Grade 7
/ Literal expressions: introduction 51 exercises (100% corrected)
- Problem situations (3 exercices)
- Introduction to literal expressions (4 exercices)
- Calculation Using an Expression (8 exercices)
- Generating Literal Expressions: Geometry (6 exercices)
- Literal Expression Evaluation: Computation Program (4 exercices)
- Literal Expression Generation: Pattern Recognition (2 exercices)
- Being a solution to an equation (10 exercices)
- Around equations (6 exercices)
- Around the equations (two side) (3 exercices)
- The Square: Calculating with an Expression (3 exercices)
- The square: being the solution to an equation (3 exercices)
01232468AbscisseOrdonnée
ABx12cm
DCx12cm
EF12cmx
Fig.1Fig.2Fig.3Fig.4Fig.5
b
What
do
you
notice?
c
Do
the
same
for
the
points
having
for
abscissa
the
val-ues
of
x
and
for
ordinate
the
corresponding
area.
3
Consider
the
expression
2
×
x
+4
.
For
each
value
assigned
to
x
,
give
the
value
of
the
expression
2
×
x
+4
when
you
change
x
by
its
value.
Complete
the
table
below
:
Value
of
x
1
1.5
2
2.5
3
Value
of
2
×
x
+4
E.1230
1
Consider
the
following
three
segments
:
We
vary
the
length
of
the
segments
of
length
x
.
Deter-
mine
some
values
of
the
segments
[
AB
]
,
[
CD
]
,
and
[
EF
]
as
a
function
of
the
value
of
x
by
completing
the
table
below
:
Value
of
x
0
1
2
10
AB
CD
EF
2
Connect
each
phrase
below
to
the
segment
with
the
cor-responding
length
:
a
12
−
x
b
3
×
x
+
12
c
2
×
(12
+
x
)
E.4647
We
consider
squares
made
of
small
squares
all
identical.
The
small
squares
surrounding
the
fig-ure
are
shaded.
Here
are
the
first
five
figures
constructed
in
this
way:
1
For
each
of
the
five
figures
above,
give
the
number
of
shaded
squares
making
up
the
figure.
2
Give
the
number
of
grayed-out
squares
composing
this
type
of
figure
when
the
side
of
such
a
figure
is
composed
of
10
small
squares.
3
Noting
n
the
number
of
small
squares
composing
the
side
of
such
a
figure,
give
a
formula
for
obtaining
the
number
of
small
shaded
squares
present
in
this
figure.
E.1813
Here
are
the
32
calculations
a
teacher
left
for
you
to
do
the
next
day
2
×
4
+
1
;
2
×
5
+
1
;
.
.
.
;
2
×
34
+
1
;
2
×
35
+
1
Find
the
simplest
statement
summarizing
this
exercise.
(We’ll
imagine
the
instruction
to
be
given
by
phone
to
a
class-mate
so
that
he
or
she
can
do
all
these
calculations.)
3.
Calculation
Using
an
Expression
E.1816
1
Find
the
value
of
the
following
expression
for
x
=1
:
A
=
x
×
2
+
3
+
x
×
x
2
Evaluate
the
following
expression
for
x
=2
:
B
=
(2
+
x
×
3)
×
x
E.564
Evaluate
the
following
expressions
for
x
=2
:
a
3
×
x
+
2
b
2
×
(3
−
x
)
−
1
c
(
x
+
2)
×
(5
−
x
)
E.1879
Evaluate
each
of
the
following
ex-pressions
for
x
=3
:
a
3
×
x
+
(
x
−
2)
×
(2
×
x
+
1)
b
(2
×
x
−
1)
×
2
+
3
E.10125
1
Evaluate
each
of
the
expressions
:
a
3
×
(2
×
x
+
1)
b
6
×
x
+
3
for
the
following
three
values
:
x
=0
;
x
=2
;
x
=10
2
Can
you
justify
the
equality
of
these
two
literal
expres-sions
in
each
of
these
three
cases?
E.10924
For
a
=4
and
b
=5
,
the
following
expressions
have
the
values
:
b
−
4
×
a
=
:
:
:
;
b
×
a
−
4
=
:
:
:
https://chingmath.fr
01232468AbscisseOrdonnée
chapExoCorrec/1230
sacados/1230
ABx12cm
DCx12cm
EF12cmx
chapExoCorrec/4647
sacados/4647
Fig.1Fig.2Fig.3Fig.4Fig.5
chapExoCorrec/1813
sacados/1813
chapExoCorrec/1816
sacados/1816
chapExoCorrec/564
sacados/564
chapExoCorrec/1879
sacados/1879
chapExoCorrec/10125
sacados/10125
chapExoCorrec/10924
sacados/10924
ABx7cm
DCx12cm
EFx2×x1cm1cm
ABx3cm
CDx100m
EF2kmx10km
GHIJ2cmxKLMNx2×x2cm
ABCD2×x3cmEFGHxx2cm
x2cmB3cmACDEF
E.10925
For
c
=2
,
d
=10
,
e
=14
,
the
follow-ing
expression
has
the
value
:
e
+
c
d
−
c
=
:
:
:
E.11703
Calculer
les
expressions
suivantes
pour
x
=3
:
a
3
×
x
−
5
b
x
−
1
×
2
×
x
+
4
E.11705
Calculer
les
expressions
suivantes
pour
x
=3
.
On
donnera
le
résultat
sous
la
forme
d’une
fraction
simplifiée
:
a
5
×
x
+
3
2
×
x
+
2
b
3
×
x
−
4
4
×
x
−
6
+
x
+
2
6
4.
Generating
Literal
Expressions:
Geometry
E.1233
1
For
x
worth
2
cm
,
give
the
length
of
segments
[
AB
]
,
[
CD
]
and
[
EF
]
.
2
Express
the
length
of
segments
[
AB
]
,
[
CD
]
and
[
EF
]
in
terms
of
ˇ
x
ı.
E.1229
The
resulting
literal
expressions
should
be
simplified
to
the
maximum.
Express,
in
each
case,
the
length
of
the
segments
[
AB
]
,
[
CD
]
,
and
[
EF
]
in
terms
of
ˇ
x
ı
:
a
b
c
E.10126
The
resulting
literal
expressions
must
fi
be
simplified
to
the
maximum.
1
Express
the
area
of
the
rectangle
GHIJ
and
the
perime-ter
of
KLMN
in
terms
of
x
.
2
For
x
=3
cm
,
calculate
the
area
of
the
rectangle
GHIJ
and
the
perimeter
of
KLMN
E.1228
Express
the
perimeter
and
area
of
the
rectangles
ABCD
and
EFGH
in
terms
of
x
.
E.1227
The
figure
shown
here
is
made
up
of
rectangles.
For
each
of
the
literal
expressions
below,
specify
whether
these
formulas
represent
a
length,
a
perimeter,
or
an
area:
1
For
each
question,
draw
a
rectangle
whose
area
is
ex-pressed
in
terms
of
x
:
a
3
×
2
b
3
×
x
c
(
x
+
2)
×
3
2
For
each
question,
draw
a
rectangle
whose
perimeter
is
expressed
in
terms
of
x
:
a
2
×
x
+
2
×
3
b
2
×
(
x
+
5)
c
2
×
(
x
+
3)
E.11701
1
For
x
worth
2
cm
,
give
the
length
of
segments
[
AB
]
,
[
CD
]
and
[
EF
]
.
2
Express
the
length
of
segments
[
AB
]
,
[
CD
]
and
[
EF
]
in
terms
of
ˇ
x
ı.
https://chingmath.fr
chapExoCorrec/10925
sacados/10925
chapExoCorrec/11703
sacados/11703
chapExoCorrec/11705
sacados/11705
chapExoCorrec/1233
sacados/1233
ABx7cm
DCx12cm
EFx2×x1cm1cm
chapExoCorrec/1229
sacados/1229
ABx3cm
CDx100m
EF2kmx10km
chapExoCorrec/10126
sacados/10126
GHIJ2cmxKLMNx2×x2cm
chapExoCorrec/1228
sacados/1228
ABCD2×x3cmEFGHxx2cm
chapExoCorrec/1227
sacados/1227
x2cmB3cmACDEF
chapExoCorrec/11701
sacados/11701
ABx7cm
DCx12cm
EFx2×x1cm1cm
Choisir un nombreMultiplier 3Ajouter2Soustraire 5Multiplier les deux nombres
Choisir un nombreAjouter 2Multiplier par4Multiplier par3Ajouter les deux nombres
Choisir un nombreCalculer son tripleCalculer son doubleAjouter2Multiplier les deux nombres obtenusSoustraire5
5.
Literal
Expression
Evaluation:
Computation
Program
E.11638
On
considère
le
programme
de
calcul
ci-dessous
:
1
Lorsque
la
valeur
d’entrée
est
2
,
quelle
est
la
valeur
de
sortie
de
ce
programme
de
calcul.
2
Lorsque
la
valeur
d’entrée
est
5
,
quelle
est
la
valeur
de
sortie
de
ce
programme
de
calcul.
E.11671
The
following
calculation
program
is
considered
:
1
Noting
x
the
number
chosen
as
the
input
to
this
compu-tational
program,
give
the
algebraic
expression
obtained
as
the
output
of
this
computational
program.
2
By
solving
an
equation,
determine
the
number
chosen
as
input
so
that
this
computation
program
returns
the
value
13
.
E.11672
The
figure
below
gives
a
schematic
of
a
calculation
program.
1
If
the
starting
number
is
1
,
show
that
the
result
is
−
15
.
2
If
we
choose
any
number
x
as
the
starting
number,
which
of
the
following
expressions
gives
the
result
obtained
by
the
calculation
program?
Justify.
A
=
x
2
−
5
×
3
x
+2
B
=(2
x
−
5)(3
x
+2)
C
=2
x
−
5
×
3
x
+2
3
Lily
claims
that
the
expression
:
D
=(3
x
+2)
2
−
(
x
+7)(3
x
+2)
gives
the
same
results
as
the
expression
B
for
all
values
of
x
.
Is
Lily’s
statement
true?
Justify.
E.11702
The
following
calculation
program
is
considered
:
1
Noting
x
the
number
chosen
as
the
input
to
this
compu-tational
program,
give
the
algebraic
expression
obtained
as
the
output
of
this
computational
program.
2
By
solving
an
equation,
determine
the
number
chosen
as
input
so
that
this
computation
program
returns
the
value
13
.
6.
Literal
Expression
Generation:
Pattern
Recognition
E.1231
For
each
of
the
two
cases
below
find
the
literal
expression
that
was
entered
into
the
calculator
to
obtain
the
following
table
:
1
Valeur
de
x
Résultat
affiché
4
16
5
20
6
24
7
28
2
Valeur
de
x
Résultat
affiché
3
7
4
9
5
11
6
13
E.1232
In
each
of
the
two
tables,
a
literal
expression
as
a
function
of
ˇ
x
ı
was
used
to
pass
in
each
row
from
the
column
ˇ
value
of
x
ı
to
the
column
ˇ
value
of
the
expression
ı.
1
Valeur
de
x
Valeur
de
l’expression
1
10
2
17
3
24
4
31
2
Valeur
de
x
Valeur
de
l’expression
0
2
1
3
2
6
10
102
https://chingmath.fr
chapExoCorrec/11638
sacados/11638
Choisir un nombreMultiplier 3Ajouter2Soustraire 5Multiplier les deux nombres
chapExoCorrec/11671
sacados/11671
Choisir un nombreAjouter 2Multiplier par4Multiplier par3Ajouter les deux nombres
chapExoCorrec/11672
sacados/11672
Choisir un nombreCalculer son tripleCalculer son doubleAjouter2Multiplier les deux nombres obtenusSoustraire5
chapExoCorrec/11702
sacados/11702
Choisir un nombreAjouter 2Multiplier par4Multiplier par3Ajouter les deux nombres
chapExoCorrec/1231
sacados/1231
chapExoCorrec/1232
sacados/1232
????
x2×x(2×x1763×2÷2−1
x17
x2×x(2×x−35×2−3÷2
7.
Being
a
solution
to
an
equation
E.1238
Check
if
the
numbers
1,
3
and
5
are
solutions
of
the
equation
:
3
x
−
3
=
2
x
+
2
E.10130
Check
if
the
numbers
1,
3
and
5
are
solutions
of
the
equation
:
4
x
−
3
=
3
x
+
2
E.1862
Definition:
An
equation
is
an
equality
that
contains
one
or
more
unknown
numbers,
represented
by
letters.
We
say
that’a
number
is
a
solution
d’to
an
equa-tion
if,
when
we
substitute
that
number
for
the
letter,
the’equality
becomes
true.
Check
whether
the
numbers
2
and
3
are
solutions
to
the
equa-tion
:
3
×
x
−
2
=
2
×
x
E.1878
Check
whether
the
numbers
1
and
3
are
solutions
of
the
equation
:
2
x
+
1
=
10
x
−
7
E.10127
Check
if
the
numbers
1,
3
and
5
are
solutions
of
the
equation
:
2(
x
+
1)
+
3
x
=
5
x
+
2
E.1831
Consider
the
equation
with
two
un-knowns
x
and
y
:
y
=
3
×
x
+
2
1
Find
the
value
of
y
for
the
following
values
of
x
:
a
x
=0
b
x
=1
c
x
=1
;
5
2
Find
the
value
of
x
that
satisfies
the
equation
for
the
following
values
of
y
:
a
y
=2
b
y
=8
c
y
=9
;
5
E.11707
L’équation
4
×
x
+2=18
admet
pour
so-lution
:
2
3
4
5
Indiquer
la
bonne
réponse
et
justifier
E.11708
L’équation
3
×
x
+1=2
×
x
+6
admet
pour
solution
:
4
2
5
3
Indiquer
la
bonne
réponse
et
justifier
8.
Around
equations
E.10919
Solve
the
following
equations
:
a
x
+
5
=
12
b
x
−
3
=
2
c
3
×
x
=
4.2
d
x
÷
5
=
1.2
Hint:
we
can
use
a
diagram
like
below
to
solve
these
equa-tions
:
E.10920
Note:
for
the
equation
(2
×
x
)+1=7
,
finding
the
solutions
is
easy,
as
all
you
need
to
do,
using
the
priorities
of
the
op-erations,
to
see
how
the
expression
of
the
left-hand
member
is
constructed
in
order
to
obtain
the
numerical
value
of
the
right-hand
member.
The
diagram
below
shows
this
resolution
:
The
solution
to
the
equation
(2
×
x
)+1=7
is
the
number
3
.
Determine
the
solution
to
the
equation
(7
×
x
)+3=17
by
com-pleting
the
diagram
below
:
E.11011
1
Complete
the
lower
part
of
the
following
diagram:
2
What
value
of
ˇ
x
ı
verifies
the
equality
below
:
(2
×
x
)
−
3
=
5
https://chingmath.fr
chapExoCorrec/1238
sacados/1238
chapExoCorrec/10130
sacados/10130
chapExoCorrec/1862
sacados/1862
chapExoCorrec/1878
sacados/1878
chapExoCorrec/10127
sacados/10127
chapExoCorrec/1831
sacados/1831
chapExoCorrec/11707
sacados/11707
chapExoCorrec/11708
sacados/11708
chapExoCorrec/10919
sacados/10919
????
chapExoCorrec/10920
sacados/10920
x2×x(2×x1763×2÷2−1
x17
chapExoCorrec/11011
sacados/11011
x2×x(2×x−35×2−3÷2
x
x41xx
x43x6x
4×x33×x5
5×x12×x10
8×x24×x14
3×x2x6
x212x
72x3x3
E.11033
Without
justification,
give
the
so-lutions
of
the
following
equations
:
a
(3
×
x
)
+
1
=
4
b
(5
×
x
)
−
4
=
6
c
(2
×
x
)
+
1
=
5
E.11074
Using
for
each
question
a
diagram
similar
to
the
one
above,
find
the
value
of
ˇ
x
ı
that
verifies
the
equality:
a
(3
×
x
)
−
2
=
7
b
(5
×
x
)
+
10
=
16
c
(3
×
x
)
+
1
=
5.5
d
2
×
(3
×
x
)
+
1
=
8
E.11704
En
justifiant
votre
démarche,
résoudre
les
équations
suivantes
:
a
4
×
x
+
7
=
18
b
5
×
x
−
1
=
1
Indication
:
on
pourra
utiliser
un
diagramme
ressemblant
à:
9.
Around
the
equations
(two
side)
E.11075
Without
justification
and
in
each
case,
give
the
value
of
x
allowing
the
balance
to
be
balanced
:
a
b
E.10921
For
each
question,
determine
the
value
of
x
that
balances
the
scale
:
a
b
c
d
E.11076
Without
justification
and
in
each
case,
give
the
value
of
x
allowing
the
balance
to
be
balanced
:
a
b
10.
The
Square:
Calculating
with
an
Expression
E.10922
1
Complete
the
following
dotted
lines
:
a
2
+
5
=
:
:
:
b
2
×
5
=
:
:
:
c
5
2
=
:
:
:
2
Complete
the
following
dotted
lines
:
a
2
+
6
=
:
:
:
b
2
×
6
=
:
:
:
c
6
2
=
:
:
:
E.10923
Complete
the
following
dotted
lines
:
a
10
2
=
:
:
:
b
2
2
=
:
:
:
c
7
2
=
:
:
:
d
0
2
=
:
:
:
e
3
2
=
:
:
:
f
5
2
=
:
:
:
E.10926
For
a
=4
,
b
=7
,
c
=3
,
the
following
expressions
have
the
values
:
a
2
−
b
2
−
4
−
c
2
=
:
:
:
;
b
2
−
a
2
−
c
2
=
:
:
:
11.
The
square:
being
the
solution
to
an
equation
E.10128
Check
whether
the
numbers
3
and
7
are
solutions
of
the
equation
:
x
2
−
3
x
+
16
=
7
x
−
5
E.10129
Check
if
the
numbers
1,
3
and
5
are
solutions
of
the
equation
:
x
2
+
1
=
2
x
E.10131
Check
whether
the
numbers
1
and
4
are
solutions
of
the
equation
:
x
2
+
3
=
5
x
−
1
https://chingmath.fr
chapExoCorrec/11033
sacados/11033
chapExoCorrec/11074
sacados/11074
chapExoCorrec/11704
sacados/11704
x
chapExoCorrec/11075
sacados/11075
x41xx
x43x6x
chapExoCorrec/10921
sacados/10921
4×x33×x5
5×x12×x10
8×x24×x14
3×x2x6
chapExoCorrec/11076
sacados/11076
x212x
72x3x3
chapExoCorrec/10922
sacados/10922
chapExoCorrec/10923
sacados/10923
chapExoCorrec/10926
sacados/10926
chapExoCorrec/10128
sacados/10128
chapExoCorrec/10129
sacados/10129
chapExoCorrec/10131
sacados/10131
Étape 1Étape 2Étape 3
12.
Unclassified
exercises
E.11706
Voici
les
premières
étapes
d’un
motif
répétitif:
1
Combien
de
carreaux
est
composée
la
figure
à
l’étape
4?
2
Pour
n
un
entier
supérieur
ou
égal
à
1
,
exprimer
le
nom-bre
de
carreaux
nécessaires
en
fonction
de
n
.
https://chingmath.fr
chapExoCorrec/11706
sacados/11706
Étape 1Étape 2Étape 3