Grade 7 / Going further: algebra 6 exercises corrected

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1. Inverse operations E.11562 On each of the diagrams below, com-plete the missing information : 1 Complete the following diagrams : 2 Give the solutions to each of the following equations : a x + 3 = 5 b 2 × x = 8 c x − 5 = 3 d x + 3.2 = 5 e 6 × x = 9 f x ÷ 2 = 7.5 E.11569 L’exercice n’existe pas. 2. Equations with variables on one side E.11563 Note: For equation (2 × x )+1=7 , finding solutions is easy because, using the order of operations, you simply need to see how the expression on the left side is constructed to ob-tain the numerical value on the right side. The diagram below shows this solution : The solution to equation 2 × x +1=7 is the number 3 . Determine the solution to equation 7 × x +3=17 by complet-ing the diagram below : 3. Equations with variables on both sides E.11564 Determine, for each question, the value of x achieving equilibrium of the balance : a b c d E.11565 Method : To solve the equation : 7 × x + 4 = 2 × x + 14 We transform it step by step to arrive at the final step in the form ˇ x = : : : ‘’, which allows us to obtain the solution to this equation. Here is a suggested transformation in several steps to obtain the solution to the equation : Solve the following equations : a 5 × x + 7 = 3 × x + 13 b 2 × x + 1 = x + 8 c 9 × x + 6 = 5 × x + 14 d 4 × x + 1 = x + 10 4. Systems of equations: introduction to substitution https://chingmath.fr chapExoCorrec/11562 sacados/11562 ??5×2??8−5??3 ;2??5×6??9÷2??7;5 sacados/11569 chapExoCorrec/11563 sacados/11563 x2×x2×x1763×2÷2−1 x17 chapExoCorrec/11564 sacados/11564 4x33x5 5x12x10 8x24x14 3x2x6 chapExoCorrec/11565 sacados/11565 7×x42×x14−4−47×x2×x10−2×x−2×x5×x10÷5÷5x2
E.11566 We know the following relationships : We have the value : =. . . https://chingmath.fr sacados/11566 141018