Grade 8
/ Cosinus 28 exercises corrected
- Reminders on angles (3 exercices)
- Introduction (6 exercices)
- Use of the cosine: search for the adjacent side (3 exercices)
- Use of the cosine: search for the hypothenuse (2 exercices)
- Use of the cosine (3 exercices)
- Use of the reciprocal cosine (3 exercices)
- Use of cosine and inverse cosine (4 exercices)
- Cosine, Pythagorean theorem and Thales theorem (3 exercices)
E.4917
We
consider
the
four
triangles
shown
below
are
right-angled
and
have
an
angle
of
25
o
.
1
Using
the
measurements
in
the
figure
above,
complete
the
table
below,
rounding
the
lengths
to
the
nearest
mil-limeter:
Triangle
1
2
3
4
Hypoténuse
Side
adjacent
à
the
corner
of
25
o
2
Using
the
calculator,
give
the
values
of
the
quotients
re-quested
rounded
to
the
nearest
hundredth
:
Triangle
1
2
3
4
Longueur
from
the
side
adjacent
to
the
corner
of
25
o
Longueur
de
l’hypoténuse
E.9029
Definition-proposition:
In
a
right-angled
triangle,
for
an
acute
angle
¸
of
this
triangle,
we
define
the
cosine
of
the
angle
α
by
the
value
of
the
quotient
:
Longueur
of
the
side
adjacent
to
the
angle
¸
Longueur
of
the
hypohtenuse
The
value
of
this
quotient
does
not
depend
on
the
dimen-sions
of
the
right-angled
triangle,
but
only
on
the
measure
¸
of
the
angle:
it
is
noted
cos(
α
)
Example
1:
Consider
the
triangle
ABC
shown
below
où
the
point
H
is
the
foot
of
the
height
arising
from
the
point
C
.
1
In
the
triangle
ABC
,
give
as
a
function
of
the
lengths
of
the
segments,
an
expression
of
the
trigonometric
ratios
:
a
cos
∠
BAC
b
cos
∠
ABC
2
a
In
the
triangle
ACH
,
give
an
expression
for
cos
∠
CAH
b
In
triangle
BCH
,
give
an
expression
of
cos
∠
CBH
https://chingmath.fr
chapExoCorrec/4917
sacados/4917
A1B1C125oA2B2C225oA3B3C325oA4B4C425o
chapExoCorrec/9029
sacados/9029
ABChypothénusecos¸ACAB¸ABChypothénusecos˛BCAB˛
ABCH
E.6439
Example:
(angles
have
been
rounded
to
the
nearest
degree)
Consider
the
two
triangles
ABC
and
DEF
below
:
Give
the
following
values
rounded
to
the
nearest
hundredth
:
a
cos
28
b
cos
64
Hint:
cosine
values
for
all
angles
from
1
o
to
89
o
are
all
known
and
available
on
a
table
or
using
the
calculator:
E.3579
Consider
the
triangle
AMN
right-angled
M
;
the
points
B
and
C
belong
to
the
segments
[
BC
]
and
[
MN
]
respectively;
the
line
(
BC
)
is
perpendicular
to
the
line
(
AM
)
:
1
Using
a
graduated
ruler,
give
an
approximate
value
for
the
side
measures
of
the
two
triangles
ABC
and
AMN
.
2
Using
a
calculator,
compare
the
approximate
values
of
the
following
two
quotients
:
BC
AC
;
MN
AM
3
a
Justify
that
the
lines
(
BC
)
and
(
MN
)
are
parallel.
b
Justify
the
equality
of
the
following
two
quotients
:
BC
MN
=
AC
AN
c
Derive
the
following
equality:
BC
AC
=
MN
AN
d
Compare
this
equality
with
your
results
from
question
1
.
Was
there
an
error
in
your
calculations?
Where
d
the
error
come
from?
4
Using
measurements
and
approximate
values,
compare
the
pairs
of
quotients
below
:
a
AB
AC
;
AM
AN
b
BC
AC
;
MN
AM
E.1154
Let
ABC
4
be
a
right-angled
trian-gle
at
B
.
The
angle
C
4
AB
measures
40
o
,
it
is
divided
into
four
angles
of
the
same
measure
using
the
points
C
1
,
C
2
,
C
3
belonging
to
the
segment
BC
4
1
Using
your
graduated
ruler,
we’ll
give
the
measurements
of
the
lengths
rounded
to
the
nearest
millimetre.
The
quotients
in
the
last
column
will
be
rounded
to
the
near-est
hundredth
:
i
BAC
i
AC
i
AB
AC
i
1
2
3
4
2
Complete
the
following
table
using
the
cos
key
on
your
calculator.
The
values
are
rounded
to
the
nearest
thou-sandth
:
¸
10
o
20
o
30
o
40
o
cos(
¸
)
3.
Use
of
the
cosine:
search
for
the
adjacent
side
E.4919
Consider
the
four
triangles
shown
below
:
https://chingmath.fr
chapExoCorrec/6439
sacados/6439
ABC4;9cm6;7cmDEF14km43km43o71o4;96;70;73114430;326
6km3,2km6,8kmABC28o8mm3,9mm8,9mmDEF26o
chapExoCorrec/3579
sacados/3579
ABCMN
chapExoCorrec/1154
sacados/1154
C110oC2C3C4AB
chapExoCorrec/4919
sacados/4919
ABC5cm25oGIH3cm35o
Determine
the
lengths
of
the
following
segments.
Round
your
answers
to
the
nearest
millimeter:
a
[
AC
]
b
[
GH
]
Hints:
Below
is
part
of
the
trigonometric
table
for
cosine.
¸
o
cos
¸
o
¸
o
cos
¸
o
¸
o
cos
¸
¸
o
cos
¸
o
¸
o
cos
¸
o
0
o
1
20
o
0
;
94
40
o
0
;
766
60
o
0
;
5
80
o
0
;
174
5
o
0
;
996
25
o
0
;
906
45
o
0
;
707
65
o
0
;
423
85
o
0
;
087
10
o
0
;
985
30
o
0
;
866
50
o
0
;
643
70
o
0
;
342
90
o
0
15
o
0
;
966
35
o
0
;
819
55
o
0
;
574
75
o
0
;
259
E.9025
Consider
the
four
triangles
shown
below
:
Determine
the
lengths
of
the
following
segments.
Round
your
answers
to
the
nearest
millimeter:
a
[
EF
]
b
[
KJ
]
Hints:
Below
is
part
of
the
trigonometric
table
for
cosine.
¸
o
cos
¸
o
¸
o
cos
¸
o
¸
o
cos
¸
¸
o
cos
¸
o
¸
o
cos
¸
o
0
o
1
20
o
0
;
94
40
o
0
;
766
60
o
0
;
5
80
o
0
;
174
5
o
0
;
996
25
o
0
;
906
45
o
0
;
707
65
o
0
;
423
85
o
0
;
087
10
o
0
;
985
30
o
0
;
866
50
o
0
;
643
70
o
0
;
342
90
o
0
15
o
0
;
966
35
o
0
;
819
55
o
0
;
574
75
o
0
;
259
E.6440
We
consider
the
four
triangles
rep-resented
below
:
Determine
the
measure
of
the
lengths
of
the
following
seg-ments
rounded
to
the
nearest
millimeter:
a
[
AB
]
b
[
GI
]
4.
Use
of
the
cosine:
search
for
the
hypothenuse
E.9027
We
consider
the
four
triangles
rep-resented
below
:
Determine
the
measure
of
the
lengths
of
the
following
seg-ments
rounded
to
the
nearest
millimeter:
a
[
EF
]
b
[
KJ
]
E.9020
At
an
acrobatic
park,
management
wants
to
install
a
new
zip
line.
The
cable
will
be
installed
at
a
height
of
8
m
in
height
and
the
slope
of
the
cable
must
be
10
o
.
Determine
the
length
of
cable,
rounded
to
the
nearest
meter,
needed
to
make
this
tirolienne.
5.
Use
of
the
cosine
E.4918
Consider
the
four
triangles
shown
below
:
Determine
the
lengths
of
the
following
segments,
rounded
to
the
nearest
millimeter:
a
[
AB
]
b
[
JL
]
Hints:
Below
is
part
of
the
trigonometric
table
for
cosine.
¸
o
cos
¸
o
¸
o
cos
¸
o
¸
o
cos
¸
¸
o
cos
¸
o
¸
o
cos
¸
o
0
o
1
20
o
0
;
94
40
o
0
;
766
60
o
0
;
5
80
o
0
;
174
5
o
0
;
996
25
o
0
;
906
45
o
0
;
707
65
o
0
;
423
85
o
0
;
087
10
o
0
;
985
30
o
0
;
866
50
o
0
;
643
70
o
0
;
342
90
o
0
15
o
0
;
966
35
o
0
;
819
55
o
0
;
574
75
o
0
;
259
https://chingmath.fr
chapExoCorrec/9025
sacados/9025
EDF3;5cm75oJLK6;5cm20o
chapExoCorrec/6440
sacados/6440
ABC6cm33oGIH3cm65o
chapExoCorrec/9027
sacados/9027
JLK4;5cm40oEDF1;5cm48o
chapExoCorrec/9020
sacados/9020
10o
chapExoCorrec/4918
sacados/4918
ABC4;5cm20oJKL1;5cm75o
E.9026
Consider
the
four
triangles
shown
below
:
Determine
the
lengths
of
the
following
segments,
rounded
to
the
nearest
millimeter:
a
[
ED
]
c
[
GI
]
Hint:
Below
is
part
of
the
trigonometric
table
for
cosine.
¸
o
cos
¸
o
¸
o
cos
¸
o
¸
o
cos
¸
¸
o
cos
¸
o
¸
o
cos
¸
o
0
o
1
20
o
0
;
94
40
o
0
;
766
60
o
0
;
5
80
o
0
;
174
5
o
0
;
996
25
o
0
;
906
45
o
0
;
707
65
o
0
;
423
85
o
0
;
087
10
o
0
;
985
30
o
0
;
866
50
o
0
;
643
70
o
0
;
342
90
o
0
15
o
0
;
966
35
o
0
;
819
55
o
0
;
574
75
o
0
;
259
E.1156
Consider
the
two
triangles
ABC
and
MNP
shown
below
:
Determine
the
lengths
of
the
following
segments,
rounded
to
the
nearest
millimetre:
a
[
AC
]
b
[
MN
]
6.
Use
of
the
reciprocal
cosine
E.2114
Note:
when
we
look
at
the
cosine
trigonometric
table,
we
see
the
cosine
values
decreasing
from
1
to
0
:
it
never
takes
the
same
value
twice.
Proposition-definition:
in
a
right-angled
triangle,
the
value
:
r
=
longueur
of
the
adjacent
longueur
side
of
the
hypoténuse
of
an
acute
angle
is
uniquely
associated
with
the
measure
¸
of
that
angle.
Note
cos
−
1
(
r
)
the
measure
of
this
angle.
Consider
the
three
right-angled
triangles
below
:
1
a
Carry
out,
on
the
figure
above,
the
measurements
below,
transferring
them
to
the
table
:
AB
AC
BC
DE
DF
EF
GH
GI
HI
b
Give
the
value
of
the
following
quotients
rounded
to
the
nearest
hundredth
:
AC
AB
BC
AB
DF
DE
EF
DE
HI
HG
GI
HG
Indication
:
we
recall
the
extract
from
the
trigonometric
table
below
:
α
cos
¸
α
cos
¸
α
cos
¸
α
cos
¸
α
cos
¸
0
1.000
2
0.999
4
0.998
6
0.995
8
0.990
10
0.985
12
0.978
14
0.970
16
0.961
18
0.951
20
0.940
22
0.927
24
0.914
26
0.899
28
0.883
30
0.866
32
0.848
34
0.829
36
0.809
38
0.788
40
0.766
42
0.743
44
0.719
46
0.695
48
0.669
50
0.643
52
0.616
54
0.588
56
0.559
58
0.530
60
0.500
62
0.469
64
0.438
66
0.407
68
0.375
70
0.342
72
0.309
74
0.276
76
0.242
78
0.208
80
0.174
82
0.139
84
0.105
86
0.070
88
0.035
3
Using
the
trigonometric
table,
give
an
approximate
value
for
each
of
the
following
angles
:
BAC
ABC
FDE
FED
GHI
HGI
https://chingmath.fr
chapExoCorrec/9026
sacados/9026
GHI5cm25oDEF3;5cm35o
chapExoCorrec/1156
sacados/1156
4cm6cm40o20oABCMNP
chapExoCorrec/2114
sacados/2114
ABCDEFGHI
E.4931
Below
is
an
excerpt
from
the
trigonometric
table
of
cosines
with
a
step
size
of
2
o
:
α
cos
¸
α
cos
¸
α
cos
¸
α
cos
¸
α
cos
¸
0
1
;
000
2
0
;
999
4
0
;
998
6
0
;
995
8
0
;
990
10
0
;
985
12
0
;
978
14
0
;
970
16
0
;
961
18
0
;
951
20
0
;
940
22
0
;
927
24
0
;
914
26
0
;
899
28
0
;
883
30
0
;
866
32
0
;
848
34
0
;
829
36
0
;
809
38
0
;
788
40
0
;
766
42
0
;
743
44
0
;
719
46
0
;
695
48
0
;
669
50
0
;
643
52
0
;
616
54
0
;
588
56
0
;
559
58
0
;
530
60
0
;
500
62
0
;
469
64
0
;
438
66
0
;
407
68
0
;
375
70
0
;
342
72
0
;
309
74
0
;
276
76
0
;
242
78
0
;
208
80
0
;
174
82
0
;
139
84
0
;
105
86
0
;
070
88
0
;
035
The
figure
below
shows
four
triangles
with
measurements
marked
on
them
:
Give
the
approximate
value
of
each
angle
to
the
nearest
two
degrees
:
a
BAC
c
HGI
E.9028
The
figure
below
shows
four
trian-gles
;
measurements
are
plotted
on
it:
Determine
the
measure
of
the
following
angles
rounded
to
the
nearest
tenth
of
a
degree
:
a
∠
DEF
b
∠
LJK
7.
Use
of
cosine
and
inverse
cosine
E.9019
Consider
the
figure
below
where
:
points
A
,
B
,
D
and
points
A
,
C
,
E
are
aligned
;
triangles
ABC
and
AED
are
rectangles
at
B
and
E
re-spectively.
1
Determine,
to
the
nearest
tenth
of
a
degree,
the
measure
of
the
angle
∠
BAC
.
2
Use
the
previous
question,
to
determine
the
measure
of
segment
[
CE
]
rounded
to
the
nearest
millimeter.
E.4932
Consider
a
triangle
ABC
right-angled
C
such
that
:
AC
=
4
cm
;
AB
=
7
cm
1
Determine
the
measure
of
the
angle
∠
CAB
rounded
to
the
tenth
degree.
In
the
remainder
of
the
exercise,
the
rounded
value
of
the
angle
∠
CAB
obtained
in
the
previous
question
will
be
used
:
2
In
this
question,
we
will
not
use
the
Pythagorean
theo-rem
:
a
Determine
the
measure
of
the
angle
∠
CBA
rounded
to
the
nearest
tenth
of
a
degree.
b
Derive
the
length
of
side
[
BC
]
rounded
to
the
nearest
millimeter.
https://chingmath.fr
chapExoCorrec/4931
sacados/4931
ABC3.5cm4.5cmGIH3cm4.5cm
chapExoCorrec/9028
sacados/9028
EDF2.5cm3.5cmJLK3cm5.7cm
chapExoCorrec/9019
sacados/9019
ABCDE5cm4;5cm2cm
chapExoCorrec/4932
sacados/4932
ABC7cm4cm
E.4935
Consider
the
figure
below
:
The
straight
lines
(
AC
)
and
(
BD
)
intersect
at
the
point
O
.
1
a
Determine
the
measure
of
the
angle
∠
BAO
rounded
to
the
nearest
tenth
of
a
degree.
b
Derive
the
measure
of
the
angle
∠
COD
.
2
Determine
the
perimeter
of
the
triangle
ODC
rounded
to
the
nearest
millimeter.
E.1157
An
explorer
arrives
in
front
of
the
Cheops
pyramid.
He
places
his
measuring
instruments
(theodolite)
at
point
H
.
Studying
the
pyramid,
he
observes
that
it
is
a
regular
pyramid:
the
foot
C
of
the
height
from
the
vertex
S
is
also
the
center
of
the
base.
It
also
estimates
the
distance
HC
to
550
m
.
From
point
H
to
vertex
S
,
his
measuring
instru-ments
reveal
an
angle
of
15
o
.
Determine
the
measure
of
height
SC
of
the
Pyramid
of
Cheops
rounded
to
the
nearest
metre.
8.
Cosine,
Pythagorean
theorem
and
Thales
theorem
E.9018
Consider
the
triangle
ABC
right-angled
C
shown
below
:
1
Determine
the
measure
of
segment
[
AC
]
.
2
Deduce
the
measure,
to
the
nearest
degree,
of
the
angle
∠
CAB
.
E.5988
Opposite
is
shown
the
right-angled
triangle
BPQ
at
B
such
that
:
PB
=6
cm
;
PQ
=8
cm
The
circle
C
is
the
circum-scribed
circle
of
the
trian-gle
BPQ
.
We
construct
the
circle
C
with
center
P
and
passing
through
point
B
.
We
de-note
A
as
the
point
of
in-tersection
of
circle
C
and
segment
[
PQ
]
.
The
aim
of
the
exercise
is
to
determine
an
approximate
value
for
the
area
of
the
shaded
part.
1
Determine
the
area
of
the
disk
C
rounded
to
the
nearest
tenth
of
cm
2
.
Hint:
we
will
use
:
ı
≈
3.1416
2
a
Determine
the
measure,
rounded
to
the
nearest
tenth
of
a
degree,
of
angle
APB
.
b
Deduce
the
area,
rounded
to
the
nearest
tenth
of
cm
2
,
of
the
angular
sector
of
the
circle
C
defined
by
the
arc
AB
.
3
Deduce
a
measurement,
rounded
to
the
nearest
tenth
of
cm
2
,
of
the
shaded
part.
https://chingmath.fr
chapExoCorrec/4935
sacados/4935
3;5cm2;5cm4cmABCDO
chapExoCorrec/1157
sacados/1157
HCS15o
chapExoCorrec/9018
sacados/9018
ABC13km5km
chapExoCorrec/5988
sacados/5988
CCOPABQ6cm
E.9016
Pour
mountain
running,
some
athletes
measure
their
per-formance
by
the
ascension
velocity
,
noted
V
a
.
V
a
is
the
quotient
of
the
difference
in
elevation
of
the
race,
expressed
in
meters,
by
the
duration,
expressed
in
hours.
Example:
for
a
gradient
of
4
500
m
and
a
run
time
of
3
h
:
V
a
=
1
500
m
=
h
Reminder
:
the
altitude
difference
of
the
race
is
the
differ-ence
between
the
altitude
at
the
finish
and
the
altitude
at
the
start.
A
top-level
runner
wants
to
achieve
an
ascent
speed
of
at
least
1
400
m
=
h
during
his
next
race
The
figure
below
is
not
a
full-scale
representation.
The
route
breaks
down
into
two
stages
(see
figure
2)
:
First
step
of
3
800
m
for
a
horizontal
displacement
of
3
790
m
.
Second
stage
of
4.1
km
with
a
slope
angle
of
approxi-mately
12
o
.
1
Check
that
the
gradient
of
the
first
stage
is
approxi-mately
275.5
m
.
2
How
steep
is
the
second
stage?
(we’ll
round
to
the
near-est
decimeter)
3
From
the
start,
the
runner
takes
48
minutes
to
reach
the
summit.
Does
the
runner
reach
his
goal?
9.
Unclassified
exercises
E.1155
Let
OAB
be
a
right
triangle
at
A
.
Con-sider
points
M
and
N
,
which
lie
on
line
segments
[
OA
]
and
[
OB
]
,
respectively,
such
that
triangle
OMN
is
a
right
triangle
at
M
.
1
Justify
the
following
equality:
ON
×
OA
=
OB
×
OM
.
2
a
Using
your
protractor,
find
the
measure
of
angle
AOB
.
b
Take
measurements,
to
the
nearest
millimeter,
on
the
figure
to
complete
the
table
below
:
Segment
[
OA
]
[
OM
]
[
OB
]
[
ON
]
Length
c
Give
the
values
of
the
ratios,
rounded
to
the
nearest
thousandth
:
OM
ON
;
OA
OB
3
a
What
conjecture
can
be
made
about
the
quotients
OM
ON
and
OA
OB
?
b
Using
question
1
,
,
justify
that
the
two
quotients
OM
ON
and
OA
OB
are
equal.
https://chingmath.fr
chapExoCorrec/9016
sacados/9016
altitude d’arrivéealtitude départdéniveléangledepenteABCFigure 1
SommetdénivelésecondeétapedénivelépremièreétapeDépartDEFGH3800m4100m3790m12oFigure 2
chapExoCorrec/1155
sacados/1155
OABMN