for
the
above
equation.
2
Solve
this
equation.
E.6598
Solve
the
following
equations
:
a
(3
x
+1)(5
x
−
2)=(6
x
+2)(1
−
x
)
b
1
x
+1
+
2
x
−
1
=
0
E.6970
Solve
the
equations
:
a
x
3
x
+
2
=
5
x
2
x
+
1
b
4
x
−
2
2
x
−
3
−
6
x
−
2
3
x
+
1
=
0
E.6695
Reminder
:
Area
of
a
trape-zoid
A
=
(
B
+
b
)
×
h
2
A
rectangular
pizza
ABCD
has
crust
on
two
consecutive
sides,
[
DA
]
and
[
AB
]
.
We
want
to
divide
the
pizza
into
three
equal
pieces
:
each
slice
must
have
the
same
length
of
crust
and
the
same
area.
We
set
the
length
of
the
short
side
AD
=1
.
In
the
specific
case
shown
here,
we
assume
that
the
division
is
equal.
Determine
the
lengths
:
DF
,
FH
,
and
HC
.
Any
evidence
of
research
and
initiative,
even
if
incom-plete,
will
be
taken
into
account
in
the
evaluation.
E.4447
Expand
the
following
expressions
:
a
(2
x
+
1)(3
−
x
)
b
(5
−
2
x
)(3
−
x
)
−
3(3
−
2
x
)
c
4(
x
+
4)(5
−
2
x
)
d
(
x
−
2)(2
x
−
1)(5
−
x
)
https://chingmath.fr
chapExoCorrec/377
sacados/377
chapExoCorrec/2755
sacados/2755
chapExoCorrec/2710
sacados/2710
x-5-4-3-2-1012345y-3-2-1123CfCf
chapExoCorrec/1782
sacados/1782
chapExoCorrec/455
sacados/455
chapExoCorrec/6598
sacados/6598
chapExoCorrec/6970
sacados/6970
chapExoCorrec/6695
sacados/6695
hBb
ABCDFGH
chapExoCorrec/4447
sacados/4447
-3-2-1234I-2-1234JOCfCg
E.6596
Expand
and
reduce
the
following
expressions
:
a
(2
x
+
1)(3
−
x
)
−
2(3
x
+
2)
b
(2
x
+
1)
2
c
(2
x
+
1)(1
−
x
)(
x
+
2)
E.4484
Definition:
a
random
experiment
is
said
to
be
equiprobable
if
each
of
its
outcomes
has
the
same
probability
of
occur-ring.
The
probability
of
an
event
is
equal
to
the
sum
of
the
probabilities
of
the
outcomes
that
define
it.
Proposition:
For
an
equiprobable
random
experiment
with
N
outcomes
and
for
an
event
A
defined
by
n
outcomes,
the
probability
of
A
has
the
value
:
n
N
Example:
We
throw
a
balanced
die
where
the
six
faces
are
numbered
from
1
to
6
.
Consider
the
event
A
:
ˇ
the
face
obtained
is
strictly
greater
than
4
ı.
This
event
is
composed
of
2
out-comes.
The
probability
of
the
event
A
is
:
2
6
=
1
×
2
\
3
×
2
\
Jean
owns
365
comic
book
albums.
In
order
to
sort
the
al-bums
in
his
collection,
he
is
arranged
by
series
and
classifies
the
series
into
three
categories:
franco-belges,
comics
and
manga
as
below
:
Séries
franco-belges
Séries
de
comics
23
albums
ˇAstérixı
22
albums
ˇTintinı
45
albums
ˇLucky-Lukeı
35
albums
ˇBatmanı
90
albums
ˇSpider-Manı
Manga
series
85
albums
ˇOne-pièceı
65
albums
ˇNarutoı
He
chooses
an
album
at
random
from
all
those
in
his
collec-tion.
1
What
is
the
probability
that
the
chosen
album
is
a
ˇ
Lucky-Luke
ı
album?
2
What
is
the
probability
that
the
chosen
album
is
a
comic
book?
E.4448
Solve
the
following
equations
using
the
method
of
your
choice
:
a
(3
x
−
2)(10
x
+
4)
=
(3
−
2
x
)(5
x
+
2)
b
(5
−
2
x
)(3
x
+
4)
−
(5
−
2
x
)
=
0
E.4462
Solve
the
following
equations
using
the
method
of
your
choice
:
a
(
x
−
2)(3
x
+
1)
=
2(
x
−
2)(
x
−
5)
b
(5
−
2
x
)(3
x
+
1)
+
(4
x
+
10)(2
x
−
5)
=
0
c
(2
x
+
3)(8
x
−
3)
+
(3
−
4
x
)(4
x
+
1)
=
0
E.4443
Solve
the
equations
below
:
a
10
x
2
−
15
x
=
(2
x
−
3)(3
x
+
1)
b
(3
−
x
)(4
x
+
2)
−
(6
x
+
3)(5
−
2
x
)
=
0
c
(3
−
2
x
)(
x
+
1)
+
(6
x
−
9)(3
−
4
x
)
=
0
E.9685
Solve
the
following
equations
:
a
x
+
1
x
−
1
=
3
x
x
+
1
b
x
2
x
−
1
−
2
x
−
1
3
−
x
=
0
E.4815
Solve
the
following
equations
:
a
(
x
+
1)
2
=
4
b
(
x
−
2)
2
+
4
=
7
c
(
x
+
2)
2
+
5
=
2
d
3
·
x
2
−
6
=
1
E.4461
Factor
the
following
expressions
:
a
(5
x
−
1)(3
x
+
1)
+
(5
x
−
1)
2
b
(3
x
+
1)(2
−
3
x
)
+
(2
−
3
x
)
c
(
x
−
3)(7
−
x
)
+
(
x
−
3)(2
x
+
1)
d
(3
x
−
1)(
x
−
2)
−
(
x
−
2)(1
−
5
x
)
E.4449
Consider
the
two
functions
f
and
g
defined
by
the
relations
:
f
(
x
)
=
(2
x
+
1)(2
−
x
)
;
g
(
x
)
=
1
8
(2
x
+
1)
2
Their
graphical
representations
are
given
below
in
the
refer-ence
frame
O
;
I
;
J
orthonormal
:
1
Determine,
graphically,
the
coordinates
of
the
intersec-tion
points
of
the
curves
C
f
and
C
g
.
2
a
Solve
the
following
equation
:
(2
x
+
1)
2
=
8(2
x
+
1)(2
−
x
)
b
Determine,
by
calculation,
the
images
of
the
numbers
−
1
2
and
3
2
by
the
functions
f
and
g
.
3
What
do
the
solution
numbers
f
(
x
)=
g
(
x
)
represent
for
the
two
curves
C
f
and
C
g
.
https://chingmath.fr
chapExoCorrec/6596
sacados/6596
chapExoCorrec/4484
sacados/4484
chapExoCorrec/4448
sacados/4448
chapExoCorrec/4462
sacados/4462
chapExoCorrec/4443
sacados/4443
chapExoCorrec/9685
sacados/9685
chapExoCorrec/4815
sacados/4815
chapExoCorrec/4461
sacados/4461
chapExoCorrec/4449
sacados/4449
-3-2-1234I-2-1234JOCfCg
OABCIxyM
E.2867
west
Indies
ffl
2004
ffl
7
points
ffl
Com-pulsory
The
figure
below
is
a
diagram
of
a
car
jack.
This
consists
of
a
deformable
rhombus
OABC
,
the
point
O
being
the
point
of
support
on
the
ground
and
the
point
B
being
the
point
through
which
the
car
is
lifted.
With
each
turn
of
the
crank
M
,
the
nuts
A
and
C
move
to-wards
(or
away)
from
2
cm
,
which
moves
(or
down)
the
B
support
up,
along
the
(
Oy
)
axis.
We
give
:
OA
=
OC
=
AB
=
BC
=25
cm
In
the
orthonormal
frame
of
reference
(
O
;
x
;
y
)
of
unit
one
centimetre,
x
A
designates
the
abscissa
of
the
point
A
and
varies
from
0
to
25.
The
ordinate
of
point
B
is
denoted
y
B
:
For
x
A
=0
,
we
have
:
y
B
=50
;
For
x
A
=25
,
we
have
:
y
B
=0
.
1
Demonstrate
that
the
values
x
A
and
y
B
verify
the
rela-tionship
:
y
B
=
2
625
−
x
A
2
2
a
Determine
the
value
of
y
B
when
x
A
is
equal
to
7
.
b
Determine
the
value
of
x
A
when
y
B
equals
40
.
3
Assume
the
jack
is
closed
;
the
height
of
point
B
is
then
0
cm
:
a
When
the
jack
is
fully
closed,
how
many
crank
turns
are
required
to
reach
a
height
of
24
cm
for
point
B
?
b
How
many
more
turns
does
it
take
to
double
the
height
of
point
B
?
https://chingmath.fr
chapExoCorrec/2867
sacados/2867
OABCIxyM