Grade 9
/ Sections, cones and spheres 38 exercises (100% corrected)
- Section of the parallelepiped by a plane parallel to an edge (5 exercices)
- Other sections of the parallelepiped (2 exercices)
- Section of the cylinder (1 exercice)
- Section of a pyramid (2 exercices)
- Section of the sphere (1 exercice)
- Section of a cone of revolution (1 exercice)
- Study of the section of the sphere (4 exercices)
- Volume of the sphere (4 exercices)
- Sphere section and volume (2 exercices)
- Volumes of solids (3 exercices)
- Geographical coordinates on the sphere (4 exercices)
- Geographical coordinates and distance calculation (5 exercices)
ACDABCDPRMNB
ABCDEFGHIJK
ABCDEFGH24cm11;7cm4;4cm
ABCDOOH
E.4205
The
cube
shown
here
is
a
6
cm
edge
cube.
(the
figure
is
not
of
actual
dimensions)
We
consider
:
the
point
M
middle
of
the
edge
[
BB
]
;
the
point
N
middle
of
the
edge
[
CC
]
;
the
point
P
middle
of
the
edge
[
DC
]
;
point
R
middle
of
the
edge
[
AB
]
.
1
What
is
the
nature
of
the
triangle
BRM
?
Construct
this
triangle
to
full
size.
Calculate
the
exact
value
of
RM
.
2
The
cube
is
cut
by
the
plane
passing
through
R
and
par-allel
to
the
edge
[
BC
]
.
The
section
is
the
quadrilateral
RMNP
.
What
is
the
nature
of
the
section
RMNP
?
Construct
RMNP
to
full
size.
Give
its
exact
dimensions.
3
Calculate
the
area
of
the
triangle
RBM
.
Calculate
the
volume
of
the
right
prism
with
base
the
triangle
RBM
and
height
[
BC
]
.
2.
Other
sections
of
the
parallelepiped
E.7980
Consider
the
cube
ABCDEFGH
shown
below
and
the
pyramid
KIJF
with
vertex
F
obtained
by
sectioning
the
cube
where
the
points
I
,
J
,
K
belong
to
the
segments
[
FE
]
,
[
FB
]
,
[
FK
]
respectively:
Give
the
nature
of
each
face
of
the
pyramid
KIJF
.
E.7992
Consider
the
parallelepiped
ABCDEFGH
whose
dimensions
are
shown
in
the
represen-tation
below
:
A
section
of
this
solid
is
made
to
obtain
the
triangle
EGB
.
Determine
the
dimensions
of
the
triangle
BEG
.
3.
Section
of
the
cylinder
E.2946
In
space,
consider
a
cylinder
of
revolution
with
axis
(
OO
)
,
ra-dius
5
cm
,
and
height
3
cm
;
the
section
of
this
cylinder
by
a
plane
parallel
to
the
axis
of
revolution
gives
the
quadrilat-eral
ABCD
;
The
distance
HO
measures
2
cm
.
1
a
Draw
the
triangle
O
BC
to
scale.
https://chingmath.fr
chapExoCorrec/4205
sacados/4205
Amerique du Sud
Novembre 2009
ACDABCDPRMNB
chapExoCorrec/7980
sacados/7980
ABCDEFGHIJK
chapExoCorrec/7992
sacados/7992
ABCDEFGH24cm11;7cm4;4cm
chapExoCorrec/2946
sacados/2946
ABCDOOH
ABCDEFGHS
ABCDEFGIOIH
PQ
Figure 1Figure 2
b
Determine
the
length
BC
,
rounded
to
the
nearest
millimeter.
2
a
Give
the
nature
of
the
quadrilateral
ABCD
.
b
Represent
the
section
ABCD
to
scale.
4.
Section
of
a
pyramid
E.7977
Consider
the
pyramid
ABCDS
with
vertex
S
and
base
rectangular
:
We
cut
this
solid
by
a
plane
(
P
)
parallel
to
the
base.
We
get
the
EFGH
section.
1
What
is
the
nature
of
section
EFGH
?
2
What
is
the
nature
of
the
solid
EFGHS
?
E.7978
Consider
a
pyramid
ABCDO
with
square
base
ABCD
shown
opposite.
Note
I
the
foot
of
the
height
of
the
pyramid
and
E
the
middle
of
[
OA
]
.
We
have
the
dimensions
:
AB
=3
cm
;
IO
=4
cm
The
plane
parallel
to
the
base
passing
through
the
point
E
intercepts
the
pyramid,
forming
the
quadrilateral
EFGH
.
1
What
is
the
nature
of
the
quadrilateral
EFGH
.
2
Justify
that
the
point
F
is
the
midpoint
of
the
segment
[
OB
]
.
3
Draw
the
base
of
pyramid
EFGHO
,
vertex
O
,
full
size.
5.
Section
of
the
sphere
E.5674
Consider
the
sphere
and
the
two
cylinders
shown
below
:
1
What
is
the
nature
of
the
cross-section
of
the
sphere
with
the
(
P
)
plane?
2
What
is
the
nature
of
the
section
of
the
first
cylinder
with
the
plane
(
Q
)
that
is
perpendicular
to
the
cylinder’s
axis
of
revolution?
3
What
is
the
nature
of
the
cross-section
of
the
second
cylinder
with
the
(
R
)
plane
that
is
parallel
to
the
cylin-der’s
axis
of
revolution?
6.
Section
of
a
cone
of
revolution
E.7982
Below,
we
consider
the
two
sections
of
cones
of
revolution
:
https://chingmath.fr
chapExoCorrec/7977
sacados/7977
ABCDEFGHS
chapExoCorrec/7978
sacados/7978
ABCDEFGIOIH
chapExoCorrec/5674
sacados/5674
PQ
chapExoCorrec/7982
sacados/7982
Figure 1Figure 2
AOH
AIOP
ORHM(P
1
In
Figure
1
,
the
section
is
through
a
plane
parallel
to
the
base
of
the
cone
of
revolution.
What
is
the
nature
of
the
section?
2
In
Figure
2
,
the
section
is
made
by
a
plane
perpendicular
to
the
base
of
the
cone
of
revolution
and
passing
through
the
top
of
the
cone.
What
is
the
nature
of
the
section?
7.
Study
of
the
section
of
the
sphere
E.5460
La
figure
below
repre-sents
the
section
of
a
sphere
S
by
a
plane
(
P
)
.
The
resulting
sec-tion
circle
is
C
.
1
What
can
be
said
about
the
points
O
,
H
and
A
shown
in
the
figure
below?
1
What
do
the
lengths
AH
,
OA
and
OH
each
represent?
2
What
is
the
nature
of
the
triangle
OHA
?
E.809
Let
S
be
a
sphere
of
radius
12
m
and
a
plane
P
located
at
a
distance
of
7
m
from
the
center
of
the
sphere.
1
Justify
that
the
lines
(
AI
)
and
(
OI
)
are
perpendicular
to
each
other.
2
Relative
to
the
sphere
and
circle-section,
what
do
each
of
the
lengths
OI
,
IA
and
OA
represent.
3
Determine
the
measure
of
the
radius
of
the
circle-section
to
the
nearest
decimeter.
E.807
Let
S
be
a
sphere
with
center
O
and
radius
7
cm
.
Let
C
be
a
circle
associated
with
the
plane
(
P
)
such
that
O
is
at
a
distance
of
5
cm
from
the
plane
(
P
)
.
Let
H
be
the
center
of
C
and
M
a
point
in
space
such
that
M
∈
C
.
1
Draw
a
diagram
showing
the
sphere
to
scale
as
well
as
the
section
circle.
2
What
can
be
said
about
triangle
OHM
?
3
Draw
triangle
OHM
to
scale.
4
Give
the
exact
value
of
HM
,
then
its
value
rounded
to
the
nearest
millimeter.
E.5458
This
exercise
is
a
multiple-choice
questionnaire
(MCQ)
.
No
justification
is
required.
For
each
question,
three
answers
are
offered,
only
one
answer
is
correct.
No
points
will
be
taken
off
for
incorrect
answers.
For
each
of
the
3
questions,
indicate
on
your
copy
the
question
number
and
copy
the
correct
answer.
To
answer
the
questions,
observe
the
figure
below
:
O
is
the
center
of
the
sphere,
plane
P
intersects
the
sphere
along
a
circle
of
center
H
,
M
is
a
point
of
this
circle,
R
is
the
middle
of
[
OH
]
.
1
The
point
R
ap-partient.
.
.
à
the
sphere
of
cen-ter
O
and
ra-dius
OM
à
the
ball
of
cen-ter
O
and
ra-dius
OM
au
plane
P
2
the
distance
from
point
O
to
plane
P
est.
.
.
OM
OR
OH
3
Si
OM
=11.7
cm
et
HM
=10.8
cm
,
alors
OH
=
:
:
:
4.5
cm
1.2
cm
20.25
cm
8.
Volume
of
the
sphere
https://chingmath.fr
chapExoCorrec/5460
sacados/5460
AOH
chapExoCorrec/809
sacados/809
AIOP
chapExoCorrec/807
sacados/807
chapExoCorrec/5458
sacados/5458
ORHM(P
2cm
RTourdetête
HhAOK
E.9317
Here
are
the
dimensions
of
four
solids
:
A
pyramid
with
a
height
of
6
cm
,
whose
base
is
a
rectan-gle
with
a
length
of
6
cm
and
a
width
of
3
cm
.
A
cylinder
with
a
radius
of
2
cm
and
a
height
of
3
cm
.
A
cone
with
a
radius
of
3
cm
and
a
height
of
3
cm
.
A
sphere
with
a
radius
of
2
cm
.
1
a
Represent
the
first
three
solids
approximately
as
in
the
example
opposite
:
b
Place
the
given
dimensions
on
the
representations
2
Classify
these
four
solids
in
ascend-ing
order
of
volume.
Some
formulas:
4
3
×
ı
×
rayon
3
ı
×
rayon
2
×
hauteur
1
3
×
ı
×
rayon
2
×
hauteur
1
3
×
aire
de
la
base
×
hauteur
Hint:
we
will
use
:
ı
≈
3
;
1416
E.2652
In
a
cubic
box
whose
edge
measures
7
cm
,
we
place
a
7
cm
ball
with
diameter
(see
diagram
opposite)
.
The
volume
of
the
ball
corre-sponds
to
a
certain
percent-age
of
the
volume
of
the
box.
We
call
this
percentage
ˇ
fill-ing
ratio
of
the
boîte
ı.
Calculate
this
filling
rate
of
the
box.
Round
this
percentage
to
the
nearest
integer.
Hint:
we’ll
use
:
ı
≈
3.1416
E.9320
Guillaume
would
like
to
know
how
many
hairs
he
has
on
his
head.
To
do
this,
he
represents
his
head
as
a
sphere
with
ra-dius
R
.
He
measures
the
circumference
of
his
head
as
shown
in
the
diagram
below
and
obtains
56
cm
.
Reminders:
Perimeter
of
a
circle
with
radius
R
:
P
=
2
ıR
Area
of
a
sphere
with
radius
R
:
A
=
4
ıR
2
.
Hint:
we
will
use
:
ı
≈
3
;
1416
1
Show
that
the
radius
of
a
circle
with
perimeter
56
cm
is
approximately
equal
to
9
cm
.
2
Guillaume
estimates
that
his
hair
covers
half
the
surface
area
of
his
head.
On
1
cm
2
of
his
skull,
he
counted
250
hairs.
Estimate
the
number
of
hairs
Guillaume
has.
Hint:
for
this
question,
all
traces
of
research
will
be
taken
into
account
when
grading.
E.4336
1
Draw
a
right
paving
block
in
cavalier
perspective.
2
An
aquarium
has
the
shape
of
a
right
cube
of
length
40
cm
,
width
20
cm
and
height
30
cm
.
a
Calculate
the
volume,
in
cm
3
,
of
this
right
block.
b
Remember
that
a
liter
corresponds
to
1
000
m
3
.
How
many
liters
of
water
can
this
aquarium
hold?
Ano
justification
is
required
.
3
From
the
following
formulae,
copy
the
one
that
gives
the
volume,
in
cm
3
,
of
a
ball
of
30
cm
de
diameter
:
4
3
×
ı
×
30
3
;
4
ı
×
15
2
;
4
3
×
ı
×
15
3
4
A
second
aquarium
contains
a
volume
of
water
equal
to
three-quarters
the
volume
of
a
ball
of
diameter
30
cm
.
Its
contents
are
poured
into
the
first
aquarium.
How
high
does
the
water
rise?
Give
a
value
rounded
to
the
nearest
mil-limetre.
Indication
:
we
will
use
:
ı
≈
3.1416
9.
Sphere
section
and
volume
E.2491
A
spherical
cap
is
a
solid
ob-tained
by
cutting
a
sphere
with
a
plane.
A
liquid
detergent
dispenser,
shown
below,
has
the
shape
of
a
spherical
cap
with
center
O
and
radius
R
=
OA
=4.5
cm
.
https://chingmath.fr
chapExoCorrec/9317
sacados/9317
2cm
chapExoCorrec/2652
sacados/2652
Bordeaux - Juin 2002
chapExoCorrec/9320
sacados/9320
RTourdetête
chapExoCorrec/4336
sacados/4336
chapExoCorrec/2491
sacados/2491
HhAOK
OHRTPartie enfouieSolPartie visible(calotte sphérique)
6cm2cm6cm
The
opening
of
this
container
is
delimited
by
the
circle
with
center
H
and
radius
HA
=2.7
cm
.
The
total
height
of
this
measuring
device
is
HK
.
1
Draw
the
triangle
AHO
to
scale.
2
Calculate
OH
,
giving
your
reasoning,
then
deduce
that
the
total
height
HK
of
the
measuring
cup
is
exactly
8.1
cm
.
3
The
volume
V
of
a
spherical
cap
with
radius
R
and
height
h
is
given
by
the
formula
:
V
=
1
3
·
ı
·
h
2
·
3
·
R
−
h
Calculate
based
on
ı
the
exact
volume
of
the
dispenser
in
cm
3
.
Deduce
the
total
capacity
of
the
dispenser
rounded
to
the
nearest
milliliter.
Note:
we
will
use
:
ı
≈
3.1416
E.5442
To
attract
more
visitors
to
his
city,
a
mayor
decides
to
build
the
Pacific
Aquarium.
The
architects
plan
to
install
a
huge
aquarium
at
the
entrance,
with
spherical
glass.
The
figure
below
shows
the
situation.
This
figure
is
not
to
scale.
Reminder
:
the
formula
for
the
volume
of
a
sphere
with
radius
R
:
V
boule
=
4
×
ı
×
R
3
3
Note:
we
will
use
:
ı
≈
3.1416
1
Calculate
the
volume
of
a
sphere
with
radius
5
m
,
rounded
to
the
nearest
cubic
meter.
2
In
reality,
the
aquarium
is
built
into
the
ground.
The
up-per
part
(visible
to
visitors)
is
a
ˇ
spherical
dome
ı.
The
lower
part
(buried)
houses
the
machinery.
a
What
is
the
geometric
nature
of
the
section
between
the
horizontal
plane
of
the
ground
and
the
aquarium
(the
grayed-out
part
in
the
figure)
?
b
Point
O
designates
the
center
of
the
sphere.
The
fol-lowing
actual
dimensions
are
given
:
OH
=
3
m
;
RO
=
5
m
;
HR
=
4
m
où
H
and
R
are
the
points
located
on
the
floor
as
shown
in
the
figure.
Is
triangle
OHR
a
right
triangle??
Justify
your
an-swer.
3
a
T
is
a
point
on
the
sphere
such
that
points
T
,
O
,
and
H
are
aligned
as
shown
in
the
figure.
Calculate
the
height
HT
of
the
visible
part
of
the
aquarium.
b
Calculate
the
volume
of
this
spherical
cap,
rounded
to
the
nearest
liter.
Hint:
the
volume
of
a
spherical
cap
with
radius
5
m
is
given
by
the
formula
:
V
calotte
=
ı
×
h
2
3
×
(15
−
h
)
où
h
denotes
its
height
(corresponding
to
the
length
HT
in
the
figure.)
c
For
this
question,
we
will
take
the
volume
of
the
aquar-ium
to
be
469
000
liters.
Pumps
deliver
seawater
at
a
constant
rate
to
fill
the
empty
aquarium.
In
2
hours
of
operation,
the
pumps
together
inject
14
000
liters
of
seawater.
After
how
many
hours
of
operation
will
the
pumps
have
filled
the
aquarium??
10.
Volumes
of
solids
E.5925
Reminders:
Volume
of
a
cylinder:
V
=
ı
×
rayon
2
×
hauteur
Volume
of
a
sphere
:
V
=
4
3
×
ı
×
rayon
3
Note:
we
will
use
:
ı
≈
3
;
1416
Flora
makes
bracelets
out
of
modeling
clay.
They
are
all
made
up
of
8
round
beads
and
4
long
beads.
This
modeling
clay
is
sold
in
blocks,
all
of
which
are
shaped
like
rectangular
prisms
with
the
dimensions
specified
opposite.
The
clay
can
be
kneaded
as
de-sired
and
then
hardens
when
baked.
Information
about
the
beads:
https://chingmath.fr
chapExoCorrec/5442
sacados/5442
OHRTPartie enfouieSolPartie visible(calotte sphérique)
chapExoCorrec/5925
sacados/5925
6cm2cm6cm
23cm23cm
ABCDEFGHIKLJOS
A
round
bead
Ball
with
a
diameter
of
8
mm
A
long
bead
Cylinder
with
a
height
of
16
mm
and
a
diameter
of
8
mm
Flora
buys
two
blocks
of
modeling
clay:
a
block
of
blue
mod-eling
clay
to
make
round
beads
and
a
block
of
white
modeling
clay
to
make
long
beads.
How
many
bracelets
can
she
expect
to
make?
E.9319
The
large
crystal
globe
is
a
trophy
awarded
to
the
winner
of
the
Ski
World
Cup.
This
trophy
weighs
9
kg
and
measures
46
cm
in
height.
This
globe
is
considered
to
be
com-posed
of
a
crystal
cylinder
with
a
di-ameter
of
6
cm
and
a
height
of
23
cm
,
topped
with
a
crystal
ball
with
a
di-ameter
of
23
cm
.
See
diagram
oppo-site.
Note:
we
will
use
:
ı
≈
3
;
1416
1
Show
that
the
volume
of
the
ball
of
this
trophy
is
6
371
cm
3
,
rounded
to
the
nearest
cubic
centimeter.
2
Marie
claims
that
the
volume
of
the
crystal
ball
repre-sents
approximately
90
%
of
the
total
volume
of
the
tro-phy.
Is
she
right?
E.4203
Consider
the
following
three
solids
:
the
ball
of
center
O
and
radius
SO
tel
that
SO
=3
cm
;
the
pyramid
SEFGH
of
height
3
cm
whose
base
is
the
square
EFGH
de
side
6
cm
;
le
cube
ABCDEFGH
d
edge
6
cm
.
These
three
solids
are
placed
in
a
container.
This
container
is
represented
by
the
right
block
ABCDIJKL
of
height
15
cm
whose
base
is
the
square
ABCD
de
side
6
cm
.
1
Calculate
the
volume
of
the
cube
ABCDEFGH
en
cm
3
.
2
Calculate
the
volume
of
the
pyramid
SEFGH
en
cm
3
.
3
Determine
the
volume
occupied
by
the
three
solids
inside
the
ABCDIJKL
cube,
rounded
to
the
cm
3
.
4
In
this
question,
write
down
all
calculations
to
justify
your
answer.
Any
trace
of
research,
even
if
incomplete,
will
be
taken
into
account
in
the
assessment.
Can
we
pour
20
c‘
water
into
this
container
without
it
overflowing?
Diagram
:
The
figure
is
not
to
scale.
Some
indications:
The
volume
of
a
pyramid
is
calculated
using
the
for-mula
:
V
=
1
3
×
h
×
B
where
h
is
the
height
of
the
pyramid
and
B
is
the
area
of
its
base.
The
volume
of
a
sphere
is
calculated
using
the
formula
:
V
=
4
3
×
ı
×
r
3
where
r
is
the
radius
of
the
sphere.
1
dm
3
=
1
‘
we
will
use
:
ı
≈
3.1416
11.
Geographical
coordinates
on
the
sphere
E.7001
Below
are
the
meridians
and
paral-lels
of
the
globe
:
https://chingmath.fr
chapExoCorrec/9319
sacados/9319
23cm23cm
chapExoCorrec/4203
sacados/4203
ABCDEFGHIKLJOS
chapExoCorrec/7001
sacados/7001
N-80-60-40-200204060-120-100-40-20020406080ABC
NS0o40oS65oN0o30oW150oE50oEABCD
15o30o45o60o75o90o105o120o135o150o165o180o165o0oNordSud15o30o45o60o75o90o105o120o135o150o165o0oéquateurEstOuest15o30o45o60o75o15o30o45o60o75oPyeongchang
NSABCD
ABSNOGEquateur
Determine
the
geodesic
coordinates
of
points
A
,
B
,
and
C
.
E.2943
On
the
sphere
below
representing
the
earth,
consider
the
points
A
,
B
,
C
,
D
shown
below
:
Read
the
geographic
coordinates
of
these
four
points.
E.9318
French
biathlete
Martin
Four-cade
won
the
sixth
big
crystal
globe
of
his
career
in
2017
Pyeongchang,
South
Korea.
Give
approximately
the
latitude
and
longitude
of
this
location
marked
on
the
map
below
:
E.2944
We
consider
on
the
earth,
four
points
A
,
B
,
C
,
D
where
we
know
the
ge-ographical
coordinates
of
the
points
A
and
B
:
A
:
30
o
S
10
o
W
B
:
55
o
N
130
o
E
Determine
the
geographic
coordinates
of
the
points
C
and
D
.
12.
Geographical
coordinates
and
distance
calculation
E.2653
The
earth
is
assimilated
to
a
sphere
of
radius
6
370
km
.
1
Consider
the
plane
perpendicular
to
the
pole
line
(
NS
)
and
equidistant
from
these
two
poles.
The
intersection
of
this
plane
with
the
earth
is
called
the
equator.
Calculate
the
length
of
the
equator
rounded
to
the
near-est
kilometer.
2
Note
O
the
center
of
the
earth
and
G
a
point
on
the
equator.
Consider
two
points
A
and
B
located
in
Africa
on
the
equator.
These
points
are
arranged
as
shown
in
the
dia-gram
above.
We
know
that
:
GOA
=42
o
;
GOB
=9
o
.
Calculate
the
length
of
the
arc
AB
,
the
portion
of
the
equator
located
in
Africa
rounded
to
the
nearest
kilome-ter.
https://chingmath.fr
N-80-60-40-200204060-120-100-40-20020406080ABC
chapExoCorrec/2943
sacados/2943
NS0o40oS65oN0o30oW150oE50oEABCD
chapExoCorrec/9318
sacados/9318
15o30o45o60o75o90o105o120o135o150o165o180o165o0oNordSud15o30o45o60o75o90o105o120o135o150o165o0oéquateurEstOuest15o30o45o60o75o15o30o45o60o75oPyeongchang
chapExoCorrec/2944
sacados/2944
NSABCD
chapExoCorrec/2653
sacados/2653
Grenoble - Juin 2002
ABSNOGEquateur
PVI49oO
LSOM
KEGCOE
E.2541
The
table
below
shows
three
cities:
their
latitude
and
longitude.
Latitude
Longitude
Douala
4
o
9
o
Cayenne
4
o
−
52
o
Milan
45
o
9
o
Remember
that
the
radius
of
the
Earth
is
approximately
6
370
km
1
a
Determine
the
distance
as
the
crow
flies
between
Douala
and
Milan
(city
in
Italy)
rounded
to
the
near-est
kilometer.
b
Determine
the
distance
as
the
crow
flies
between
Douala
and
Cayenne
(city
in
French
Guiana)
rounded
to
the
nearest
kilometer.
2
The
distance
as
the
crow
flies
from
Cayenne
to
Milan
is
7
470
km
.
Can
this
distance
be
deduced
from
the
data
obtained
in
the
previous
questions?
Note:
Spherical
geometry
is
said
to
be
a
geometry
with
positive
curvature.
Hint:
we
will
use
:
ı
≈
3.1416
E.2954
Vancouver,
Canada,
has
the
following
geographical
coordinates
:
123
o
E
49
o
N
Paris
has
the
following
ge-ographical
coordinates
:
2
o
E
49
o
N
Point
I
is
the
only
point
on
the
equator
such
that
triangle
OIP
is
a
right
tri-angle.
Note:
The
radius
of
the
Earth
is
approximately
6
371
km
.
We
will
use
:
ı
≈
3.1416
1
Justify
that
the
cities
of
Vancouver
and
Paris
are
on
the
same
latitude.
2
a
Determine
the
radius
of
the
circle
defining
the
lati-tude
49
o
N
,
rounded
to
the
nearest
kilometer.
b
Determine
the
length
of
the
latitude
49
o
N
,
rounded
to
the
nearest
kilometer.
c
Deduce
the
length,
on
the
earth’s
surface,
separating
these
two
cities,
rounded
to
the
nearest
kilometer.
3
Give
the
coordinates
of
the
geographical
point
diametri-cally
opposite
the
city
of
Vancouver.
E.2456
The
drawing
below
represents
the
Earth,
which
is
assimilated
to
a
sphere
of
6
370
km
radius.
The
circle
with
center
O
passing
through
M
represents
the
equator.
The
point
L
represents
the
city
of
London.
L
lies
on
the
sphere
and
on
the
circle
with
center
S
(see
figure)
.
We’ll
admit
that
the
angle
LSO
is
a
right
angle.
We
give
OS
=4
880
km
.
1
Calculate
SL
to
the
nearest
kilometer.
2
Calculate
the
measure
of
the
angle
SOL
rounded
to
the
nearest
degree.
3
Deduce
London’s
northern
latitude
from
the
equator
to
the
nearest
degree,
i.e.
the
angle
LOM
.
E.2540
The
Earth
is
considered
to
be
spher-ical;
a
representation
is
given
opposite,
showing
:
The
city
G
of
Greenwich
and
its
meridian
The
city
K
of
Kiev
and
its
meridian
passing
through
this
city.
The
cities
G
and
K
are
on
the
same
parallel.
Reminder
:
the
radius
of
the
Earth
is
approximately
6
370
km
.
Note:
we
will
use
:
ı
≈
3.1416
1
Justify
that
angles
GOE
and
KOE
are
equal
in
length.
2
Determine
the
radius
of
the
circle
section
formed
by
the
Greenwich
parallel,
rounded
to
the
nearest
kilometer,
given
that
the
latitude
of
Greenwich
is
51
o
.
3
Determine
the
distance
between
Greenwich
and
Kiev
,
rounded
to
the
nearest
kilometer,
given
that
the
longi-tude
of
Kiev
is
31
o
W
13.
Share
https://chingmath.fr
chapExoCorrec/2541
sacados/2541
chapExoCorrec/2954
sacados/2954
PVI49oO
chapExoCorrec/2456
sacados/2456
LSOM
chapExoCorrec/2540
sacados/2540
KEGCOE
AOH
OAB
IJKL70oOO
ABCDLOABCDABCDLOABCDEFGH
E.5459
Reminder
:
volume
of
a
sphere
:
V
=
4
×
ı
×
R
3
3
Note:
we
will
use
:
ı
≈
3.1416
1
Calculate
the
volume
of
a
sphere
with
radius
R
=7
cm
,
rounded
to
cm
3
.
2
We
cut
the
sphere
with
center
O
and
radius
OA
=7
cm
with
a
plane,
shown
below.
What
is
the
nature
of
this
section?
3
Calculate
the
exact
value
of
the
radius
HA
of
this
section,
given
that
OH
=4
cm
.
14.
Unclassified
exercises
E.985
The
small
ball
has
a
radius
of
OA
=3
cm
and
a
volume
of
36
ı
while
the
large
one
has
a
volume
of
288
ı
.
1
Determine
the
enlargement
coefficient
from
the
small
ball
to
the
large
ball.
2
Deduce
the
measure
of
the
radius
of
the
large
ball
[
OB
]
.
E.5444
Consider
the
cylinder
of
revolu-tion
shown
opposite,
where
O
and
O
are
the
centers
of
two
faces.
A
plane
parallel
to
the
axis
of
(
OO
)
intersects
the
cylinder:
the
section
forms
the
quadrilateral
IJKL
.
We
have
the
measurements
:
OO
=
6
cm
;
OI
=
4
cm
KO
L
=
70
o
1
What
is
the
nature
of
the
quadrilateral
IJKL
?
2
a
What
is
the
nature
of
triangle
O
KL
?
b
By
noting
H
the
foot
of
the
height
from
O
in
trian-gle
O
KL
,
determine
the
length
of
the
segment
[
KL
]
rounded
to
the
nearest
millimeter.
3
Determine
the
area
of
the
quadrilateral
IJKL
rounded
to
the
nearest
square
centimeter.
E.988
The
unit
of
length
is
the
centimeter,
the
unit
of
area
is
the
square
centimeter,
the
unit
of
volume
is
the
cubic
centimeter.
Consider
the
right
paving
block
ABCDA
B
C
D
.
Note
L
the
point
of
intersection
of
segments
[
AC
]
and
[
BD
]
.
This
pavement
was
excavated
by
removing
the
pyramid
OABCD
of
height
[
OL
]
.
We
have
:
DD
=5
;
DC
=6
;
DA
=7
Part
A
In
this
part,
we
have
:
OL
=4
.
1
Construct
full-scale,
face
ABCD
and
place
point
L
.
2
a
Calculate
BD
(a
value
rounded
to
the
tenth
will
be
given.)
b
Deduct
DL
(we’ll
give
a
value
rounded
to
the
tenth)
3
a
Calculate
the
volume
of
the
right
block
ABCDA
B
C
D
.
b
Calculate
the
volume
of
the
pyramid
OABCD
.
c
Deduce
the
volume
of
the
hollowed-out
paving
stone.
Part
B
In
this
part,
we
pose
OL
=
x
where
x
is
a
number
between
0
and
5.
The
resulting
hollowed-out
paving
stone
is
the
wooden
base
of
a
trophy.
On
this
base,
we
place
a
glass
pyramid
OEFGH
which
is
an
enlargement
of
the
pyramid
OABCD
,
of
ratio
2.
https://chingmath.fr
chapExoCorrec/5459
sacados/5459
AOH
chapExoCorrec/985
sacados/985
OAB
chapExoCorrec/5444
sacados/5444
IJKL70oOO
chapExoCorrec/988
sacados/988
ABCDLOABCDABCDLOABCDEFGH
1
a
Calculate
the
volume
of
the
pyramid
OABCD
as
a
function
of
x
.
b
Show
that
the
volume
of
the
wooden
base
is
:
210
−
14
x
.
2
Show
that
the
volume
of
the
glass
pyramid
OEFGH
is
112
x
3
Calculate
the
value
of
x
for
which
the
volume
of
glass
is
equal
to
2
times
the
volume
of
wood.
Part
C
Consider
the
functions
f
and
g
defined
by:
f
:
x
↦→
210
−
14
x
et
g
:
x
↦→
112
x
When
x
is
between
0
and
5,
the
function
f
represents
varia-tions
in
wood
volume
and
the
function
g
represents
variations
in
glass
volume.
1
Graph
the
functions
f
and
g
for
x
between
0
and
5.
For
the
benchmark,
we’ll
take
:
the
origin
at
the
bottom
left
of
the
sheet
;
on
the
x-axis
2cm
for
1
unit
;
on
the
y-axis
1cm
for
25
units.
the
x-axis
and
y-axis
are
perpendicular
2
a
We
want
the
volume
of
wood
and
the
volume
of
glass
to
be
equal.
Using
the
graph,
give
an
approximate
value
of
x
for
this
to
be
the
case.
(show
the
plot
used
to
answer)
.
b
Find
this
result
by
calculation.
https://chingmath.fr