- A little further: arithmetic-geometric sequences (3 exercices)
- Reminders (4 exercices)
- Modeling a problem (3 exercices)
- Explicit formula (3 exercices)
- Limit (3 exercices)
- Weir study (3 exercices)
- Solving inequalities (logarithm) (2 exercices)
- Reminders Sum of the terms of a sequence (5 exercices)
- Threshold study (3 exercices)
- Sum of the terms of a geometric sequence (4 exercices)
- Geometric sequences, threshold and sum (2 exercices)
- Geometric sequences: limits (4 exercices)
- Geometric sequences: limits and thresholds (2 exercices)
E.7040
On
1
er
September
2015
,
a
school
complex
has
3
000
pupils.
An
internal
statistical
study
has
shown
that
every
1
er
Septem-ber:
10
%
headcount
leaves
;
250
new
students
enroll.
We
seek
to
model
this
situation
by
a
sequence
u
n
where,
for
any
natural
number
n
,
u
n
represents
the
number
of
students
on
1
er
September
of
the
year
2015+
n
.
Justify
that
we
can
model
the
situation
with
the
sequence
u
n
such
that
u
0
=3
000
and,
for
any
natural
number
n
:
u
n
+1
=
0.9
·
u
n
+
250
E.7028
A
company
is
interested
in
the
number
of
3
D
screens
it
has
sold
since
2010
:
Année
2010
2011
2012
Number
of
screens
3
D
vendus
0
5
000
11
000
The
number
of
screens
3
D
sold
by
the
company
in
the
year
(2010+
n
)
is
modeled
by
a
sequence
u
n
,
arithmetic-geometric,
of
first
term
u
0
=0
.
Recall
that
an
arithmetic-geometric
sequence
verifies,
for
any
natural
number
n
,
a
recurrence
relation
of
the
form
u
n
+1
=
a
×
u
n
+
b
where
a
and
b
are
two
real
numbers.
1
a
Assuming
u
1
=5
000
,
determine
the
value
of
b
.
b
Assuming
further
that
u
2
=11
000
,
show
that
for
any
natural
number
n
,
we
have
:
u
n
+1
=
1.2
×
u
n
+
5
000
2
a
Calculate
u
3
and
u
4
.
b
In
2013
and
2014
,
the
company
sold
18
000
and
27
000
screens
respectively
3
D
.
Does
the
modeling
seem
relevant?
E.7012
The
company
PiscinePlus
,
based
in
the
south
of
France,
offers
annual
maintenance
contracts
to
private
pool
owners.
The
head
of
this
company
notes
that,
every
year,
12
%
ad-ditional
contracts
are
taken
out
and
6
contracts
terminated.
He
uses
this
observation
to
estimate
the
number
of
annual
contracts
to
come.
In
2015
,
the
company
PiscinePlus
counted
75
contracts
sub-scribed.
We
model
the
situation
by
a
sequence
u
n
where
u
n
repre-sents
the
number
of
contracts
taken
out
with
the
company
PiscinePlus
in
the
year
2015+
n
.
Thus,
we
have
u
0
=75
.
1
Estimate
the
number
of
maintenance
contracts
in
2016
.
2
Show
that,
for
any
natural
number
n
,
we
have
:
u
n
+1
=
1.12
·
u
n
−
6
4.
Explicit
formula
E.7527
Let
the
sequence
u
n
be
defined
by
u
0
=150
and
for
any
natural
number
n
:
u
n
+1
=
0.8
·
u
n
+
45
Consider
the
sequence
v
n
defined
for
any
natural
number
n
by:
v
n
=
u
n
−
225
1
Demonstrate
that
v
n
is
a
geometric
sequence
and
spec-ify
its
first
term
and
reason.
2
Deduce
that
for
any
natural
number
n
:
u
n
=
225
−
75
×
0.8
n
E.7529
Consider
the
sequence
u
n
de-fined
for
u
0
=27
500
and
for
any
natural
number
n
,
we
have
:
u
n
+1
=
1.04
·
u
n
−
156
We
seek
to
explicitly
calculate
the
general
term
u
n
as
a
func-tion
of
n
.
To
do
this,
note
v
n
the
sequence
defined,
for
any
natural
number
n
,
by:
v
n
=
u
n
−
3
900
1
Show
that
v
n
is
a
geometric
sequence
whose
reason
and
first
term
should
be
specified.
2
Deduce
that,
for
any
natural
number
n
:
u
n
=
23
600
×
1.04
n
+
3
900
E.7530
A
plan
to
reduce
greenhouse
gas
emissions
(GHG)
has
been
implemented
on
an
industrial
es-tate.
It
is
estimated
that,
for
companies
already
established
on
the
site,
the
measures
of
this
plan
lead
to
a
year-on-year
reduction
in
emissions
of
2
%
and
that,
each
year,
new
com-panies
setting
up
on
the
site
generate
200
tonnes
of
GHG
equivalent
CO
2
.
In
2005
,
this
industrial
estate
emitted
41
thousands
of
tons
of
CO
2
in
total.
For
any
natural
integer
n
,
let
u
n
be
the
number
of
thousand
tonnes
of
CO
2
emitted
in
this
industrial
zone
during
the
year
2005+
n
.
1
Determine
u
0
and
u
1
.
2
Show
that,
for
any
natural
number
n
,
we
have
:
u
n
+1
=
0.98
×
u
n
+
0.2
3
Consider
the
sequence
v
n
defined,
for
any
natural
num-ber
n
,
by:
v
n
=
u
n
−
10
a
Show
that
the
sequence
v
n
is
geometric
of
reason
0.98
.
Specify
its
first
term.
b
Express
v
n
as
a
function
of
n
,
for
any
natural
number
n
.
c
Deduce
that,
for
any
natural
number
n
:
u
n
=
31
×
0.98
n
+
10
5.
Limit
https://chingmath.fr
chapExoCorrec/7040
sacados/7040
Extrait d'Asie
Juin 2016
chapExoCorrec/7028
sacados/7028
chapExoCorrec/7012
sacados/7012
Extrait de Liban
Mai 2016
chapExoCorrec/7527
sacados/7527
chapExoCorrec/7529
sacados/7529
chapExoCorrec/7530
sacados/7530
Extrait Liban
Juin 2017
E.7033
A
car
rental
company
has
a
total
of
10
000
cars
for
Europe
at
1
er
March
2015
.
In
order
to
maintain
his
fleet,
he
decides
to
resell,
at
1
er
March
each
year,
25
%
of
his
car
fleet
and
to
buy
3
000
new
cars.
The
number
of
cars
in
the
agency
is
modeled
using
a
sequence
:
For
any
natural
number
n
,
let
u
n
be
the
number
of
cars
in
the
fleet
as
at
1
er
March
of
year
2015+
n
.
So
we
have
:
u
0
=10
000
1
Expliquer
why
for
any
natural
number
n
:
u
n
+1
=
0.75
·
u
n
+
3000
2
Pour
any
natural
number
n
,
consider
the
sequence
v
n
defined
by:
v
n
=
u
n
−
12
000
a
Montrer
that
the
sequence
v
n
is
a
geometric
sequence
of
reason
0.75
.
Specify
its
first
term.
b
Express
v
n
as
a
function
of
n
.
Determine
the
limit
of
the
sequence
v
n
.
c
Justify
that,
for
any
natural
number
n
:
u
n
=
12
000
−
2
000
×
0.75
n
d
En
based
on
the
answers
given
to
the
two
previous
questions,
what
can
you
conjecture
about
the
number
of
cars
this
rental
company’s
fleet
will
have
after
a
large
number
of
years?
E.7025
A
website
offers
its
subscribers
movies
to
download.
Due
to
a
welcome
offer,
the
number
of
subscribers
at
launch
is
15
000
.
Based
on
the
first
few
months,
we
estimate
that
the
number
of
customers
subscribing
to
the
site
evolves
according
to
the
following
rule
:
each
month,
10
%
customers
unsubscribe
and
2
500
new
sub-scribers
are
registered.
We
note
v
n
the
estimated
number
of
subscribers
n
months
after
opening,
so
we
have
v
0
=15
000
.
1
Justify
that,
for
any
natural
number
n
,
we
have
:
v
n
+1
=
0.9
×
v
n
+
2
500
2
Consider
the
sequence
w
n
defined
for
any
natural
num-ber
n
by:
w
n
=
v
n
−
25
000
a
Show
that
the
sequence
w
n
is
geometric
of
reason
0.9
and
specify
its
first
term.
b
Deduce
that,
for
any
integer
n
:
v
n
=25
000
−
10
000
×
0.9
n
c
Can
this
model
be
used
to
predict
that
the
number
of
subscribers
will
stabilize
over
the
long
term?
Justify
the
answer.
E.7604
In
2015
,
forests
covered
approximately
4
000
million
hectares
of
land.
It
is
estimated
that
this
area
decreases
by
0.4
%
each
year.
This
loss
is
partly
offset
by
natural
or
voluntary
reforestation,
which
is
estimated
at
7.2
million
hectares
per
year.
Consider
the
sequence
u
n
defined
by
u
0
=4
000
and,
for
any
natural
number
n
:
u
n
+1
=
0.996
×
u
n
+
7.2
1
Justify
that,
for
any
natural
integer
n
,
u
n
provides
an
estimate
of
the
global
forest
area,
in
millions
of
hectares,
for
the
year
2015+
n
.
2
Copy
and
complete
the
algorithm
below
so
that,
at
the
end
of
its
execution,
the
variable
N
has
the
value
of
the
first
year
for
which
the
total
forest
area
covers
less
than
3
500
million
hectares
on
earth.
N
←
2015
U
←
4
000
...
...
...
3
Consider
the
sequence
v
n
defined
for
any
natural
num-ber
n
by:
v
n
=
u
n
−
1
800
a
Prove
that
the
sequence
v
n
is
geometric,
then
specify
its
first
term
and
its
ratio.
b
Deduce
that
for
any
natural
number
n
,
we
have
:
u
n
=
2200
×
0.996
n
+
1800
c
According
to
this
model,
if
the
phenomenon
continues,
will
the
Earth’s
forest
cover
eventually
disappear?
Jus-tify
your
answer.
6.
Weir
study
E.7211
Every
day,
an
association
prepares
and
delivers
meals
to
the
homes
of
dependent
people.
In
2015
,
600
people
subscribed
to
this
service.
To
study
its
development,
this
association
conducted
a
survey
according
to
which
the
evaluation
can
be
modeled
as
follows
:
Every
year,
5
%
subscriptions
are
not
renewed.
Each
year,
there
are
80
new
subscriptions
to
this
service.
This
evolution
can
be
studied
using
a
sequence
u
n
where
u
n
is
the
number
of
subscribers
during
the
year
2015+
n
.
We
thus
have,
u
0
=600
and
for
any
natural
number
n
:
u
n
+1
=0.95
·
u
n
+80
Admit
that
the
terms
of
the
sequence
u
n
admit
as
a
func-tion
of
rank
n
the
expression
:
u
n
=
1
600
−
1
000
×
0.95
n
The
size
of
the
premises
does
not
allow
us
to
serve
more
than
1
000
meals.
If
this
development
continues
at
the
same
rate,
will
the
asso-ciation
one
day
have
to
consider
expansion
work?
https://chingmath.fr
chapExoCorrec/7033
sacados/7033
chapExoCorrec/7025
sacados/7025
chapExoCorrec/7604
sacados/7604
chapExoCorrec/7211
sacados/7211
Extrait Antilles-Guyanes
Septembre 2016
E.7526
Let
u
n
be
defined
by
u
0
=150
and
for
any
natural
number
n
:
u
n
+1
=
0.8
·
u
n
+
45
1
Calculate
u
1
and
u
2
.
2
Here
are
two
proposed
algorithms
:
U
←
150
N
←
0
While
U
220
U
←
0.8
×
U+45
N
←
N+1
End
While
Algorithm
1
U
←
150
N
←
0
While
U<220
U
←
0.8
×
U+45
N
←
N+1
End
While
Algorithm
2
At
the
end
of
its
execution,
we
are
interested
in
the
value
of
the
variable
N
of
the
algorithm.
a
Only
one
of
these
algorithms
allows
the
variable
N
,
to
be
assigned,
at
the
end
of
execution,
the
smallest
nat-ural
number
n
such
that
u
n
220
.
Specify
which
one,
explaining
why
the
other
algorithm
does
not
allow
this.
b
What
is
the
value
of
the
variable
N
at
the
end
of
the
execution
of
this
algorithm?
E.7528
A
large
university,
experienc-ing
rapid
growth
in
enrollment,
welcomed
27
500
students
in
September
2016
.
The
university
president
is
concerned
because
he
knows
that,
despite
optimal
management
of
the
premises
and
distribution
of
students
across
the
university’s
various
sites,
he
will
not
be
able
to
accommodate
more
than
33
000
students.
A
statistical
study
allows
him
to
develop
a
forecast
model
according
to
which,
each
year:
150
students
drop
out
during
the
academic
year
(between
September
1
er
and
June
30
)
;
the
number
of
students
enrolled
at
the
start
of
the
aca-
demic
year
in
September
increases
by
4
%
compared
to
the
previous
month
of
June.
For
any
natural
number
n
,
we
note
u
n
the
number
of
stu-dents
estimated
according
to
this
model
at
the
start
of
the
academic
year
in
September
2016+
n
,
so
we
have
u
0
=27
500
.
1
a
Estimate
the
number
of
students
in
June
2017
.
b
Estimate
the
number
of
students
at
the
start
of
the
academic
year
in
September
2017
.
2
Justify
that,
for
any
natural
number
n
,
we
have
:
u
n
+1
=
1.04
·
u
n
−
156
3
Copy
and
complete
lines
3
,
4
,
5
,
and
7
of
the
following
algorithm
so
that,
at
the
end
of
its
execution,
the
vari-able
n
has
a
value
equal
to
the
year
in
which
the
number
of
students
to
be
admitted
will
exceed
the
maximum
ca-pacity
of
the
institution
‘
.1
n
←
0
‘
.2
U
←
27
500
‘
.3
As
long
as
U
...
‘
.4
n
←
...
‘
.5
U
←
...
‘
.6
End
While
‘
.7
U
←
U+
...
4
a
We
run
this
algorithm
step
by
step.
Copy
the
following
table
and
complete
it
by
adding
the
necessary
number
of
columns
;
round
the
values
of
U
to
the
nearest
whole
number.
Initialization
Step
1
.
.
.
Valeur
of
n
0
.
.
.
.
.
.
Valeur
of
U
27
500
.
.
.
.
.
.
b
Give
the
value
of
the
variable
n
at
the
end
of
the
exe-cution
of
this
algorithm.
7.
Solving
inequalities
(logarithm)
E.7013
Consider
the
sequence
u
n
de-fined
by:
u
0
=
75
;
u
n
+1
=
1.12
·
u
n
−
6
for
any
n
∈
N
We
pose
for
any
natural
number
n
:
v
n
=
u
n
−
50
1
Show
that
the
sequence
v
n
is
a
geometric
sequence.
Specify
its
reason
and
first
term.
2
Deduce
the
expression
of
v
n
as
a
function
of
n
,
then
show
that,
for
any
natural
number
n
,
we
have
:
u
n
05.12
n
+50
3
Solve
in
the
set
of
natural
numbers
the
inequation
:
u
n
>
100
.
E.7016
Consider
the
sequence
u
n
de-fined
by:
u
0
=4
;
u
n
+1
=
0.92
·
u
n
+
8
for
all
n
∈
N
For
any
natural
number,
we
set
:
v
n
=
u
n
−
100
1
Show
that
the
sequence
v
n
is
geometric
with
common
ratio
0.92
and
calculate
its
first
term
v
0
.
2
Give
the
expression
of
v
n
in
terms
of
n
.
3
Deduce
that,
for
any
natural
number
n
,
we
have
:
u
n
=
100
−
96
×
0.92
n
.
4
Solve
the
inequality:
u
n
70
8.
Reminders
Sum
of
the
terms
of
a
sequence
https://chingmath.fr
chapExoCorrec/7526
sacados/7526
chapExoCorrec/7528
sacados/7528
chapExoCorrec/7013
sacados/7013
Extrait de Liban
Mai 2016
chapExoCorrec/7016
sacados/7016
E.7261
For
each
question,
determine
the
exact
value
of
the
sum,
then,
if
necessary,
its
value
rounded
to
two
decimal
places
:
a
1+4+4
2
+
···
+4
6
b
1+0.2+0.2
2
+
···
+0.2
7
c
1+
1
6
+
1
6
2
+
···
+
1
6
10
d
1+1
1
+1
2
+
···
+1
10
E.7262
Determine,
for
each
question,
the
exact
value
of
the
sum,
then
its
value
rounded
to
the
hundredth
:
a
3
+
3
×
2
+
3
×
2
2
+
·
·
·
+
3
×
2
6
b
4
+
4
×
0.2
+
4
×
0.2
2
+
·
·
·
+
4
×
0.2
7
E.7004
Consider
the
geometric
sequence
with
first
term
1
and
reason
2
.
The
sum
of
the
first
13
terms
of
this
sequence
is
:
Which
of
the
3
answers
below
is
correct?
a
4095
b
8191
c
1
−
2
14
1
−
2
E.7046
Which
of
the
following
four
state-ments
is
true?
The
sum
S
=1+2+2
2
+2
3
+
···
+2
30
is
equal
to
:
a
−
1
+
2
31
b
1
−
2
31
c
−
1
+
2
30
d
1
−
2
30
E.7267
Among
the
four
statements
below,
only
one
is
correct.
Which
statement?
Justify
your
answer.
The
sequence
u
n
is
the
geometric
sequence
with
first
term
u
0
=
400
and
reason
1
2
.
The
sum
S
=
u
0
+
u
1
+
···
+
u
10
is
equal
to
:
a
2
×
1
−
0.5
10
b
2
×
1
−
0.5
11
c
800
×
1
−
0
;
5
10
d
800
×
1
−
0.5
11
9.
Threshold
study
E.7313
A
commune
opens
a
media
library
on
1
er
January
2013
,
the
media
library
has
a
stock
of
35
000
books
from
the
old
library,
increased
by
7
000
additional
new
books
donated
by
the
commune.
Each
year,
the
librarian
is
responsible
for
removing
5
%
books
that
are
too
old
or
damaged.
It
is
assumed
that
no
new
books
are
purchased
by
the
library.
We
call
u
n
the
number,
in
thousands,
of
books
available
on
1
er
January
of
the
year
(2013+
n
)
.
We
give
u
0
=42
.
1
a
Justify
that,
for
any
natural
number
n
,
we
have
:
u
n
+1
=0.95
×
u
n
b
Give
the
number
of
books
in
this
library
at
1
er
January
2018
.
2
A
natural
language
algorithm
is
proposed
below.
u
←
42
n
←
0
As
long
as
u>10
u
←
u
×
0;
95
n
←
n+1
End
As
long
as
a
After
running
the
algorithm,
what
does
the
value
of
the
variable
n
represent.
b
Using
your
calculator,
determine
the
value
of
the
vari-able
n
after
execution
of
the
algorithm.
E.7268
Among
the
four
statements
below,
only
one
is
correct.
Which
statement?
Justify
your
answer.
Consider
the
algorithm
below
:
n
←
0
U
←
50
As
long
as
U<120
U
←
1;
2
×
U
n
←
n+1
End
As
long
as
At
the
end
of
execution,
what
is
the
value
of
the
variable
n
:
a
4
b
124.416
c
5
d
96
E.7206
A
shopkeeper
who
has
just
opened
a
bou-tique
notices
that
his
sales
started
at
25
000
euros
per
month
and
increased
every
month
by
2
%
.
He
decides
to
model
the
progression
of
his
sales
by
the
follow-ing
u
n
where
u
0
represents
the
sales
of
the
first
month
of
opening.
1
Give
the
nature
and
characteristics
of
the
sequence
u
n
.
2
a
Using
the
calculator,
determine
after
how
many
months
his
sales
will
exceed
30
000
euros.
b
Complete
the
algorithm
so
that
the
value
of
the
vari-able
n
has
the
value,
at
the
end
of
its
execution,
of
the
number
of
months
after
opening
so
that
its
sales
will
exceed
30
000
euros
‘
.1
n
←
0
‘
.
2
U
←
25
000
‘
.3
As
long
as
.
..
make
‘
.4
n
←
...
‘
.5
U
←
...
‘
.6
End
As
long
as
10.
Sum
of
the
terms
of
a
geometric
sequence
https://chingmath.fr
chapExoCorrec/7261
sacados/7261
chapExoCorrec/7262
sacados/7262
chapExoCorrec/7004
sacados/7004
chapExoCorrec/7046
sacados/7046
Extrait Antilles-Guyane
Juin 2014
chapExoCorrec/7267
sacados/7267
Extrait Antilles-Guyannes
Juin 2016
chapExoCorrec/7313
sacados/7313
chapExoCorrec/7268
sacados/7268
Extrait Antilles-Guyannes
Juin 2016
chapExoCorrec/7206
sacados/7206
E.7263
On
1
er
January
2017
,
a
sports
as-sociation
had
900
members.
We
observe
that
each
month,
8
%
of
the
association’s
members
do
not
renew
their
membership.
1
Determine
the
number
of
members
on
March
1
er
2017
.
2
We
model
the
number
of
members
n
months
after
1
er
January
2017
thereafter
u
n
.
a
Give
the
nature
and
characteristic
elements
of
the
se-quence
u
n
.
b
Give
the
expression
of
the
term
u
n
according
to
its
rank
n
.
c
Determine
the
number
of
members,
rounded
to
the
nearest
whole
number,
on
1
er
January
2018
.
3
Each
member
pays
a
monthly
membership
fee
of
10
eu-ros.
The
association’s
treasurer
wants
to
calculate
the
total
amount
of
membership
fees
for
the
year
2017
.
The
treasurer
wants
to
use
the
following
algorithm,
in
which
the
fourth
line
is
incomplete
(dotted
line)
.
a
Copy
and
complete
the
algorithm
so
that,
at
the
end
of
its
execution,
the
variable
S
has
a
value
equal
to
the
total
amount
of
membership
fees
for
the
year
2017
.
S
←
0
U
←
900
For
N
ranging
from
1
to
12
S
←
...
U
←
0.92
·
U
End
For
b
What
is
the
total
amount
of
contributions
received
by
the
association
during
the
year
2017
?
The
amount
is
rounded
to
the
nearest
euro.
E.7271
Consider
the
following
algorithm:
Function
f(n)
u
←
2
000
S
←
2
000
For
i
ranging
from
2
to
n
u
←
u
×
1.008
S
←
S+u
End
for
We
execute
the
function
by
providing
it
with
the
argument
n
value
5
.
In
the
table
below,
summarize
the
values
assigned
to
the
vari-ables
of
the
function
f
during
its
call:
Value
of
i
2
Value
of
u
2
000
Value
of
S
2
000
E.7315
Without
justification,
give
the
value
con-tained
in
the
variable
S
after
execution
of
this
algorithm:
1
u
←
2
2
S
←
2
3
For
i
from
1
to
20
4
u
←
u
×
1;
05
5
S
←
S+u
.
6
End
for
E.7532
Consider
the
sequence
u
n
,
defined
for
any
natural
number
n
,
geometric
of
first
term
3
and
reason
2
.
Let
S
n
be
the
sum
of
the
(
n
+1)
first
terms
of
the
sequence
u
n
.
Establish
the
identity
below
for
any
natural
number
n
:
S
n
=
3
·
2
n
+1
−
1
11.
Geometric
sequences,
threshold
and
sum
E.7314
A
small
town
has
a
municipal
bike
rental
service.
The
municipality
wants
to
know
how
many
bikes
are
in
circulation
and
how
much
it
costs.
The
manager
of
the
bike
rental
service
notes
that
between
bikes
that
are
unusable
because
they
have
been
lost,
stolen,
or
damaged,
and
new
bikes
that
have
been
purchased,
the
number
of
usable
bikes
increases
by
5
%
each
year.
On
January
1
er
,
2017
,
the
fleet
contains
200
usable
bikes.
We
model
the
evolution
of
the
number
of
usable
bicycles
by
a
sequence
u
n
in
which,
for
any
natural
number
n
,
u
n
is
the
number
of
bicycles
on
January
1
er
of
year
2017+
n
.
Thus,
u
0
=200
and,
for
any
natural
number
n
:
u
n
+1
=
1.05
×
u
n
.
1
a
Justify
the
coefficient
1.05
in
the
expression
of
u
n
+1
as
a
function
of
u
n
.
b
How
many
bicycles
will
there
be
in
this
park
on
Jan-uary
1
er
2018
?
2
The
municipality
has
decided
to
stop
purchasing
new
bi-cycles
as
soon
as
its
stock
exceeds
500
units.
In
what
year
will
the
municipal
service’s
stock
exceed
500
bicycles
for
the
first
time?
3
To
help
maintain
the
rental
service,
the
municipality
has
obtained
a
grant
from
the
region
that
will
be
paid
from
2017
to
2032
inclusive
This
subsidy
amounts
to
10
euros
per
bicycle
available
for
rental.
Assuming
that
the
increase
in
the
number
of
bikes
re-mains
constant
at
5
%
each
year
during
this
period,
de-termine
the
total
amount
received
from
this
subsidy
from
January
1
er
to
January
2017
to
January
1
er
to
January
2032
.
Give
the
exact
value
and
the
value
rounded
to
two
deci-mal
places.
https://chingmath.fr
chapExoCorrec/7263
sacados/7263
chapExoCorrec/7271
sacados/7271
chapExoCorrec/7315
sacados/7315
chapExoCorrec/7532
sacados/7532
chapExoCorrec/7314
sacados/7314
S0Pournallantde0à24S×nFinPourAlgorithme1S0Pournallantde0à24S50×nFinPourAlgorithme2S50Pournallantde0à24S×nFinPourAlgorithme3
E.7264
Consider
the
geometric
sequence
u
n
,
with
common
ratio
0.9
and
first
term
u
0
=50
.
1
a
Copy
and
complete
the
algorithm
so
that,
at
the
end
of
its
execution,
the
variable
U
has
the
value
25
e
,
which
is
the
term
of
this
sequence,
i.e.,
u
24
:
U
←
...
For
N
ranging
from
1
to
24
U
←
...
End
For
b
For
any
natural
number
n
,
express
u
n
as
a
function
of
n
.
c
Calculate
u
24
and
give
an
approximate
value
of
the
result
to
10
−
3
near.
2
Using
a
calculator,
give
the
smallest
natural
number
n
such
that
:
u
n
<
0.01
.
3
We
want
to
calculate
the
sum
:
S
24
=
u
0
+
u
1
+
···
+
u
24
.
Here
are
three
proposed
algorithms
:
a
At
the
end
of
their
execution,
only
one
of
these
algo-rithms
will
have
its
variable
S
assigned
the
value
of
the
sum
u
24
.
Specify
which
one
and
justify
your
answer.
b
Calculate
the
sum
S
24
.
Give
an
approximate
value
for
the
result,
rounded
to
the
nearest
whole
number.
12.
Geometric
sequences:
limits
E.7293
1
Consider
the
geometric
sequence
u
n
with
first
term
1
and
common
ratio
2
.
a
Consider
the
code
:
Function
f(n)
u
←
1
For
i
ranging
from
1
to
n
u
←
2
×
u
End
For
Return
u
The
function
call
f(n)
returns
the
value
of
the
term
of
the
sequence
u
n
of
rank
n
to
the
program.
Complete
the
table
of
values
below
:
n
0
1
2
10
20
u
n
b
Complete
the
dotted
lines
:
lim
n
↦→
+
∞
u
n
=
:
:
:
2
a
Modify
the
function
f
displays
the
terms
of
the
se-quence
v
n
defined
by:
v
0
=
2
;
v
n
+1
=
0.8
×
v
n
b
Complete
the
table
of
values
rounded
to
the
nearest
thousandth
:
n
0
1
2
10
20
v
n
c
Complete
the
dotted
lines
:
lim
n
↦→
+
∞
v
n
=
:
:
:
3
Consider
the
geometric
sequence
w
n
with
first
term
50
and
common
ratio
0.8
.
Let
S
n
be
the
sum
of
the
n
+1
first
terms
of
the
sequence
w
n
:
S
n
=
w
0
+
w
1
+
·
·
·
+
w
n
a
Complete
the
dotted
lines
so
that
the
function
f(n)
returns
the
term
of
rank
n
of
the
sequence
S
n
:
Function
f(n)
u
←
50
S
←
50
For
i
ranging
from
1
to
n
u
←
...
S
←
S+...
End
for
Return
S
b
By
making
several
calls
to
the
function
f
,
conjecture
the
limit
of
the
sequence
S
n
c
Establish
that
:
S
n
=250
·
1
−
0.8
n
+1
d
Justify
the
conjecture
of
the
question
b
.
E.7205
A
website
offers
its
subscribers
movies
to
download.
When
it
opens,
500
films
are
offered
and
each
month
the
num-ber
of
films
offered
to
subscribers
increases
by
6
%
.
We
model
the
number
of
films
offered
by
a
geometric
sequence
u
n
where
n
denotes
the
number
of
months
since
the
site
opened.
We
therefore
have
:
u
0
=500
.
1
Calculate
u
1
and
u
2
and
give
the
result
rounded
to
unity.
2
Express
u
n
as
a
function
of
n
.
3
Determine
the
limit
of
the
sequence
u
n
.
E.7265
Consider
the
geometric
sequence
u
n
,
of
reason
0.9
and
first
term
u
0
=50
.
For
any
natural
number
n
,
note
S
n
=
u
0
+
u
1
+
···
+
u
n
.
We
admit
that
the
sequence
S
n
is
increasing
and
that
for
any
natural
number
n
:
S
n
=500
−
450
×
0.9
n
.
1
Determine
the
limit
of
the
sequence
S
n
when
n
tends
to
+
∞
.
2
Alex
assert
that
S
n
can
exceed
500
for
a
sufficiently
large
value
of
the
integer
n
.
What
do
you
think
of
his
assertion?
Justify
the
answer.
https://chingmath.fr
chapExoCorrec/7264
sacados/7264
S0Pournallantde0à24S×nFinPourAlgorithme1S0Pournallantde0à24S50×nFinPourAlgorithme2S50Pournallantde0à24S×nFinPourAlgorithme3
chapExoCorrec/7293
sacados/7293
chapExoCorrec/7205
sacados/7205
chapExoCorrec/7265
sacados/7265
E.7531
Consider
the
geometric
sequence
u
n
with
first
term
u
0
=50
and
reason
0.9
.
1
Determine
the
exact
value
of
the
term
u
24
and
give
an
approximate
value
of
the
result
to
within
10
−
3
.
2
For
any
natural
number
n
,
note
:
S
n
=
u
0
+
u
1
+
···
+
u
n
a
Determine
the
exact
value
of
the
sum
S
24
.
An
approx-imate
value
of
the
result
to
the
nearest
unit
will
be
given.
We
admit
that
the
sequence
S
n
is
increasing
and
that
for
any
natural
number
n
:
S
n
=
500
−
450
×
0.9
n
b
Determine
the
limit
of
the
sequence
S
n
when
n
tends
to
+
∞
.
c
Alex
asserts
that
S
n
can
exceed
500
for
a
sufficiently
large
value
of
the
integer
n
.
What
do
you
think
of
his
assertion?
Justify
the
an-swer.
13.
Geometric
sequences:
limits
and
thresholds
E.7292
Consider
the
sequence
u
n
defined
by:
u
0
=
0
;
u
n
+1
=
0.8
·
u
n
+
0.1
for
all
n
∈
N
∗
1
a
Enter
the
algorithm
below
:
u
←
0
For
i
ranging
from
1
to
n
u
←
8
×
u+
0.1
End
for
b
The
variable
n
having
value
10
,
what
do
the
different
values
of
the
variable
u
represent
during
the
execution
of
the
algorithm.
c
Running
the
algorithm
step
by
step,
what
conjecture
can
be
made
about
the
values
of
the
terms
in
the
se-quence
u
n
?
2
a
Enter
the
algorithm
below
:
u
←
0
n
←
0
As
long
as
u<0;
499
u
←
0.8
×
u+0.1
n
←
n+1
End
as
b
At
the
end
of
the
algorithm
execution,
what
does
the
value
of
the
variable
n
represent?
E.7269
Note
S
n
=
u
1
+
u
2
+
···
+
u
n
the
sum
of
the
first
n
terms
of
a
sequence
u
n
,
n
being
a
non-zero
natural
number.
We
admit
that
:
S
n
=
−
250
000
+
250
000
×
1.008
n
and
that
the
sequence
S
n
is
increasing.
1
Determine
the
limit
of
the
terms
of
the
sequence
S
n
when
n
tends
to
+
∞
.
2
Determine,
using
the
calculator,
from
which
rank
on-wards,
the
sequence
S
n
has
a
value
greater
than
125
000
.
14.
Unclassified
financial
years
E.6109
Consider
the
sequence
u
n
de-fined
by:
u
0
=
115
;
u
n
+1
=
0.4
·
u
n
+
120
for
all
n
∈
N
1
Consider
the
sequence
v
n
defined
for
any
natural
num-ber
n
by:
v
n
=
u
n
−
200
.
a
Show
that
v
n
is
a
geometric
sequence
of
reason
0.4
.
Specify
v
0
.
b
Express,
for
any
natural
number
n
,
v
n
as
a
function
of
n
.
2
Deduce
that
for
any
natural
number
n
:
u
n
=
200
−
85
×
0.4
n
3
Is
the
sequence
u
n
convergent?
Justify
your
answer.
E.5557
Consider
the
sequence
u
n
de-fined
by:
u
0
=
10
;
u
n
+1
=
0.9
u
n
+
1.2
for
all
n
∈
N
.
1
Give
the
exact
value
of
the
first
three
terms
of
the
se-quence
u
n
.
2
Consider
the
sequence
v
n
defined
by:
v
n
=
u
n
−
12
for
all
n
∈
N
.
Show
that
the
sequence
v
n
is
a
geometric
sequence
of
reason
0.9
and
of
first
term
−
2
.
3
a
Express,
for
any
natural
number
n
,
v
n
as
a
function
of
n
.
b
Express,
for
any
natural
number
n
,
u
n
as
a
function
of
n
.
c
Deduce
the
limit
of
the
sequence
u
n
.
https://chingmath.fr
chapExoCorrec/7531
sacados/7531
chapExoCorrec/7292
sacados/7292
chapExoCorrec/7269
sacados/7269
chapExoCorrec/6109
sacados/6109
chapExoCorrec/5557
sacados/5557
E.5563
The
production
of
Tahitian
cul-tured
pearls
is
an
important
economic
activity
for
French
Polynesia.
To
forecast
the
amounts
realized
from
the
export
of
Tahitian
pearls,
we
model
the
situation
by
a
sequence
u
n
.
We
note
u
0
the
amount
in
2011
,
in
millions
of
euros,
and
u
n
the
amount
in
2011+
n
,
in
millions
of
euros.
The
following
information
is
given
:
In
2011
,
the
gross
value
of
pearl
products
was
63
million
euros.
It
is
assumed
that
the
amount
of
exports
made
fell
every
year
by
8
%
.
1
Show
that
the
sequence
u
n
is
a
geometric
sequence
whose
reason
will
be
specified.
2
Express,
for
any
natural
number
n
,
u
n
as
a
function
of
n
.
3
With
this
model,
what
amount
can
we
forecast
for
the
export
of
pearl
products
from
French
Polynesia
in
2016
?
Round
the
result
to
the
nearest
million
euros.
E.5560
Consider
the
sequence
u
n
de-fined
by:
u
0
=
42
;
u
n
+1
=
0.95
·
u
n
+
4
for
everything
n
∈
N
1
Determine
the
exact
value
of
the
first
three
terms
of
the
sequence
u
n
2
Consider
the
sequence
w
n
defined
by:
v
n
=
u
n
−
80
for
all
n
∈
N
.
Show
that
v
n
is
a
geometric
sequence
of
reason
q
=0.95
and
of
first
term
−
38
.
3
a
Express,
for
any
natural
number
n
,
v
n
as
a
function
of
n
.
b
Express,
for
any
natural
number
n
,
u
n
as
a
function
of
n
.
c
Determine
the
limit
of
the
sequence
u
n
.
E.6095
Consider
the
sequence
a
n
defined
by:
a
0
=
8
;
a
n
+1
=
3
4
·
a
n
+
4
for
all
n
∈
N
1
For
any
natural
number
n
,
note
:
u
n
=
a
n
−
16
.
a
Show
that
the
sequence
u
n
is
a
geometric
sequence
of
reason
3
4
.
b
Express
u
n
in
terms
of
n
.
2
Express
a
n
as
a
function
of
n
.
What
can
we
say
about
the
convergence
of
the
sequence
a
n
?
E.3578
Two
companies,
Ultra-eau
(
U
)
and
Vital-eau
(
V
)
,
share
the
market
for
bottled
water
coolers
in
businesses
in
a
large
city.
In
2013
,
company
U
had
45
%
of
the
market
and
company
V
had
the
rest.
Each
year,
company
U
retains
90
%
of
its
customers,
while
the
others
choose
company
V
.
As
for
the
company
V
,
it
retains
85
%
of
its
customers,
while
the
others
choose
the
company
U
.
A
customer
is
chosen
at
random
each
year
and
the
following
is
noted
for
each
natural
number
n
:
u
n
the
probability
that
they
will
be
a
customer
of
the
company
U
in
the
year
2013+
n
,
thus
u
0
=0.45
;
v
n
the
probability
that
he
is
a
customer
of
the
company
V
in
the
year
2013+
n
.
1
Represent
the
situation
using
a
probabilistic
graph
with
vertices
U
and
V
.
2
Give
v
0
,
calculate
u
1
et
v
1
.
3
Consider
the
function
f
(incomplete)
,
extracted
from
an
algorithm,
given
below.
Called
with
a
non-zero
natural
integer
n
as
argument,
this
returns
the
pair
of
values
(
u
n
;
v
n
)
.
Complete
the
lines
(
‘
.3
)
and
(
‘
.6
)
of
the
function
to
ob-tain
the
expected
result.
‘
.1
Fonction
f(N)
‘
.2
U
←
0.45
‘
.3
V
←
...
‘
.
4
For
i
allowing
from
1
to
N
‘
.5
U
←
0.9
×
U+0.15
×
V
‘
.
6
V
←
...
‘
.7
Finish
For
‘
.8
Send
(
U
;
V)
4
We
admit
that,
for
any
natural
number
n
:
u
n
+1
=
0.75
·
u
n
+
0.15
.
We
note,
for
any
natural
number
n
:
w
n
=
u
n
−
0.6
a
Show
that
the
sequence
w
n
est
a
geometric
sequence
of
reason
0.75
.
b
What
is
the
limit
of
the
sequence
w
n
?
Deduce
the
limit
of
the
sequence
u
n
.
Interpret
the
result
in
the
context
of
this
exercise.
https://chingmath.fr
chapExoCorrec/5563
sacados/5563
chapExoCorrec/5560
sacados/5560
chapExoCorrec/6095
sacados/6095
chapExoCorrec/3578
sacados/3578