Grade 9
/ Theorem of Thales 60 exercises (100% corrected)
- Reminders: Thales' theorem (6 exercices)
- Reminders: reciprocal of Thales' theorem (4 exercices)
- Butterfly configuration (3 exercices)
- Problem and theorem of Thales (3 exercices)
- Thales' theorem and equation (8 exercices)
- Theorem of Thales, equations and Pythagorean theorem (3 exercices)
- Reciprocal of Thales' theorem in butterfly configuration (3 exercices)
- Thales' theorem and reciprocal in two butterfly configurations (2 exercices)
- Thales' theorem and reciprocal in a nested and butterfly configuration (5 exercices)
- Thales' theorem and reciprocal in the same configuration (2 exercices)
- Reciprocal, Thales' theorem, and magnitudes (2 exercices)
- Theorem, reciprocal of Thales and Pythagoras (5 exercices)
- Thales' theorem and trigonometry (3 exercices)
- Contraposé of Thales' theorem (2 exercices)
JesaisJ’utiliseJ’endéduisLes points ..., ..., ...sont alignés.Les points ..., ..., ...sont alignés.:::==:::D’après le théorème de Thalès, on a l’égalité desquotients:Chaînonsdéductifs
EFGHI1;532
MGPUA4;5m3;5m5;6m7;2m
JesaisJ’utiliseJ’endéduisLes pointsM,A,Pet les pointsM,U,Gsont alignés dans le même ordre.MAMPMUMGD’aprèslaréciproqueduthéorèmedeThalès:(AU==(PGChaînonsdéductifs
ATNCR3;2cm4;8cm7;5cm5cm
JesaisJ’utiliseJ’endéduisLes points ..., ..., ...et les points ..., ..., ...sont alignés dans le même ordre.::::::::::::D’après la réciproque du théorème de Thalès::::==:::Chaînonsdéductifs
2
Use
the
equality
of
quotients
in
question
2
to
determine
the
length
of
segment
[
TX
]
.
E.9309
In
the
plane,
we
consider
the
config-uration
below
:
The
straight
lines
(
FG
)
and
(
HI
)
are
respectively
parallel
to
each
other.
1
Give
the
length
of
segment
[
EH
]
.
2
Using
Thales’
theorem,
determine
the
length
of
segment
[
EI
]
.
3
Deduce
that
the
length
of
segment
[
GI
]
.
E.10757
Solve
the
following
equations
:
a
x
x
+
1
=
1
3
b
x
+
2
3
x
−
4
=
2
3
c
2
x
x
−
3
=
4
E.10792
1
Consider
the
three
numbers
:
a
=
2
5
;
b
=
2
3
;
c
=
3
Determine
the
solution
to
the
equation
:
a
b
=
x
c
2
Consider
the
three
numbers
:
a
=
4
3
;
b
=
5
2
;
c
=
14
3
Determine
the
solution
to
the
equation
:
x
a
=
b
c
2.
Reminders:
reciprocal
of
Thales’
theorem
E.11451
Commented
example:
Consider
the
triangle
MGP
shown
below
and
the
points
A
and
U
belonging
respectively
to
the
segments
[
MP
]
and
[
MG
]
:
MA
=3
;
5
m
;
MP
=5
;
6
m
;
MU
=4
;
5
m
;
AT
=7
;
2
m
We
have
the
numerical
application
:
MA
MP
=
3
;
5
5
;
6
=
0
;
625
;
MU
MG
=
4
;
5
7
;
2
=
0
;
625
Consider
triangle
ANT
and
the
two
points
R
and
C
belong-ing
respectively
to
segments
[
AN
]
and
[
AT
]
.
We
have
the
measurements
:
AN
=7
;
5
cm
;
AR
=4
;
8
cm
;
AC
=3
;
2
cm
;
AT
=5
cm
1
Prove
that
the
quotients
are
equal:
AR
AN
=
AC
AT
2
Complete
the
deductive
chain
below
:
https://chingmath.fr
JesaisJ’utiliseJ’endéduisLes points ..., ..., ...sont alignés.Les points ..., ..., ...sont alignés.:::==:::D’après le théorème de Thalès, on a l’égalité desquotients:Chaînonsdéductifs
chapExoCorrec/9309
sacados/9309
EFGHI1;532
chapExoCorrec/10757
sacados/10757
chapExoCorrec/10792
sacados/10792
chapExoCorrec/11451
sacados/11451
MGPUA4;5m3;5m5;6m7;2m
JesaisJ’utiliseJ’endéduisLes pointsM,A,Pet les pointsM,U,Gsont alignés dans le même ordre.MAMPMUMGD’aprèslaréciproqueduthéorèmedeThalès:(AU==(PGChaînonsdéductifs
ATNCR3;2cm4;8cm7;5cm5cm
JesaisJ’utiliseJ’endéduisLes points ..., ..., ...et les points ..., ..., ...sont alignés dans le même ordre.::::::::::::D’après la réciproque du théorème de Thalès::::==:::Chaînonsdéductifs
ABCMN0;91;21;5
4cm12cm5cm7;5cmABCDO
KGHJIVWXYZ
ABCMN1;552
ABCOMND
ABCDG
E.3462
We
consider
the
configuration
below
representing
a
Thales
configuration.
Moreover,
we
know
that
:
AN
=3.5
.
Show
that
the
following
lines
(
BC
)
and
(
MN
)
are
parallel.
E.9310
In
the
configuration
below,
A
∈
[
OC
]
and
B
∈
[
OD
]
.
Show
that
the
lines
(
AB
)
and
(
CD
)
are
parallel:
3.
Butterfly
configuration
E.2167
We
have
represented
two
configura-tions
of
Thales
where
(
GH
)
==
(
IJ
)
and
(
XY
)
==
(
V
W
)
.
In
each
case,
list
the
equalities
of
length
ratios
given
by
Thales’
theorem
:
E.3451
In
the
plane,
we
consider
the
config-uration
:
The
straight
lines
(
BC
)
and
(
MN
)
are
respectively
parallel
to
each
other.
Using
Thales’
theorem,
determine
the
length
of
segment
[
AN
]
.
E.660
Consider
the
lines
(
BD
)
and
(
CN
)
intersecting
O
with
A
a
point
of
(
CN
)
and
M
a
point
of
(
BD
)
such
that
:
The
lines
(
BN
)
,
(
AM
)
and
(
CD
)
are
parallel
to
each
other.
1
Give
all
length
ratios
equal
to
:
a
OM
OD
b
OB
OM
2
We
are
given
the
following
measurements
:
NO
=
5
cm
;
OA
=
4
cm
;
OM
=
3
cm
AC
=
2
cm
;
CD
=
3
cm
a
Determine
the
measure
of
segment
[
BO
]
.
b
Determine
the
length
AM
.
Then,
derive
the
length
BN
.
4.
Problem
and
theorem
of
Thales
E.5695
A
folding
stool
was
geometrically
modeled
by
segments
[
CB
]
and
[
AD
]
for
the
metal
frame
and
segment
[
CD
]
for
the
fabric
seat.
We
have
:
CG
=
DG
=30
cm
,
AG
=
BG
=45
cm
and
AB
=
51
cm
.
For
comfort,
the
seat
[
CD
]
is
parallel
to
the
floor
represented
by
the
line
(
AB
)
.
Determine
the
length
CD
of
the
seat.
Hint:
leave
all
traces
of
research
apparent.
Even
if
the
work
is
not
completed,
it
will
be
considered
in
the
scoring.
https://chingmath.fr
chapExoCorrec/3462
sacados/3462
ABCMN0;91;21;5
chapExoCorrec/9310
sacados/9310
4cm12cm5cm7;5cmABCDO
chapExoCorrec/2167
sacados/2167
KGHJIVWXYZ
chapExoCorrec/3451
sacados/3451
ABCMN1;552
chapExoCorrec/660
sacados/660
ABCOMND
chapExoCorrec/5695
sacados/5695
ABCDG
RivièreADRBV20m12m15mLa∏guren’estpasàl’échelle
FBCRGDiamètre75cmhauteurduregard:1;80mhauteurdurebord:1mépaisseur du mur:20cm
ACBNMACBNM5;2cmACBNMACBNM5;2cm3cmACBNMACBNM5;2cmACBNMACBNM5;2cm3cm7cm
AMNBC3;2cm2;1cm7;4cm
E.6282
Indication
:
any
trace
of
response,
even
if
incomplete,
will
be
taken
into
account
in
the
evaluation
Joachim
has
to
cross
a
river
with
a
group
of
friends.
He
wants
to
install
a
rope
so
that
the
insecure
people
can
hold
on.
He
wants
to
know
the
width
of
the
river
at
this
location
(named
D
)
to
determine
if
the
rope
he
has
is
long
enough.
To
do
this,
he
has
located
a
tree
(named
A
)
on
the
other
bank.
He
travels
20
meters
on
the
straight
bank
o
where
he
is
and
finds
a
new
landmark
:
a
rock
(named
R
)
.
Then
he
continues
for
12
meters
and
then
moves
away
from
the
river,
at
right
angles,
until
the
rock
is
aligned
with
the
tree
from
his
vantage
point
(named
B
)
.
To
do
this,
he
travels
15
m
.
He
is
now
satisfied
:
his
30
-meter-long
rope
is
long
enough
for
him
to
install
it
between
the
points
D
and
A
.
Using
the
figure,
confirm
your
decision.
E.5049
A
young
shepherd
stands
at
the
edge
of
a
cylindrical
well
with
a
diameter
of
75
cm
:
he
aligns
his
gaze
with
the
lower
edge
of
the
well
and
the
bottom
of
the
well
to
estimate
its
depth.
The
bottom
of
the
well
and
the
rim
are
horizontal.
The
well
is
vertical.
1
Using
the
diagram
below
(not
to
scale)
,
give
the
lengths
CB
,
FG
,
RB
in
meters.
2
Calculate
the
depth
BG
of
the
well.
3
The
shepherd
notices
that
the
water
level
in
the
well
is
2.60
m
.
The
young
shepherd
needs
1
m
3
of
water
to
water
all
his
sheep.
Will
he
find
enough
in
this
well?
Hint:
we
will
use
:
ı
≈
3.1416
5.
Thales’
theorem
and
equation
E.11446
Solve
the
following
equations
:
a
x
x
+
8
=
2
3
b
x
−
5
x
=
7
8
E.11447
Solve
the
equations
:
a
x
+
8
x
+
12
=
4
5
b
x
−
5
x
+
2
=
4
5
E.1141
1
Solve
the
following
equation
:
(
E
)
:
x
x
+
5.2
=
3
7
2
In
the
figure
at
right.
the
straight
lines
(
MN
)
and
(
BC
)
are
parallel.
Determine
the
measure
of
the
segment
[
AM
]
.
E.1136
In
the
figure
below,
the
lines
(
BC
)
and
(
MN
)
are
parallel.
Determine
the
measure
of
the
segment
[
AC
]
.
https://chingmath.fr
chapExoCorrec/6282
sacados/6282
RivièreADRBV20m12m15mLa∏guren’estpasàl’échelle
chapExoCorrec/5049
sacados/5049
Brevet Pondichery
Avril 2012
Le volume d'un cylindre ne fait pas partie du socle commun
FBCRGDiamètre75cmhauteurduregard:1;80mhauteurdurebord:1mépaisseur du mur:20cm
chapExoCorrec/11446
sacados/11446
chapExoCorrec/11447
sacados/11447
chapExoCorrec/1141
sacados/1141
ACBNMACBNM5;2cmACBNMACBNM5;2cm3cmACBNMACBNM5;2cmACBNMACBNM5;2cm3cm7cm
chapExoCorrec/1136
sacados/1136
AMNBC3;2cm2;1cm7;4cm
ABCDMN5;5cm3;5cm1;5cm
ABCEFx223
6cm9cm4cm1cmABCDJIK
ABCD45m24mIM
E.11454
Let
ABCD
be
a
rectangle
and
M
a
point
belonging
to
the
segment
[
CD
]
.
Let
N
be
the
point
of
intersection
of
the
lines
(
AM
)
and
(
BC
)
.
We
have
the
following
measurements
:
AB
=5
;
5
cm
;
BC
=3
;
5
cm
;
CN
=1
;
5
cm
Let
x
be
the
length
of
the
segment
[
DM
]
.
1
Establish
the
equality:
x
5
;
5
−
x
=
3
;
5
1
;
5
2
Deduce
the
length
DM
.
E.658
The
figure
opposite
was
made
freehand
;
we
have
the
follow-ing
properties
:
the
point
E
belongs
to
the
line
(
AB
)
;
point
F
belongs
to
line
(
AC
)
;
the
straight
lines
(
EF
)
and
(
BC
)
are
parallel.
Determine
the
value
of
ˇ
x
ı.
E.655
Consider
a
parallelogram
ABCD
such
that
:
AD
=
6
cm
;
CD
=
4
cm
;
AC
=
9
cm
Let
J
be
the
point
on
segment
[
AB
]
that
satisfies
:
AJ
=
1
cm
.
The
line
parallel
to
line
(
AD
)
passing
through
point
J
inter-sects
lines
(
AC
)
and
(
CD
)
at
points
I
and
K
,
respectively.
The
figure
below
illustrates
this
situation
:
1
a
Prove
that
lines
(
IJ
)
and
(
BC
)
are
parallel.
b
Find
the
length
of
segment
[
AI
]
.
2
a
Find
the
length
of
segment
[
KC
]
.
b
Use
this
to
find
the
length
of
segment
[
IJ
]
.
Let
x
denote
the
length
of
segment
[
IJ
]
.
E.10842
1
Solve
the
equation
:
x
51
−
x
=
1
2
2
Consider
a
rectangular
park
with
dimensions
45
m
×
24
m
where
two
paths
intersect
(represented
by
paths
[
BD
]
and
[
IC
]
)
:
a
Establish
that
the
path
represented
by
segment
[
BD
]
measures
51
m
.
b
The
two
paths
intersect
at
point
M
.
Determine
the
distance
DM
.
6.
Theorem
of
Thales,
equations
and
Pythagorean
theorem
E.1139
1
a
Draw
a
rectangle
ABCD
such
that
:
AB
=
1.5
cm
;
AD
=
6
cm
b
Place
the
point
I
belonging
to
[
BC
]
such
that
:
BI
=
1
3
BC
.
c
Name
M
the
point
of
intersection
of
the
lines
(
AI
)
and
(
CD
)
.
2
Determine
the
length
of
segment
[
MC
]
.
3
Determine
the
length
of
segment
[
AM
]
.
https://chingmath.fr
chapExoCorrec/11454
sacados/11454
ABCDMN5;5cm3;5cm1;5cm
chapExoCorrec/658
sacados/658
ABCEFx223
chapExoCorrec/655
sacados/655
6cm9cm4cm1cmABCDJIK
chapExoCorrec/10842
sacados/10842
ABCD45m24mIM
chapExoCorrec/1139
sacados/1139
ABCDE600m270m450m
4m4;8m5m6mABCDO
34;5710;5MNBCA
PQZFG5;533;31;8
E.11500
A
farmer
wants
to
cultivate
a
field
represented
by
the
triangle
ABC
shown
opposite.
The
figure,
which
is
not
to
scale,
provides
the
following
informa-tion
:
triangle
ABC
is
a
right
tri-angle
at
B
;
triangle
CDE
is
a
right
triangle
at
D
;
points
C
,
E
,
and
A
are
collinear;
points
C
,
D
,
and
B
are
collinear;
AB
=600
m
;
BC
=450
m
;
CD
=270
m
1
Show
that
the
segment
[
AC
]
measures
750
meters.
2
a
Show
that
the
lines
(
ED
)
and
(
AB
)
are
parallel.
b
Show
that
segment
[
DE
]
measures
360
meters.
3
Show
that
the
area
of
triangle
CDE
is
48
600
m
2
.
E.5780
On
a
full
moon
night,
Romeo
wishes
to
visit
Juliet.
He
has
a
ladder
of
10
m
in
length.
The
windowsill
is
at
a
height
4.8
m
but
there
is
a
wall
be-tween
it
and
the
house
:
this
wall
is
50
cm
thick,
4
m
high.
The
driveway
separating
the
wall
from
the
house
has
a
width
of
1
m
Will
Romeo
manage
to
put
the
end
of
the
ladder
on
Juliet’s
windowsill?
7.
Reciprocal
of
Thales’
theorem
in
butterfly
configuration
E.666
For
the
configuration
below,
show
that
the
straight
lines
(
AB
)
and
(
CD
)
are
parallel:
E.653
Show
that
the
lines
(
BC
)
and
(
MN
)
are
parallel:
E.9311
Consider
the
configura-tion
below
representing
Thales
configurations.
Show
that
the
straight
lines
(
FG
)
and
(
PQ
)
are
parallel.
8.
Thales’
theorem
and
reciprocal
in
two
butterfly
configurations
https://chingmath.fr
chapExoCorrec/11500
sacados/11500
ABCDE600m270m450m
chapExoCorrec/5780
sacados/5780
chapExoCorrec/666
sacados/666
4m4;8m5m6mABCDO
chapExoCorrec/653
sacados/653
34;5710;5MNBCA
chapExoCorrec/9311
sacados/9311
PQZFG5;533;31;8
AFGEDCB
ABCMNPR
ABCDOFE2;5cm3cm5cm2;4cm4cm
ABCGF
E.671
The
unit
of
length
is
the
cen-timeter
In
the
figure
opposite,
which
is
not
full-scale,
the
straight
lines
(
BC
)
and
(
GF
)
are
parallel.
We
know
that
:
AB
=
3
;
CE
=
2.4
;
AC
=
4
;
BD
=
1.8
BC
=
4.5
;
AF
=
3.6
1
Calculate
length
GF
.
2
Are
the
straight
lines
(
BC
)
and
(
ED
)
parallel?
Justify.
E.659
For
each
of
the
two
questions
in
this
exercise,
specify
the
course
property
used
The
figure
to
the
right
is
not
shown
at
full
size.
The
straight
lines
(
BC
)
and
(
MN
)
are
parallel.
The
following
lengths
are
given
:
AB
=2.4
cm
;
AC
=5.2
cm
;
AN
=7.8
cm
;
MN
=4.5
cm
1
Calculate
the
lengths
AM
and
BC
.
2
Knowing
that
AP
=2.6
cm
and
AR
=1.2
cm
,
show
that
the
lines
(
PR
)
and
(
BC
)
are
parallel.
9.
Thales’
theorem
and
reciprocal
in
a
nested
and
butterfly
configuration
E.670
In
the
figure
opposite,
the
straight
lines
(
AC
)
and
(
DB
)
are
parallel.
1
Calculate
the
length
AO
.
2
Are
the
straight
lines
(
EF
)
and
(
OD
)
parallel?
Justify
your
assertion.
E.5184
Hint:
the
figure
below
is
not
full-scale,
it
is
not
to
be
re-produced.
The
points
A
,
C
and
F
are
aligned,
as
are
the
points
B
,
C
and
G
.
The
straight
lines
(
AB
)
and
(
GF
)
are
parallel.
The
following
measurements
are
given
:
AB
=
3
cm
;
FC
=
8.4
cm
;
FG
=
11.2
cm
1
Calculate
the
length
CA
.
2
Let
D
be
the
point
on
segment
[
CF
]
and
E
be
the
point
on
segment
[
GF
]
such
that
:
FD
=
6.3
cm
;
FE
=
8.4
cm
Show
that
the
straight
lines
(
GC
)
and
(
ED
)
are
parallel.
https://chingmath.fr
chapExoCorrec/671
sacados/671
Groupe Nord - Septembre 2002 - 4 points
AFGEDCB
chapExoCorrec/659
sacados/659
Groupe Sud - Juin 2003 - 5 points
ABCMNPR
chapExoCorrec/670
sacados/670
ABCDOFE2;5cm3cm5cm2;4cm4cm
chapExoCorrec/5184
sacados/5184
ABCGF
ABCDEFG
ABCDEF
ABCDEO
OABMN
E.661
The
unit
is
centimetres.
In
the
figure
below,
the
straight
lines
(
AB
)
and
(
CD
)
are
parallel.
The
straight
lines
(
AD
)
and
(
BC
)
intersect
at
E
.
We
give
:
DE
=6
,
AE
=10
,
AB
=20
and
BE
=16
.
Figures
are
not
full-scale.
They
are
not
to
be
reproduced.
1
Calculate
distance
CD
.
2
The
points
F
and
G
belong
to
the
segments
[
BC
]
and
[
AB
]
respectively.
They
verify:
BF
=
12.8
;
BG
=
16
.
Show
that
the
straight
lines
(
FG
)
and
(
AE
)
are
parallel.
E.3461
The
following
figure
is
not
a
full-scale
figure.
The
unit
of
length
is
centimeters
;
we
give
:
AB
=
8
;
BC
=
9
;
AC
=
6
;
AE
=
4
1
The
lines
(
DE
)
and
(
BC
)
are
parallel.
Compute
AD
.
Its
exact
value
will
be
given,
and
then
its
value
rounded
to
the
tenth
of
a
centimeter.
2
Let
F
be
the
point
such
that
C
,
B
,
and
F
are
aligned
in
that
order,
with
BF
=6
.
Show
that
the
lines
(
EF
)
and
(
AB
)
are
parallel.
E.664
1
a
Draw
a
triangle
ABC
such
that
:
AC
=
7.5
cm
;
BC
=
10
cm
;
AB
=
6
cm
.
b
Place
E
on
[
AC
]
such
that
AE
=
4.5
cm
and
F
on
[
BC
]
such
that
BF
=
6
cm
.
2
Are
the
straight
lines
(
AB
)
and
(
EF
)
parallel?
Justify.
3
We
draw
the
line
parallel
to
(
AB
)
passing
through
C
.
This
line
intersects
(
BE
)
at
L
.
Determine
CL
.
10.
Thales’
theorem
and
reciprocal
in
the
same
configuration
E.673
The
figure
below
shows
a
dia-gram
of
an
ironing
board.
The
segment
[
AB
]
and
[
EC
]
represent
the
legs.
The
straight
lines
(
AB
)
and
(
EC
)
intersect
at
O
.
We
give
:
AD
=
125
cm
;
AC
=
100
cm
;
OA
=
60
cm
OB
=
72
cm
;
OE
=
60
cm
;
OC
=
50
cm
1
Show
that
the
line
(
AC
)
is
parallel
to
the
line
(
EB
)
.
2
Calculate
the
distance
EB
in
cm
.
E.9312
The
structure
of
a
stool
is
shown
op-posite.
The
straight
line
(
AB
)
represents
the
floor,
the
segments
[
AM
]
and
[
BN
]
represent
the
legs
and
the
seg-ment
[
MN
]
represents
the
seat
of
the
stool.
The
stool’s
legs
are
connected
to
the
point
O
.
The
following
measurements
in
cen-timeters
are
given
:
OA
=80
;
OM
=50
;
BN
=143
;
ON
=55
;
AB
=72
Determine
the
length
of
the
stool
seat.
Indication
:
it
will
be
indicated
beforehand
that
the
seat
of
the
stool
is
parallel
to
the
ground
11.
Reciprocal,
Thales’
theorem,
and
magnitudes
https://chingmath.fr
chapExoCorrec/661
sacados/661
Groupe Est - Juin 2003 - 3 points
ABCDEFG
chapExoCorrec/3461
sacados/3461
ABCDEF
chapExoCorrec/664
sacados/664
Groupe Sud - Juin 2003 - 4 points
chapExoCorrec/673
sacados/673
Groupe Nord - Juin 2004 - 4 points
ABCDEO
chapExoCorrec/9312
sacados/9312
OABMN
ABCDEFG7km1;5km2km5km3;5km
ABCDE
ABCDE
E.10840
Michel
is
taking
part
in
a
mountain
bike
rally
on
a
signposted
route.
The
route
is
shown
in
solid
lines.
The
drawing
is
not
to
scale.
Points
A
,
B
and
C
are
aligned.
The
points
C
,
D
and
E
are
aligned.
The
points
B
,
D
and
F
are
aligned.
The
points
E
,
F
and
G
are
aligned.
The
triangle
BCD
is
right-angled
at
C
.
The
triangle
DEF
is
right-angled
at
E
.
1
Show
that
the
length
BD
is
equal
to
2.5
km
.
2
Justify
that
the
straight
lines
(
BC
)
and
(
EF
)
are
paral-lel.
3
Calculate
the
length
DF
.
4
Calculate
the
total
length
of
the
course.
5
Michel
drives
at
an
average
speed
of
16
km
=
h
to
get
from
point
A
to
point
B
.
How
long
will
it
take
to
go
from
point
A
to
point
B
.
Give
your
answer
in
minutes
and
seconds.
E.10839
La
régate
AB
=
400
;
AC
=
300
;
BC
=
500
;
CD
=
700
the
straight
lines
(
AE
)
and
(
BD
)
intersect
at
C
.
The
straight
lines
(
AB
)
and
(
DE
)
are
parallel.
1
Calculate
length
DE
.
2
Show
that
the
triangle
ABC
is
right-angled.
3
Calculate
the
measure
of
the
angle
ABC
.
Round
to
the
nearest
degree.
In
a
race,
competitors
must
complete
several
laps
of
the
course
shown
above.
They
start
from
point
A
,
then
pass
through
points
B
,
C
,
D
and
E
in
that
order
then
back
through
point
C
and
then
back
to
point
A
.
Maltéo,
the
winner,
took
1
h
48
min
to
complete
all
5
of
the
course.
The
distance
traveled
to
complete
one
lap
is
2
880
m
.
4
Calculate
the
total
distance
traveled
to
complete
the
5
laps
of
the
course.
5
Calculate
Maltéo’s
average
speed.
Round
to
the
nearest
whole
number.
12.
Theorem,
reciprocal
of
Thales
and
Pythagoras
E.650
The
figure
below
is
not
full-scale.
It
is
not
required
to
be
reproduced.
The
points
A
,
C
and
E
are
aligned,
as
are
the
points
B
,
C
and
D
.
The
triangle
ABC
is
rectangular
in
B
.
The
following
lengths
are
expressed
in
centimetres
:
BC
=
12
;
CD
=
9.6
;
DE
=
4
;
CE
=
10.4
1
Show
that
the
triangle
CDE
is
rectangular
at
D
.
2
Deduce
that
the
straight
lines
(
AB
)
and
(
DE
)
are
paral-lel.
3
Calculate
the
length
AB
.
E.2680
Consider
a
triangle
EFG
such
that
:
EF
=
6
cm
;
FG
=
7.5
cm
;
GE
=
4.5
cm
.
1
Construct
the
triangle
EFG
.
2
Show
that
the
triangle
EFG
is
right-angled
and
specify
at
which
point.
3
Construct
the
point
M
middle
of
[
EF
]
and
construct
the
line
parallel
to
[
EG
]
passing
through
M
;
it
intersects
[
FG
]
at
N
.
4
Show
that
N
is
the
middle
of
[
FG
]
.
https://chingmath.fr
chapExoCorrec/10840
sacados/10840
ABCDEFG7km1;5km2km5km3;5km
chapExoCorrec/10839
sacados/10839
ABCDE
chapExoCorrec/650
sacados/650
Nantes - Juin 2006
ABCDE
chapExoCorrec/2680
sacados/2680
MNORS
A(Départ)BCDE(Départ)400m300m1000m
ABCDIJMN17cm16cm
ABCMN
E.2168
the
figure
opposite
is
not
full-scale
;
we
don’t
ask
you
to
reproduce
it.
The
points
N
,
O
,
R
on
the
one
hand
and
the
points
M
,
O
,
S
on
the
other
are
aligned
in
this
order.
OS
=
6
cm
;
OM
=
9
cm
;
ON
=
5.4
cm
;
OR
=
3.6
cm
1
Are
the
straight
lines
(
MN
)
and
(
RS
)
parallel?
Justify.
2
Assume
SR
=4.8
cm
.
Is
the
triangle
ORS
right-angled?
Justify.
3
Using
Thales’
theorem
,
calculate
MN
.
4
It
will
be
assumed
that
the
straight
lines
(
MN
)
and
(
NR
)
are
perpendicular.
What
is
the
area
of
the
quadrilateral
MNSR
?
Justify.
E.5047
Students
participate
in
a
foot
race.
Before
the
event,
they
were
given
a
map.
It
is
repre-sented
by
the
figure
below
:
It
is
agreed
that
:
The
straight
lines
(
AE
)
and
(
BD
)
intersect
at
C
.
The
straight
lines
(
AB
)
and
(
DE
)
are
parallel.
ABC
is
a
right
triangle
in
A
.
Calculate
the
actual
length
of
the
path
ABCDE
If
the
work
is
not
completed,
still
leave
a
record
of
the
search.
It
will
be
considered
in
the
scoring.
E.10841
Consider
the
rectangle
ABCD
shown
below
with
:
AB
=
17
cm
;
AD
=
16
cm
Let
I
and
J
be
the
respective
middles
of
segments
[
AD
]
and
[
BC
]
.
We
place
the
point
M
on
the
segment
[
IJ
]
so
that
the
triangle
AMB
is
isosceles
at
A
.
Finally,
we
note
N
the
point
of
intersection
of
the
straight
lines
(
AM
)
and
(
BC
)
.
Determine
the
measure
of
segment
[
AN
]
.
13.
Thales’
theorem
and
trigonometry
E.10764
Consider
the
right
triangle
ABC
at
C
shown
below
and
the
points
M
and
N
belonging
respec-tively
to
the
segments
[
BC
]
and
[
BA
]
:
We
have
the
following
measurements
:
https://chingmath.fr
chapExoCorrec/2168
sacados/2168
MNORS
chapExoCorrec/5047
sacados/5047
Brevet Metropole
Juin 2012
A(Départ)BCDE(Départ)400m300m1000m
chapExoCorrec/10841
sacados/10841
ABCDIJMN17cm16cm
chapExoCorrec/10764
sacados/10764
ABCMN
ABCMN
520m200m120m600mDKJAL
133209200314OZSHX
AMNUVCB
BM
=2.4
cm
;
MC
=1.2
cm
;
AC
=1.5
cm
BN
=2.6
cm
;
BA
=3.9
cm
1
Prove
that
triangle
BMN
is
a
right
triangle
at
M
.
2
a
Determine
the
length
of
segment
[
MN
]
.
b
Determine
the
measure
of
angle
MNB
rounded
to
the
nearest
degree.
E.10791
Consider
the
five
points
A
,
B
,
C
,
M
,
N
such
that
the
point
B
is
the
intersection
of
the
straight
lines
(
AN
)
and
(
CM
)
:
We
have
the
following
measurements
:
BA
=4
cm
;
BC
=3.2
cm
;
AC
=2.4
cm
BM
=2
cm
;
BN
=2.5
cm
1
Demonstrate
that
the
triangle
BMN
is
rectangular
at
M
.
2
a
Determine
the
length
of
the
segment
[
MN
]
.
b
Determine
the
measure
of
the
angle
MNB
rounded
to
the
nearest
degree.
E.10835
The
following
figure,
which
is
not
to
scale,
shows
the
route
Oscar
must
take.
In
the
right-angled
triangle
DLA
at
L
,
point
J
belongs
to
segment
[
DA
]
and
point
K
belongs
to
segment
[
DL
]
.
Given
:
DL
=600
cm
;
KJ
=200
m
;
DJ
=520
m
;
KL
=120
m
1
Show
that
the
length
DK
is
equal
to
480
m
.
2
Justify
that
triangle
DKJ
is
a
right
triangle
at
K
.
3
Show
that
segment
[
DA
]
measures
650
m
.
4
Calculate
the
length
of
path
DKJA
,
marked
with
arrows
in
the
figure.
5
A
photographer
places
a
camera
at
point
D
.
In
order
to
film
the
entire
race
without
moving
the
camera,
angle
LDA
must
be
less
than
25
o
.
Is
this
the
case?
14.
Contraposé
of
Thales’
theorem
E.667
Show
that
the
straight
lines
(
OZ
)
and
(
HS
)
are
not
parallel:
E.657
A
carpenter
has
just
created
the
following
cabinet.
The
[
CB
]
board
rests
directly
on
the
floor.
He
noted
the
following
dimensions
:
AC
=
2
m
;
AB
=
2.5
m
;
AM
=
0.4
m
CU
=
0.8
m
;
AN
=
0.6
m
;
V
B
=
1
m
1
Is
the
MN
board
in
the
horizontal
position?
2
Same
question
for
board
UV
.
15.
Unclassified
exercises
E.5441
https://chingmath.fr
chapExoCorrec/10791
sacados/10791
ABCMN
chapExoCorrec/10835
sacados/10835
Juillet 2024
Martinique
520m200m120m600mDKJAL
chapExoCorrec/667
sacados/667
133209200314OZSHX
chapExoCorrec/657
sacados/657
AMNUVCB
chapExoCorrec/5441
sacados/5441
ABCDEFSH
ABCEJHM
BFHJK4;2m7;5m9;3m12;4m10m
On
wants
to
make
a
teepee
that
will
have
the
shape
of
a
pyramid
having
as
its
base
a
rectangle
ABCD
of
center
H
and
as
its
height
[
SH
]
(see
diagram
oppo-site)
.
The
tipi
will
have
the
following
dimensions
:
AD
=
1.60
m
CD
=
1.20
m
SH
=
2.40
m
1
Calculate
the
volume
V
of
this
pyramid,
in
m
3
.
Recall
that
V
=
1
3
×
B
×
h
où
h
denotes
the
height
and
B
the
area
of
the
base.
2
Calculate
the
length
BD
.
3
The
tepee’s
frame,
consisting
of
the
rectangular
ABCD
frame
and
the
four
side
edges
coming
from
S
,
is
made
of
bamboo
rods.
No
written
demonstration
is
expected
in
this
question.
Quoting
a
property
and
clearly
presenting
a
calculation
will
suffice.
a
Show
that
:
SD
=2.60
m
b
A
rod
[
EF
]
is
added
to
the
frame
as
shown
in
the
draw-ing
so
that
(
EF
)
==
(
AD
)
and
SF
=1.95
m
.
Calculate
EF
.
4
We
found
3
m
bamboo
stalks
in
a
store.
A
rod
can
be
cut
to
make
two
chopsticks,
but
a
chopstick
cannot
be
made
by
gluing
together
two
pieces
of
bamboo.
How
many
bamboo
rods
do
you
need
to
buy,
minimum,
to
make
the
nine
chopsticks
for
the
teepee
frame?
E.663
Consider
the
triangle
ABC
below,
such
that
:
AB
=
6
cm
;
AC
=
10
cm
;
BC
=
8
cm
Let
E
be
the
point
of
[
AC
]
such
that
AE
=4
cm
and
J
be
the
point
of
[
BC
]
such
that
CJ
=2.4
cm
.
Let
H
be
the
midpoint
of
[
EC
]
and
M
the
point
of
intersection
of
the
lines
(
BE
)
and
(
JH
)
.
(in
the
figure
the
dimensions
are
not
respected)
1
Prove
that
the
straight
lines
(
JH
)
and
(
AB
)
are
parallel.
2
Derive
the
calculation
of
the
length
HM
.
E.10837
In
the
configuration
below,
the
points
F
,
B
,
J
and
the
points
H
,
B
,
K
are
aligned
:
Establish
that
the
straight
lines
(
HF
)
and
(
KJ
)
are
parallel.
E.10838
A
tourist
climbs
to
the
top
of
the
Arc
de
Triomphe
in
Paris
:
Stepping
back
2
m
from
the
edge
of
the
Arc
de
Triomphe,
he
realizes
that
he
has
aligned
his
vision
perfectly
with
the
edge
of
the
monument
and
the
foot
of
a
lamppost
standing
at
the
same
level
as
the
monument.
These
eyes
are
estimated
to
be
at
a
height
of
1
m
70
from
the
ground.
Once
back
down,
he
measures
that
the
distance
between
the
edge
of
the
monument
and
the
edge
of
the
lamp
post
is
58.2
m
.
Determine
the
height
of
the
monument,
rounded
to
the
near-est
decimeter.
Indication
:
all
traces
of
research
and
writing
will
be
taken
into
account
during
assessment.
https://chingmath.fr
ABCDEFSH
chapExoCorrec/663
sacados/663
ABCEJHM
chapExoCorrec/10837
sacados/10837
BFHJK4;2m7;5m9;3m12;4m10m
chapExoCorrec/10838
sacados/10838
OABDEFC
ABCDE
ABCDE
E.10973
In
the
figure
below,
we
have
:
C
is
a
circle
of
center
O
and
radius
4.5
cm
;
[
AB
]
is
a
diameter
of
this
circle
and
D
is
a
point
of
the
circle;
The
points
B
,
E
,
A
are
aligned,
as
are
the
points
D
,
F
,
A
;
the
straight
lines
(
BD
)
and
(
EF
)
are
parallel;
BD
=
5.4
cm
;
DA
=
7.2
cm
;
AE
=
2.7
cm
1
Justify
that
the
diameter
[
AB
]
measures
9
cm
.
2
Demonstrate
that
the
triangle
ABD
is
right-angled
at
D
.
3
Calculate
AF
.
4
a
Justify
that
the
area
of
the
triangle
ABD
is
equal
to
19.44
cm
2
.
b
Calculate
the
area
of
the
disk,
rounded
to
the
hun-dredth.
Hint:
we’ll
use
:
ı
≈
3.1416
5
What
percentage
of
the
area
of
the
disc
represents
the
area
of
the
triangle
ABD
?
E.11546
A
city’s
botanical
garden
can
be
represented
by
the
quadrilateral
ABCD
below
:
We
know
that
:
AB
=
500
m
;
BE
=
250
m
;
DE
=
750
m
segments
[
AC
]
and
[
BD
]
intersect
at
point
E
.
The
figure
opposite
is
not
to
scale
.
1
What
is
the
length
of
segment
[
BD
]
?
2
Using
the
right
triangle
ABD
,
show
that
the
length
of
segment
[
AD
]
,
rounded
to
the
nearest
meter,
is
approxi-mately
equal
to
866
m
.
3
a
Calculate
the
sine
of
angle
EAB
.
b
Deduce
the
measure
in
degrees
of
angle
EAB
.
4
a
Show
that
lines
(
AB
)
and
(
DC
)
are
parallel.
b
Show
that
the
length
of
segment
[
CD
]
is
equal
to
1
500
m
.
5
A
pedestrian
walks
around
the
botanical
garden
at
an
average
speed
of
1
;
1
m
=
s
.
He
reads
on
his
map
that
the
length
of
segment
[
BC
]
is
approximately
equal
to
1
323
m
.
Does
it
take
the
pedestrian
less
than
an
hour
to
walk
around
the
botanical
garden?
E.11547
Consider
the
triangle
ACE
below,
where
points
B
and
D
belong
to
segments
[
AC
]
and
[
CE
]
,
respectively.
The
measurements
are
given
:
AB
=
9
m
;
BC
=
6
m
;
AE
=
8
m
;
CE
=
17
m
1
Justify
that
triangle
ACE
is
a
right
triangle
at
A
.
2
Justify
that
lines
(
AE
)
and
(
BD
)
are
parallel.
3
Determine
the
length
of
segment
[
CD
]
.
https://chingmath.fr
chapExoCorrec/10973
sacados/10973
Metropole
2024
OABDEFC
chapExoCorrec/11546
sacados/11546
ABCDE
chapExoCorrec/11547
sacados/11547
ABCDE
ABC2;5m2m1;5m
ABCIJ(AB==(IJ
ABCO(d1(d2
ABCI
ABCOOcentre du cercle
ABC
EFG
AEFRT
E.1031
In
each
of
the
figures
below,
new
prop-erties
can
be
obtained.
In
each
case,
which
theorem
can
be
used
to
assert
the
existence
of
these
new
properties?
a
b
c
d
e
E.652
1
Consider
the
two
half-lines
[
AC
)
and
[
AB
)
.
The
points
represented
on
the
half-right
[
AC
)
are
equally
distributed
on
it.
a
Name
N
one
of
the
points
represented
on
the
half-line
[
AC
)
.
b
Draw
the
parallel
to
the
line
(
BC
)
passing
through
N
.
Name
M
the
point
of
intersection
of
this
parallel
with
the
half-line
[
AB
)
.
c
Replace
the
greyed-out
ˇı
values,
present
in
the
table
below,
by
the
measurement
of
the
associated
segment
:
[
AB
]
[
AC
]
[
BC
]
[
AM
]
[
AN
]
[
MN
]
d
What
can
we
say
about
the
previous
table?
e
Check
whether
the
equality
below
is
verified
or
not
:
AM
AB
=
AN
AC
=
MN
BC
2
Consider
the
triangle
EFG
below
and
wish
to
construct
a
ˇ
agrandissement
ı
and
verify
some
properties
of
these
two
triangles
:
a
Place
the
point
P
on
the
half-right
[
EF
)
and
the
point
Q
on
the
half-right
[
EG
)
such
that
:
EP
=
2.5
×
EF
;
EQ
=
2.5
×
EG
.
b
What
can
be
said
about
the
straight
lines
(
FG
)
and
(
PQ
)
?
c
Compare
the
measurements
of
[
FG
]
and
[
PQ
]
.
E.8934
Consider
the
figure
opposite,
made
freehand
and
not
to
scale.
The
following
information
is
given
:
The
straight
lines
(
ER
)
and
(
FT
)
intersect
at
A
.
AE
=8
cm
,
AF
=10
cm
,
EF
=6
cm
AR
=12
cm
,
AT
=14
cm
1
Show
that
the
triangle
AEF
is
right-angled
E
.
2
Are
the
lines
(
EF
)
and
(
RT
)
parallel?
https://chingmath.fr
chapExoCorrec/1031
sacados/1031
ABC2;5m2m1;5m
ABCIJ(AB==(IJ
ABCO(d1(d2
ABCI
ABCOOcentre du cercle
chapExoCorrec/652
sacados/652
ABC
EFG
chapExoCorrec/8934
sacados/8934
AEFRT