Grade 7
/ Literal expressions: introduction 51 exercises corrected
- Problem situations (3 exercices)
- Introduction to literal expressions (4 exercices)
- Calculation Using an Expression (8 exercices)
- Generating Literal Expressions: Geometry (6 exercices)
- Literal Expression Evaluation: Computation Program (4 exercices)
- Literal Expression Generation: Pattern Recognition (2 exercices)
- Being a solution to an equation (10 exercices)
- Around equations (6 exercices)
- Around the equations (two side) (3 exercices)
- The Square: Calculating with an Expression (3 exercices)
- The square: being the solution to an equation (3 exercices)
b
What
do
you
notice?
c
Do
the
same
for
the
points
having
for
abscissa
the
val-ues
of
x
and
for
ordinate
the
corresponding
area.
3
Consider
the
expression
2
×
x
+4
.
For
each
value
assigned
to
x
,
give
the
value
of
the
expression
2
×
x
+4
when
you
change
x
by
its
value.
Complete
the
table
below
:
Value
of
x
1
1.5
2
2.5
3
Value
of
2
×
x
+4
E.1230
1
Consider
the
following
three
segments
:
We
vary
the
length
of
the
segments
of
length
x
.
Deter-
mine
some
values
of
the
segments
[
AB
]
,
[
CD
]
,
and
[
EF
]
as
a
function
of
the
value
of
x
by
completing
the
table
below
:
Value
of
x
0
1
2
10
AB
CD
EF
2
Connect
each
phrase
below
to
the
segment
with
the
cor-responding
length
:
a
12
−
x
b
3
×
x
+
12
c
2
×
(12
+
x
)
E.4647
We
consider
squares
made
of
small
squares
all
identical.
The
small
squares
surrounding
the
fig-ure
are
shaded.
Here
are
the
first
five
figures
constructed
in
this
way:
1
For
each
of
the
five
figures
above,
give
the
number
of
shaded
squares
making
up
the
figure.
2
Give
the
number
of
grayed-out
squares
composing
this
type
of
figure
when
the
side
of
such
a
figure
is
composed
of
10
small
squares.
3
Noting
n
the
number
of
small
squares
composing
the
side
of
such
a
figure,
give
a
formula
for
obtaining
the
number
of
small
shaded
squares
present
in
this
figure.
E.1813
Here
are
the
32
calculations
a
teacher
left
for
you
to
do
the
next
day
2
×
4
+
1
;
2
×
5
+
1
;
.
.
.
;
2
×
34
+
1
;
2
×
35
+
1
Find
the
simplest
statement
summarizing
this
exercise.
(We’ll
imagine
the
instruction
to
be
given
by
phone
to
a
class-mate
so
that
he
or
she
can
do
all
these
calculations.)
3.
Calculation
Using
an
Expression
E.1816
1
Find
the
value
of
the
following
expression
for
x
=1
:
A
=
x
×
2
+
3
+
x
×
x
2
Evaluate
the
following
expression
for
x
=2
:
B
=
(2
+
x
×
3)
×
x
E.564
Evaluate
the
following
expressions
for
x
=2
:
a
3
×
x
+
2
b
2
×
(3
−
x
)
−
1
c
(
x
+
2)
×
(5
−
x
)
E.1879
Evaluate
each
of
the
following
ex-pressions
for
x
=3
:
a
3
×
x
+
(
x
−
2)
×
(2
×
x
+
1)
b
(2
×
x
−
1)
×
2
+
3
E.10125
1
Evaluate
each
of
the
expressions
:
a
3
×
(2
×
x
+
1)
b
6
×
x
+
3
for
the
following
three
values
:
x
=0
;
x
=2
;
x
=10
2
Can
you
justify
the
equality
of
these
two
literal
expres-sions
in
each
of
these
three
cases?
E.10924
For
a
=4
and
b
=5
,
the
following
expressions
have
the
values
:
b
−
4
×
a
=
:
:
:
;
b
×
a
−
4
=
:
:
:
https://chingmath.fr
01232468AbscisseOrdonnée
chapExoCorrec/1230
sacados/1230
ABx12cm
DCx12cm
EF12cmx
chapExoCorrec/4647
sacados/4647
Fig.1Fig.2Fig.3Fig.4Fig.5
chapExoCorrec/1813
sacados/1813
chapExoCorrec/1816
sacados/1816
chapExoCorrec/564
sacados/564
chapExoCorrec/1879
sacados/1879
chapExoCorrec/10125
sacados/10125
chapExoCorrec/10924
sacados/10924
E.10925
For
c
=2
,
d
=10
,
e
=14
,
the
follow-ing
expression
has
the
value
:
e
+
c
d
−
c
=
:
:
:
E.11703
Calculer
les
expressions
suivantes
pour
x
=3
:
a
3
×
x
−
5
b
x
−
1
×
2
×
x
+
4
E.11705
Calculer
les
expressions
suivantes
pour
x
=3
.
On
donnera
le
résultat
sous
la
forme
d’une
fraction
simplifiée
:
a
5
×
x
+
3
2
×
x
+
2
b
3
×
x
−
4
4
×
x
−
6
+
x
+
2
6
4.
Generating
Literal
Expressions:
Geometry
E.1233
1
For
x
worth
2
cm
,
give
the
length
of
segments
[
AB
]
,
[
CD
]
and
[
EF
]
.
2
Express
the
length
of
segments
[
AB
]
,
[
CD
]
and
[
EF
]
in
terms
of
ˇ
x
ı.
E.1229
The
resulting
literal
expressions
should
be
simplified
to
the
maximum.
Express,
in
each
case,
the
length
of
the
segments
[
AB
]
,
[
CD
]
,
and
[
EF
]
in
terms
of
ˇ
x
ı
:
a
b
c
E.10126
The
resulting
literal
expressions
must
fi
be
simplified
to
the
maximum.
1
Express
the
area
of
the
rectangle
GHIJ
and
the
perime-ter
of
KLMN
in
terms
of
x
.
2
For
x
=3
cm
,
calculate
the
area
of
the
rectangle
GHIJ
and
the
perimeter
of
KLMN
E.1228
Express
the
perimeter
and
area
of
the
rectangles
ABCD
and
EFGH
in
terms
of
x
.
E.1227
The
figure
shown
here
is
made
up
of
rectangles.
For
each
of
the
literal
expressions
below,
specify
whether
these
formulas
represent
a
length,
a
perimeter,
or
an
area:
1
For
each
question,
draw
a
rectangle
whose
area
is
ex-pressed
in
terms
of
x
:
a
3
×
2
b
3
×
x
c
(
x
+
2)
×
3
2
For
each
question,
draw
a
rectangle
whose
perimeter
is
expressed
in
terms
of
x
:
a
2
×
x
+
2
×
3
b
2
×
(
x
+
5)
c
2
×
(
x
+
3)
E.11701
1
For
x
worth
2
cm
,
give
the
length
of
segments
[
AB
]
,
[
CD
]
and
[
EF
]
.
2
Express
the
length
of
segments
[
AB
]
,
[
CD
]
and
[
EF
]
in
terms
of
ˇ
x
ı.
https://chingmath.fr
chapExoCorrec/10925
sacados/10925
chapExoCorrec/11703
sacados/11703
chapExoCorrec/11705
sacados/11705
chapExoCorrec/1233
sacados/1233
ABx7cm
DCx12cm
EFx2×x1cm1cm
chapExoCorrec/1229
sacados/1229
ABx3cm
CDx100m
EF2kmx10km
chapExoCorrec/10126
sacados/10126
GHIJ2cmxKLMNx2×x2cm
chapExoCorrec/1228
sacados/1228
ABCD2×x3cmEFGHxx2cm
chapExoCorrec/1227
sacados/1227
x2cmB3cmACDEF
chapExoCorrec/11701
sacados/11701
ABx7cm
DCx12cm
EFx2×x1cm1cm
5.
Literal
Expression
Evaluation:
Computation
Program
E.11638
On
considère
le
programme
de
calcul
ci-dessous
:
1
Lorsque
la
valeur
d’entrée
est
2
,
quelle
est
la
valeur
de
sortie
de
ce
programme
de
calcul.
2
Lorsque
la
valeur
d’entrée
est
5
,
quelle
est
la
valeur
de
sortie
de
ce
programme
de
calcul.
E.11671
The
following
calculation
program
is
considered
:
1
Noting
x
the
number
chosen
as
the
input
to
this
compu-tational
program,
give
the
algebraic
expression
obtained
as
the
output
of
this
computational
program.
2
By
solving
an
equation,
determine
the
number
chosen
as
input
so
that
this
computation
program
returns
the
value
13
.
E.11672
The
figure
below
gives
a
schematic
of
a
calculation
program.
1
If
the
starting
number
is
1
,
show
that
the
result
is
−
15
.
2
If
we
choose
any
number
x
as
the
starting
number,
which
of
the
following
expressions
gives
the
result
obtained
by
the
calculation
program?
Justify.
A
=
x
2
−
5
×
3
x
+2
B
=(2
x
−
5)(3
x
+2)
C
=2
x
−
5
×
3
x
+2
3
Lily
claims
that
the
expression
:
D
=(3
x
+2)
2
−
(
x
+7)(3
x
+2)
gives
the
same
results
as
the
expression
B
for
all
values
of
x
.
Is
Lily’s
statement
true?
Justify.
E.11702
The
following
calculation
program
is
considered
:
1
Noting
x
the
number
chosen
as
the
input
to
this
compu-tational
program,
give
the
algebraic
expression
obtained
as
the
output
of
this
computational
program.
2
By
solving
an
equation,
determine
the
number
chosen
as
input
so
that
this
computation
program
returns
the
value
13
.
6.
Literal
Expression
Generation:
Pattern
Recognition
E.1231
For
each
of
the
two
cases
below
find
the
literal
expression
that
was
entered
into
the
calculator
to
obtain
the
following
table
:
1
Valeur
de
x
Résultat
affiché
4
16
5
20
6
24
7
28
2
Valeur
de
x
Résultat
affiché
3
7
4
9
5
11
6
13
E.1232
In
each
of
the
two
tables,
a
literal
expression
as
a
function
of
ˇ
x
ı
was
used
to
pass
in
each
row
from
the
column
ˇ
value
of
x
ı
to
the
column
ˇ
value
of
the
expression
ı.
1
Valeur
de
x
Valeur
de
l’expression
1
10
2
17
3
24
4
31
2
Valeur
de
x
Valeur
de
l’expression
0
2
1
3
2
6
10
102
https://chingmath.fr
chapExoCorrec/11638
sacados/11638
Choisir un nombreMultiplier 3Ajouter2Soustraire 5Multiplier les deux nombres
chapExoCorrec/11671
sacados/11671
Choisir un nombreAjouter 2Multiplier par4Multiplier par3Ajouter les deux nombres
chapExoCorrec/11672
sacados/11672
Choisir un nombreCalculer son tripleCalculer son doubleAjouter2Multiplier les deux nombres obtenusSoustraire5
chapExoCorrec/11702
sacados/11702
Choisir un nombreAjouter 2Multiplier par4Multiplier par3Ajouter les deux nombres
chapExoCorrec/1231
sacados/1231
chapExoCorrec/1232
sacados/1232
7.
Being
a
solution
to
an
equation
E.1238
Check
if
the
numbers
1,
3
and
5
are
solutions
of
the
equation
:
3
x
−
3
=
2
x
+
2
E.10130
Check
if
the
numbers
1,
3
and
5
are
solutions
of
the
equation
:
4
x
−
3
=
3
x
+
2
E.1862
Definition:
An
equation
is
an
equality
that
contains
one
or
more
unknown
numbers,
represented
by
letters.
We
say
that’a
number
is
a
solution
d’to
an
equa-tion
if,
when
we
substitute
that
number
for
the
letter,
the’equality
becomes
true.
Check
whether
the
numbers
2
and
3
are
solutions
to
the
equa-tion
:
3
×
x
−
2
=
2
×
x
E.1878
Check
whether
the
numbers
1
and
3
are
solutions
of
the
equation
:
2
x
+
1
=
10
x
−
7
E.10127
Check
if
the
numbers
1,
3
and
5
are
solutions
of
the
equation
:
2(
x
+
1)
+
3
x
=
5
x
+
2
E.1831
Consider
the
equation
with
two
un-knowns
x
and
y
:
y
=
3
×
x
+
2
1
Find
the
value
of
y
for
the
following
values
of
x
:
a
x
=0
b
x
=1
c
x
=1
;
5
2
Find
the
value
of
x
that
satisfies
the
equation
for
the
following
values
of
y
:
a
y
=2
b
y
=8
c
y
=9
;
5
E.10928
The
literal
expressions
obtained
must
be
simplified
as
much
as
possible.
1
Express
the
area
of
the
rectangle
GHIJ
and
the
perime-ter
of
KLMN
in
terms
of
x
.
2
For
x
=3
cm
,
calculate
the
area
of
rectangle
GHIJ
and
the
perimeter
of
KLMN
.
Do
an
exercise
with
2
×
x
+
2
×
2
×
x
+
2
×
2
6
x
+
4
E.10929
1
For
x
equal
to
2
cm
,
give
the
lengths
of
segments
[
AB
]
,
[
CD
]
,
and
[
EF
]
.
2
Express
the
lengths
of
segments
[
AB
]
,
[
CD
]
,
and
[
EF
]
in
terms
of
ˇ
x
‘’.
x
=
1
2
×
:
:
:
+
7
x
=
2
2
×
:
:
:
+
7
x
=
3
:
:
:
x
=
4
ldots
x
=
x
ldots
E.11707
L’équation
4
×
x
+2=18
admet
pour
so-lution
:
2
3
4
5
Indiquer
la
bonne
réponse
et
justifier
E.11708
L’équation
3
×
x
+1=2
×
x
+6
admet
pour
solution
:
4
2
5
3
Indiquer
la
bonne
réponse
et
justifier
8.
Around
equations
E.10919
Solve
the
following
equations
:
a
x
+
5
=
12
b
x
−
3
=
2
c
3
×
x
=
4.2
d
x
÷
5
=
1.2
https://chingmath.fr
chapExoCorrec/1238
sacados/1238
chapExoCorrec/10130
sacados/10130
chapExoCorrec/1862
sacados/1862
chapExoCorrec/1878
sacados/1878
chapExoCorrec/10127
sacados/10127
chapExoCorrec/1831
sacados/1831
chapExoCorrec/10928
sacados/10928
GHIJ2cmxKLMNx2×x2cm
chapExoCorrec/10929
sacados/10929
ABx7cm
DCx12cm
EFx2×x1cm1cm
chapExoCorrec/11707
sacados/11707
chapExoCorrec/11708
sacados/11708
chapExoCorrec/10919
sacados/10919
Hint:
we
can
use
a
diagram
like
below
to
solve
these
equa-tions
:
E.10920
Note:
for
the
equation
(2
×
x
)+1=7
,
finding
the
solutions
is
easy,
as
all
you
need
to
do,
using
the
priorities
of
the
op-erations,
to
see
how
the
expression
of
the
left-hand
member
is
constructed
in
order
to
obtain
the
numerical
value
of
the
right-hand
member.
The
diagram
below
shows
this
resolution
:
The
solution
to
the
equation
(2
×
x
)+1=7
is
the
number
3
.
Determine
the
solution
to
the
equation
(7
×
x
)+3=17
by
com-pleting
the
diagram
below
:
E.11011
1
Complete
the
lower
part
of
the
following
diagram:
2
What
value
of
ˇ
x
ı
verifies
the
equality
below
:
(2
×
x
)
−
3
=
5
E.11033
Without
justification,
give
the
so-lutions
of
the
following
equations
:
a
(3
×
x
)
+
1
=
4
b
(5
×
x
)
−
4
=
6
c
(2
×
x
)
+
1
=
5
E.11074
Using
for
each
question
a
diagram
similar
to
the
one
above,
find
the
value
of
ˇ
x
ı
that
verifies
the
equality:
a
(3
×
x
)
−
2
=
7
b
(5
×
x
)
+
10
=
16
c
(3
×
x
)
+
1
=
5.5
d
2
×
(3
×
x
)
+
1
=
8
E.11704
En
justifiant
votre
démarche,
résoudre
les
équations
suivantes
:
a
4
×
x
+
7
=
18
b
5
×
x
−
1
=
1
Indication
:
on
pourra
utiliser
un
diagramme
ressemblant
à:
9.
Around
the
equations
(two
side)
E.11075
Without
justification
and
in
each
case,
give
the
value
of
x
allowing
the
balance
to
be
balanced
:
a
b
E.10921
For
each
question,
determine
the
value
of
x
that
balances
the
scale
:
a
b
c
d
E.11076
Without
justification
and
in
each
case,
give
the
value
of
x
allowing
the
balance
to
be
balanced
:
a
b
10.
The
Square:
Calculating
with
an
Expression
E.10922
1
Complete
the
following
dotted
lines
:
a
2
+
5
=
:
:
:
b
2
×
5
=
:
:
:
c
5
2
=
:
:
:
https://chingmath.fr
????
chapExoCorrec/10920
sacados/10920
x2×x(2×x1763×2÷2−1
x17
chapExoCorrec/11011
sacados/11011
x2×x(2×x−35×2−3÷2
chapExoCorrec/11033
sacados/11033
chapExoCorrec/11074
sacados/11074
chapExoCorrec/11704
sacados/11704
x
chapExoCorrec/11075
sacados/11075
x41xx
x43x6x
chapExoCorrec/10921
sacados/10921
4×x33×x5
5×x12×x10
8×x24×x14
3×x2x6
chapExoCorrec/11076
sacados/11076
x212x
72x3x3
chapExoCorrec/10922
sacados/10922
2
Complete
the
following
dotted
lines
:
a
2
+
6
=
:
:
:
b
2
×
6
=
:
:
:
c
6
2
=
:
:
:
E.10923
Complete
the
following
dotted
lines
:
a
10
2
=
:
:
:
b
2
2
=
:
:
:
c
7
2
=
:
:
:
d
0
2
=
:
:
:
e
3
2
=
:
:
:
f
5
2
=
:
:
:
E.10926
For
a
=4
,
b
=7
,
c
=3
,
the
following
expressions
have
the
values
:
a
2
−
b
2
−
4
−
c
2
=
:
:
:
;
b
2
−
a
2
−
c
2
=
:
:
:
11.
The
square:
being
the
solution
to
an
equation
E.10128
Check
whether
the
numbers
3
and
7
are
solutions
of
the
equation
:
x
2
−
3
x
+
16
=
7
x
−
5
E.10129
Check
if
the
numbers
1,
3
and
5
are
solutions
of
the
equation
:
x
2
+
1
=
2
x
E.10131
Check
whether
the
numbers
1
and
4
are
solutions
of
the
equation
:
x
2
+
3
=
5
x
−
1
12.
Unclassified
exercises
E.11706
Voici
les
premières
étapes
d’un
motif
répétitif:
1
Combien
de
carreaux
est
composée
la
figure
à
l’étape
4?
2
Pour
n
un
entier
supérieur
ou
égal
à
1
,
exprimer
le
nom-bre
de
carreaux
nécessaires
en
fonction
de
n
.
https://chingmath.fr
chapExoCorrec/10923
sacados/10923
chapExoCorrec/10926
sacados/10926
chapExoCorrec/10128
sacados/10128
chapExoCorrec/10129
sacados/10129
chapExoCorrec/10131
sacados/10131
chapExoCorrec/11706
sacados/11706
Étape 1Étape 2Étape 3