a
Middle
School
Grade 6
Grade 7
Grade 8
Grade 9
Ressource
Out Middle
High
School
Grade 10
Grade 11
Grade 11 - STMG
Grade 12 - STMG
Grade 12
Grade 12 - Comp.
Grade 12 - Exp.
Ressource
Out High
4
3
2
1
Grade 12 - Comp.
/ Annales sequences
10 exercises (100% corrected)
a
Threshold
(2 exercices)
Limits
(4 exercices)
Solving inequalities
(3 exercices)
Sum of terms
(2 exercices)
1.
Thr
eshold
E.7207
On
1
er
Septem
b
er
2015
,
a
sc
ho
ol
complex
has
3
000
studen
ts.
An
in
ternal
statistical
study
sho
w
ed
that
ev
ery
Septem
b
er
1
er
:
10
%
of
the
studen
t
b
o
dy
lea
v
es
the
sc
ho
ol
;
250
new
studen
ts
enroll.
W
e
seek
to
mo
del
this
situation
using
a
sequence
u
n
where,
for
an
y
natural
n
um
b
er
n
,
u
n
represen
ts
the
n
um
b
er
of
stu-
den
ts
on
Septem
b
er
1
er
of
y
ear
2015+
n
.
1
Justify
that
w
e
can
mo
del
the
situation
with
the
sequence
u
n
suc
h
that
u
0
=
3
000
and,
for
an
y
natural
n
um
b
er
n
:
u
n
+1
=
0.9
·
u
n
+250
.
2
F
or
an
y
natural
n
um
b
er
n
,
w
e
set
:
v
n
=
u
n
−
2
500
.
a
Demonstrate
that
the
sequence
v
n
is
geometric
with
ratio
0.9
.
Sp
ecify
v
0
.
b
Express,
for
an
y
natural
n
um
b
er
n
,
v
n
as
a
function
of
n
.
Deduce
that
for
an
y
natural
n
um
b
er
n
:
u
n
=
500
×
0.9
n
+2
500
3
Pro
v
e
that
for
an
y
natural
n
um
b
er
n
:
u
n
+1
−
u
n
=
−
50
×
0.9
n
.
Deduce
the
direction
of
v
ariation
of
the
sequence
u
n
.
4
The
optimal
capacit
y
is
2
800
studen
ts.
Th
us,
on
Septem-
b
er
1
er
2015
,
the
sc
ho
ol
complex
has
an
excess
of
200
studen
ts.
W
rite
an
algorithm
to
determine
the
y
ear
in
whic
h,
as-
suming
the
con
text
remains
the
same,
the
sc
ho
ol
complex
will
no
longer
ha
v
e
an
excess
of
studen
ts.
E.6973
Let
the
sequence
u
n
b
e
defined
b
y
:
u
0
=
150
and
for
an
y
natural
n
um
b
er
n
,
u
n
+1
=
0.8
·
u
n
+
45
.
1
Calculate
u
1
and
u
2
.
2
Here
are
t
w
o
prop
osed
algorithms
:
Algorithm
1
u
←
150
n
←
0
While
u
220
u
←
0.8
×
u
+
45
n
←
n+1
End
While
Algorithm
2
u
←
150
n
←
0
While
u
<
220
u
←
0.8
×
u
+
45
n
←
n+1
End
As
long
as
W
e
are
in
terested
in
the
v
alue
of
the
v
ariable
n
at
the
end
of
the
algorithm’s
execution.
a
Only
one
of
these
algorithms
allo
ws,
at
the
end
of
exe-
cution,
the
v
ariable
n
to
b
e
assigned
the
smallest
nat-
ural
n
um
b
er
n
suc
h
that
u
n
220
.
Sp
ecify
whic
h
one,
explaining
wh
y
the
other
algorithm
do
es
not
allo
w
this.
b
What
is
the
n
umerical
v
alue
of
the
v
ariable
n
at
the
end
of
the
algorithm?
3
Consider
the
sequence
v
n
defined
for
all
natural
n
um-
b
ers
n
b
y
:
v
n
=
u
n
−
225
a
Sho
w
that
v
n
is
a
geometric
sequence
and
sp
ecify
its
first
term
and
common
ratio
b
Deduce
that
for
an
y
natural
n
um
b
er
n
:
u
n
=
225
−
75
×
0.8
n
4
Ev
ery
y
ear,
a
small
pro
vincial
to
wn
organizes
a
fo
otrace
through
the
streets
of
its
cen
ter.
In
2015
,
the
n
um
b
er
of
participan
ts
in
this
race
w
as
150
.
W
e
assume
that
from
one
y
ear
to
the
next
:
20
%
participan
ts
do
not
return
the
follo
wing
y
ear
;
45
new
participan
ts
register
for
the
race.
The
narro
w
streets
of
the
historic
cit
y
cen
ter
force
orga-
nizers
to
limit
the
n
um
b
er
of
participan
ts
to
250
.
Will
they
ha
v
e
to
refuse
registrations
in
the
coming
y
ears?
Justify
y
our
answ
er.
2.
Limits
E.6976
A
large
univ
ersit
y
,
exp
erienc-
ing
rapid
gro
wth
in
enrollmen
t,
w
elcomed
27
500
studen
ts
in
Septem
b
er
2016
.
The
univ
ersit
y
presiden
t
is
concerned
b
ecause
he
kno
ws
that,
despite
optimal
managemen
t
of
the
premises
and
distribution
of
studen
ts
across
the
univ
ersit
y’s
v
arious
sites,
he
will
not
b
e
able
to
accommo
date
more
than
33
000
studen
ts.
A
statistical
study
allo
ws
him
to
dev
elop
a
forecast
mo
del
according
to
whic
h,
eac
h
y
ear
:
150
studen
ts
drop
out
during
the
academic
y
ear
(b
etwe
en
Septemb
er
1
er
and
June
30
)
;
the
n
um
b
er
of
studen
ts
enrolled
at
the
start
of
the
aca-
demic
y
ear
in
Septem
b
er
increases
b
y
4
%
compared
to
the
previous
mon
th
of
June.
F
or
an
y
natural
n
um
b
er
n
,
w
e
note
u
n
the
estimated
n
um-
b
er
of
studen
ts
according
to
this
mo
del
at
the
start
of
the
academic
y
ear
in
Septem
b
er
2016+
n
,
so
w
e
ha
v
e
u
0
=
27
500
.
1
a
Estimate
the
n
um
b
er
of
studen
ts
in
June
2017
.
b
Estimate
the
n
um
b
er
of
studen
ts
at
the
start
of
the
sc
ho
ol
y
ear
in
Septem
b
er
2017
.
2
Justify
that,
for
an
y
natural
n
um
b
er
n
,
w
e
ha
v
e
:
u
n
+1
=
1.04
·
u
n
−
156
3
Cop
y
and
complete
the
lines
‘
.3
,
‘
.4
,
‘
.5
et
‘
.
7
of
the
follo
wing
algorithm
so
that
at
the
end
of
its
execu-
tion,
the
v
ariable
n
has
the
v
alue
of
the
y
ear
from
whic
h
the
n
um
b
er
of
studen
ts
to
b
e
admitted
will
exceed
the
maxim
um
capacit
y
of
the
institution
‘
.1
n
←
0
‘
.2
u
←
27
500
h
ttps:/
/c
hingmath.fr
chapExoCorrec/7207
sacados/7207
Asie Juin 2016
chapExoCorrec/6973
sacados/6973
chapExoCorrec/6976
sacados/6976
‘
.3
As
long
as
u
...
‘
.4
n
←
...
‘
.5
u
←
...
‘
.6
End
As
long
as
‘
.7
n
←
2017+...
4
a
W
e
run
this
algorithm
step
b
y
step.
Cop
y
the
follo
wing
table
and
complete
it
b
y
adding
the
necessary
n
um
b
er
of
columns
;
round
the
v
alues
of
U
to
the
nearest
whole
n
um
b
er.
Initialization
Step
1
.
.
.
V
alue
of
n
0
.
.
.
.
.
.
V
alue
of
U
27
500
.
.
.
.
.
.
b
Giv
e
the
v
alue
assigned
to
the
v
ariable
n
at
the
end
of
the
execution
of
this
algorithm.
5
W
e
seek
to
explicitly
calculate
the
general
term
u
n
as
a
function
of
n
.
T
o
do
this,
w
e
denote
v
n
the
sequence
defined,
for
an
y
natural
n
um
b
er
n
,
b
y
v
n
=
u
n
−
3
900
.
a
Sho
w
that
v
n
is
a
geometric
sequence,
sp
ecifying
the
ratio
and
the
first
term
b
Deduce
that,
for
an
y
natural
n
um
b
er
n
:
u
n
=
23
600
×
1.04
n
+
3
900
.
c
Determine
the
limit
of
the
sequence
u
n
and
giv
e
an
in
terpretation
in
the
con
text
of
the
exercise.
E.6980
The
t
w
o
parts
are
indep
enden
t
P
art
A
:
The
Ky
oto
Agreemen
t
(1997)
The
main
greenhouse
gas
(GES)
is
carb
on
dio
xide,
denoted
C
O
2
.
In
2011
,
F
rance
emitted
486
megatons
of
GHG
equiv
alen
ts
C
O
2
compared
to
559
megatons
in
1990
.
1
In
the
Ky
oto
Agreemen
t,
F
rance
committed
to
reducing
its
GHG
emissions
b
y
8
%
b
et
w
een
1990
and
2012
.
Can
w
e
sa
y
that
in
2011
F
rance
w
as
already
meeting
this
commitmen
t?
Justify
y
our
answ
er.
2
Giv
en
that
emissions
in
2011
w
ere
do
wn
5.6
%
compared
to
2010
,
calculate
the
n
um
b
er
of
megatons
of
C
O
2
equiv-
alen
t
emitted
b
y
F
rance
in
2010
.
Round
y
our
answ
er
to
0.1
.
P
art
B
:
Study
of
greenhouse
gas
emissions
in
an
in-
dustrial
zone
A
plan
to
reduce
greenhouse
gas
emissions
(GES)
has
b
een
implemen
ted
in
an
industrial
zone.
It
is
estimated
that,
for
companies
already
established
on
the
site,
the
measures
in
this
plan
will
lead
to
a
reduction
in
emissions
of
2
%
y
ear-on-
y
ear
and
that,
eac
h
y
ear,
new
companies
setting
up
on
the
site
will
generate
200
tons
of
GHG
equiv
alen
t
C
O
2
.
In
2005
,
this
industrial
zone
emitted
a
total
of
41
thousand
tons
of
C
O
2
F
or
the
whole
natural
y
ear
n
,
w
e
note
u
n
the
n
um
b
er
of
thou-
sand
tons
of
C
O
2
emitted
in
this
industrial
zone
during
the
y
ear
2005+
n
.
1
Determine
u
0
and
u
1
.
2
Sho
w
that,
for
an
y
natural
n
um
b
er
n
,
w
e
ha
v
e
:
u
n
+1
=
0.98
×
u
n
+
0.2
.
3
Consider
the
sequence
v
n
defined,
for
an
y
natural
n
um-
b
er,
b
y
:
v
n
=
u
n
−
10
a
Sho
w
that
the
sequence
v
n
is
geometric
with
com-
mon
ratio
0.98
.
Sp
ecify
its
first
term.
b
Express
v
n
in
terms
of
n
,
for
an
y
natural
n
um
b
er
n
.
c
Deduce
that,
for
an
y
natural
n
um
b
er
n
:
u
n
=
31
×
(0.98)
n
+10
.
4
a
Calculate
the
limit
of
the
sequence
u
n
.
b
In
terpret
this
result
in
the
con
text
of
the
exercise.
5
W
e
w
an
t
to
use
the
algorithm
b
elo
w
so
that
the
v
alue
of
v
ariable
n
helps
us
determine
the
y
ear
from
whic
h
the
industrial
zone
will
ha
v
e
reduced
its
emissions
b
y
at
least
half
C
O
2
,
compared
to
the
y
ear
2005
a
Cop
y
and
complete
lines
3
and
4
of
the
algorithm.
‘
.1
U
←
41
‘
.2
n
←
0
‘
.3
As
long
as
...
‘
.4
u
←
...
‘
.5
n
←
n+1
‘
.6
End
As
long
as
b
A
t
the
end
of
the
algorithm,
the
v
ariable
n
is
assigned
the
v
alue
54
.
In
terpret
this
result
in
the
con
text
of
the
exercise
h
ttps:/
/c
hingmath.fr
chapExoCorrec/6980
sacados/6980
Liban Juin 2017
E.6987
An
individual
o
wns
a
swimming
p
o
ol
and
decides
to
install
an
automatic
filling
system
to
com-
p
ensate
for
ev
ap
oration
during
the
summer.
On
a
sp
ecialized
w
ebsite,
he
learns
that
the
climatic
conditions
in
his
region
during
this
p
erio
d
are
suc
h
that
he
can
exp
ect
daily
ev
ap
ora-
tion
of
4
%
of
the
w
ater
v
olume.
He
then
decides
to
set
his
automatic
filling
system
to
add
2
m
3
of
w
ater
p
er
da
y
.
On
the
first
da
y
of
op
eration
of
the
automatic
filling
system,
the
p
o
ol
con
tains
75
m
3
.
F
or
an
y
natural
in
teger
n
,
w
e
note
u
n
as
the
v
olume
of
w
ater
in
the
p
o
ol,
expressed
in
cubic
meters
(
m
3
)
,
n
da
ys
after
the
automatic
filling
system
w
as
put
in
to
op
eration.
Th
us,
u
0
=
75
.
1
Calculate
u
1
and
u
2
.
2
Justify
that
the
sequence
u
n
is
not
arithmetic.
Is
it
geometric?
3
Justify
that,
for
an
y
natural
n
um
b
er
n
:
u
n
+1
=
0.96
×
u
n
+2
4
F
or
an
y
natural
n
um
b
er
n
,
w
e
set
:
v
n
=
u
n
−
50
a
Sho
w
that
the
sequence
v
n
is
a
geometric
sequence
with
common
ratio
0.96
and
first
term
v
0
b
F
or
an
y
natural
n
um
b
er
n
,
express
v
n
in
terms
of
n
.
c
Deduce
that
for
an
y
natural
n
um
b
er
n
:
u
n
=
25
×
0.96
n
+
50
d
Determine
the
limit
of
the
sequence
u
n
and
in
terpret
this
result
in
the
con
text
of
the
exercise.
5
If
the
v
olume
of
w
ater
in
the
p
o
ol
is
less
than
65
m
3
,
the
w
ater
lev
el
is
insufficien
t
to
p
o
w
er
the
filtration
pumps,
whic
h
ma
y
damage
them.
T
o
find
out
the
n
um
b
er
of
da
ys
during
whic
h
the
w
ater
lev
el
remains
sufficien
t
without
risk
of
failure
while
main
taining
this
setting,
w
e
construct
the
follo
wing
algorithm
:
‘
.1
n
←
0
‘
.2
u
←
75
‘
.3
As
long
as
u...
‘
.4
u
←
...
‘
.5
n
←
n+1
‘
.6
End
While
A
t
the
end
of
its
execution,
the
v
ariable
n
should
con-
tain
the
n
um
b
er
of
da
ys
for
whic
h
the
w
ater
lev
el
will
b
e
sufficien
t.
a
Cop
y
and
complete
lines
‘
.3
and
‘
.4
of
this
algorithm.
b
What
is
the
v
alue
assigned
to
v
ariable
n
at
the
end
of
the
algorithm
execution?
c
Ho
w
man
y
da
ys
will
the
w
ater
lev
el
b
e
sufficien
t
if
this
setting
is
main
tained?
E.6992
In
2015
,
forests
co
v
ered
appro
xi-
mately
4
000
million
hectares
of
land.
It
is
estimated
that
this
area
decreases
b
y
0.4
%
eac
h
y
ear.
This
loss
is
partly
offset
b
y
natural
or
v
olun
tary
reforestation,
whic
h
is
estimated
at
7.2
million
hectares
p
er
y
ear.
Consider
the
sequence
u
n
defined
b
y
u
0
=
4
000
and,
for
an
y
natural
n
um
b
er
n
:
u
n
+1
=
0.996
×
u
n
+
7.2
1
Justify
that,
for
an
y
natural
in
teger
n
,
u
n
pro
vides
an
estimate
of
the
global
forest
area,
in
millions
of
hectares,
for
the
y
ear
2015+
n
.
2
Cop
y
and
complete
the
algorithm
b
elo
w
so
that,
at
the
end
of
its
execution,
the
v
ariable
N
has
the
v
alue
of
the
first
y
ear
for
whic
h
the
total
forest
area
co
v
ers
less
than
3
500
million
hectares
on
earth.
N
←
2015
U
←
4
000
...
...
...
3
Consider
the
sequence
v
n
defined
for
all
natural
n
um-
b
ers
n
b
y
:
v
n
=
u
n
−
1
800
a
Pro
v
e
that
the
sequence
v
n
is
geometric,
then
sp
ecify
its
first
term
and
its
ratio.
b
Deduce
that
for
an
y
natural
n
um
b
er
n
,
w
e
ha
v
e
:
u
n
=
2200
×
0.996
n
+
1800
y
c
A
ccording
to
this
mo
del,
if
the
phenomenon
con
tin
ues,
will
the
Earth’s
forest
co
v
er
ev
en
tually
disapp
ear?
Jus-
tify
y
our
answ
er
4
A
study
sho
ws
that,
to
comp
ensate
for
the
n
um
b
er
of
trees
destro
y
ed
o
v
er
the
last
ten
y
ears,
140
billion
trees
w
ould
need
to
b
e
plan
ted
in
10
y
ears.
In
2016
,
it
is
estimated
that
the
n
um
b
er
of
trees
plan
ted
b
y
the
United
Nations
(ONU)
is
7.3
billion.
It
is
assumed
that
the
n
um
b
er
of
trees
plan
ted
b
y
the
UN
increases
b
y
10
%
eac
h
y
ear.
Can
the
UN
succeed
in
replan
ting
140
billion
trees
b
et
w
een
2016
and
2025
?
3.
Solving
ine
qualities
E.6984
Japanese
knot
w
eed
is
a
v
ery
fast-
gro
wing
and
highly
in
v
asiv
e
plan
t.
A
gardener
w
an
ts
to
remo
v
e
this
sp
ecies
from
his
land,
whic
h
co
v
ers
an
area
of
120
m
2
on
Jan
uary
1
er
,
2017
.
T
o
do
this,
ev-
ery
spring
he
pulls
up
the
plan
ts,
reducing
the
area
of
land
in-
v
aded
the
previous
y
ear
b
y
10
%
.
Ho
w
ev
er,
this
plan
t
sp
ecies
spreads
v
ery
quic
kly
,
and
new
sho
ots
app
ear
ev
ery
summer,
in
v
ading
a
new
plot
of
land
with
an
area
of
4
m
2
.
1
Determine
the
area
of
land
in
v
aded
b
y
this
plan
t
on
1
er
Jan
uary
2018
.
W
e
mo
del
the
situation
using
a
sequence
u
n
where
u
n
rep-
resen
ts
the
area
of
land
m
2
in
v
aded
b
y
Japanese
knot
w
eed
on
Jan
uary
1
er
of
the
y
ear
2017+
n
.
The
sequence
u
n
is
therefore
defined
b
y
u
0
=
120
and,
for
an
y
natural
n
um
b
er
n
,
b
y
:
u
n
+1
=
0.9
·
u
n
+
4
2
Le
gardener
wishes
to
kno
w
the
y
ear
from
whic
h
he
will
ha
v
e
at
least
halv
ed
the
area
of
in
v
aded
land
compared
to
1
er
Jan
uary
of
y
ear
2017
h
ttps:/
/c
hingmath.fr
chapExoCorrec/6987
sacados/6987
Antilles Juin 2017
chapExoCorrec/6992
sacados/6992
chapExoCorrec/6984
sacados/6984
Cop
y
and
complete
the
lines
‘
.1
,
‘
.3
,
‘
.4
and
‘
.7
of
the
algorithm
b
elo
w
so
that,
at
the
end
of
its
execution,
the
v
ariable
u
has
the
desired
y
ear
as
its
v
alue.
It
is
not
necessary
to
run
the
algorithm
‘
.1
u
←
...
‘
.2
n
←
0
‘
.3
As
long
as
...
‘
.4
u
←
...
‘
.5
n
←
n+1
‘
.6
End
as
long
as
‘
.7
n
←
...
3
W
e
consider
the
sequence
v
n
defined
for
an
y
natural
n
um
b
er
n
b
y
:
v
n
=
u
n
−
40
a
Mon
trer
that
the
sequence
v
n
is
a
geometric
sequence
of
reason
q
=
0.9
and
sp
ecify
the
first
term.
b
Express
v
n
as
a
function
of
n
,
for
an
y
natural
n
um
b
er
n
.
c
Justify
that
u
n
=
80
×
0.9
n
+40
for
an
y
natural
n
um
b
er
n
.
4
a
Solv
e
in
the
set
of
natural
n
um
b
ers
the
inequation
:
80
×
0.9
n
+
40
60
b
En
deduce
the
y
ear
from
whic
h
the
area
in
v
aded
b
y
the
plan
t
will
b
e
at
least
halv
ed
compared
to
1
er
Jan
uary
of
y
ear
2017
.
5
Will
the
gardener
manage
to
completely
remo
v
e
the
plan
t
from
his
land?
Justify
y
our
answ
er
E.7208
In
order
to
com
bat
air
p
ollution,
as
early
as
the
y
ear
2013
certain
companies
w
ere
obliged
to
reduce
the
quan
tit
y
of
p
ollutan
ts
they
released
in
to
the
air
eac
h
y
ear.
These
companies
disc
harged
410
tonnes
of
these
p
ollutan
ts
in
2013
and
332
tonnes
in
2015
.
The
ann
ual
rate
of
decrease
in
the
mass
of
p
ollutan
ts
released
is
assumed
to
b
e
constan
t.
1
Justify
that
the
y
ear-on-y
ear
c
hange
can
b
e
considered
to
corresp
ond
to
a
decrease
of
10
%
.
2
Assuming
that
this
rate
of
10
%
remains
constan
t
for
the
coming
y
ears,
determine
from
whic
h
y
ear
on
w
ards
the
quan
tit
y
of
p
ollutan
ts
disc
harged
b
y
these
companies
will
no
longer
exceed
the
threshold
of
180
tonnes
set
b
y
the
departmen
tal
council.
E.7212
P
art
A
Let
u
n
b
e
the
sequence
defined
b
y
u
0
=
350
and,
for
an
y
natural
n
um
b
er
n
:
u
n
+1
=
0.5
·
u
n
+100
1
Calculate
u
1
and
u
2
.
2
Consider
the
sequence
w
n
defined
for
an
y
natural
n
um-
b
er
n
b
y
:
w
n
=
u
n
−
200
.
a
Sho
w
that
the
sequence
w
n
is
a
geometric
sequence,
sp
ecifying
the
ratio
and
the
first
term.
b
Demonstrate
that,
for
an
y
natural
n
um
b
er
n
:
u
n
=
200
+
150
×
0.5
n
.
P
art
B
A
m
unicipalit
y
offers
c
hildren
the
opp
ortunit
y
to
join
a
sp
orts
asso
ciation.
On
Septem
b
er
1,
2015
,
the
n
um
b
er
of
c
hildren
enrolled
in
this
club
is
500
,
including
350
girls.
Statistics
from
previous
y
ears
lead
us
to
the
follo
wing
mo
del
for
the
ev
olution
of
mem
b
ership
n
um
b
ers
in
the
coming
y
ears
:
Eac
h
y
ear,
half
of
the
girls
who
enrolled
the
previous
y
ear
do
not
renew
their
mem
b
ership
;
in
addition,
the
club
w
elcomes
100
new
girls
eac
h
y
ear.
F
rom
one
y
ear
to
the
next,
the
n
um
b
er
of
b
o
ys
enrolled
in
the
club
increases
b
y
10
%
.
1
W
e
represen
t
the
c
hange
in
the
n
um
b
er
of
girls
enrolled
in
this
club
b
y
a
sequence
F
n
where
F
n
denotes
the
n
um
b
er
of
girls
who
joined
the
asso
ciation
in
the
y
ear
2015+
n
.
W
e
therefore
ha
v
e
:
F
0
=
350
.
F
or
an
y
natural
n
um
b
er
n
,
express
F
n
+1
as
a
function
of
F
n
.
2
W
e
represen
t
the
c
hange
in
the
n
um
b
er
of
b
o
ys
enrolled
in
this
club
b
y
a
sequence
G
n
,
where
G
n
denotes
the
n
um
b
er
of
b
o
ys
who
w
ere
mem
b
ers
of
the
asso
ciation
in
the
y
ear
2015+
n
.
a
F
or
an
y
natural
n
um
b
er
n
,
express
G
n
in
terms
of
n
.
b
In
whic
h
y
ear
will
the
club
ha
v
e
more
than
300
b
o
ys?
3
W
e
w
an
t
to
kno
w
from
whic
h
y
ear
on
w
ards
the
n
um
b
er
of
b
o
ys
in
this
asso
ciation
will
exceed
the
n
um
b
er
of
girls.
W
e
prop
ose
the
follo
wing
algorithm
:
n
←
0
G
←
150
F
←
350
As
long
as
G
F
n
←
n+1
G
←
1.1
·
G
F
←
0.5
·
F+100
End
As
long
as
a
Cop
y
and
complete
the
follo
wing
table
as
necessary
.
The
results
will
b
e
rounded
to
the
nearest
whole
n
um-
b
er.
V
alue
of
n
0
1
V
alue
of
G
150
V
alue
of
F
350
Condition
G
F
b
Deduce
the
v
alue
assigned
to
v
ariable
n
at
the
end
of
the
algorithm
execution.
4.
Sum
of
terms
E.7536
During
a
game,
Marc
m
ust
answ
er
the
follo
wing
question
:
On
the
first
da
y
,
w
e
offer
y
ou
100
e
then
eac
h
follo
wing
da
y
,
w
e
offer
y
ou
5
%
more
than
the
da
y
b
efore
and
a
fixed
sum
of
20
e
.
After
ho
w
man
y
da
ys
will
y
ou
ha
v
e
earned
10
000
e
?
h
ttps:/
/c
hingmath.fr
chapExoCorrec/7208
sacados/7208
Antilles-Guyane Juin 2016
chapExoCorrec/7212
sacados/7212
chapExoCorrec/7536
sacados/7536
1
F
or
an
y
non-zero
natural
n
um
b
er
n
,
note
u
n
the
to-
tal
amoun
t
in
e
paid
to
Mark
on
the
n
-th
da
y
.
Th
us,
u
1
=
100
.
a
Calculate
u
2
.
b
Justify
that,
for
an
y
non-zero
natural
n
um
b
er
n
:
u
n
+1
=
1.05
·
u
n
+
20
2
F
or
an
y
non-zero
natural
n
um
b
er
n
,
w
e
p
ose
v
n
=
u
n
+
400
.
a
Calculate
v
1
.
b
Demonstrate
that
the
sequence
v
n
is
a
geometric
se-
quence
and
sp
ecify
its
reason.
c
Express
v
n
in
terms
of
n
,
then
deduce
that
:
u
n
=
500
×
1.05
n
−
1
−
400
d
Determine,
as
a
function
of
n
,
the
sum
:
v
1
+
v
2
+
···
+
v
n
.
3
What
answ
er
should
Marc
giv
e?
h
ttps:/
/c
hingmath.fr
ChingMath
by ChingLab
©
Middle School
Grade 6
Grade 7
Grade 8
Grade 9
High School
Grade 10
Grade 11
Grade 12
Grade 12 opt. Complémentaire
Grade 12 opt. Experte
Various
Contact me
F.A.Q
Other website
ChingWeb